Write a mathematical expression for the output Z. Also develop the truth table. A
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- Design a combinational circuit with the four inputs A,B.C, and D, and three outputs X, Y, and Z. When the binary input is odd number, the binary output is one lesser than the input. When the binary input is even number the binary output is one greate than the input. Implement the function using multiplexers with minimal input and select line.Write, and test using spim, an assembly language program that inputs apositive integer N from the user, followed by N integers. Your program should outputhow many of the N integers have a value greater than 496 but less than or equal to 8128.Your task is to implement a Full Adder(a) Using TWO 8:1 Multiplexers (ONE for Sum output and ONE for Cout output). Assign (or Connect) X, Y,and Cin variables to the Select Inputs of Multiplexers and connect 1 or 0 to each Data Input.
- Which of the following is true about quantization? a. Actual quantization error is the same all throughout the process.b. The signal to noise ratio is the same all throughout the quantization process.c. The smaller the resolution the less quantization error is introducedd. All of the choicesUSE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W XY Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'C
- Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A B C D) respectively with A is the MSB, the output variables are organized as (W XY Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. W=A+BD+BC' W=A+BD+BC, W=A'+BD+BC W= BC'D'+B'D+B'C5. Circuit Problem: Convert each of the following circuits to a Boolean expression. Then simplify the expression, and draw the corresponding simplified circuit. (a) (b) a b' a' b —b — с' a a' "CHHE (c) a bReset A/O B/O so S1 S2 B/O AB/1 A/O A+ BIO Describe in words what the state machine in figure above does. Using one- hot encodings, complete a state transition table and output table for the FSM above. Write Boolean equations for the next state and output and sketch a schematic of the FSM.
- A 4-bit magnitude comparator is explained in the attached file. With similarlogic, design a 3 bit magnitude comparator. You must show the equations and draw the logic circuit. [Hints: A and B are two numbers each with 3 bits. How can you implement a circuit to compare these two numbers if, A=B, A>B or A<B]Adocs.google.com is a logic switch that select information from one of the input line and directs it to a single line Encoder Decoder Adder Multiplexer Binary to octal can be implemented used 3-8 De-Multiplexer Multiplexer Decoder Encoder System base 12 include numbers from ... to .... 1-B 1-C 1-12 1-11 ۹:۰۳ FDesign a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W X Y Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'C