Write a program that can calculate the future and present value of an investment given various parameters. When you calculate the future value of an investment, the more years you hold the investment and the higher the rate of return, the more valuable it is. For example, a $1000 investment at 7% return will give you $1070 (1000+ 0.07-1000) after one year and $1144.90 (1070+0.07-1007) after two years. However, because of inflation, that $1144.90 after two years is not worth the same as $1144.90 now. If the inflation rate is 2%, $1144.90 in two years is the equivalent of $1100.44 now-i.e- 102 More generally, the present value, p, of an investment is 1.02² 1144.90 f p= where is the inflation rate as a percentage. Typically, one would add to the investment with annual contributions. Let's say you start with a $1000 investment and add $100 every year. Therefore, after the first year, you will have $1177 - 7% return on $1100i.e. $1000 initial investment + the $100 year one contribution. After the second year, you will have $1366.39 - 7% return on $1277 - i.e. $1177 year one end + the $100 year two contribution. For 10 years, you will get the following: Year 0 1 2 3 4 5 6 7 8 9 10 (1+. ¹+100) Payment Future Value Present Value 1000.00 100.00 100.00 100.00 100.00 100.00 100.00 100.00 100.00 100.00 100.00 1177.00 1366.39 1569.04 1785.87 2017.88 2266.13 2531.76 2815.99 1153.92 1313.33 1478.54 1649.87 1827.66 2012.26 2204.05 2403.42 2610.76 2826.52 3120.10 3445.51 The present value is calculated from the future value using the above formula. Running the program Your program should take 5 arguments: start annual years return inflation where start is the initial investment amount annual is the amount that is added to the investment every year years is the number of years that the investment is held return is the annual investment return expressed as a percentage inflation is the annual inflation rate expressed as a percentage So, to calculate the future and present value of $1000 investment after 10 years where you add $100 every year with a 7% return and 2% inflation, you give the following arguments and get this output: $ ./fv 1000 100 10 7 2 Future Value: $3445.51 Present Value: $2826.52 Writing the code Starter code is provided for you below int main(int arge, char **argv ) { int a, n double value, present, I, is value= atof (argv[1]); a = atoi (argv[2]); natoi (argv[3]); r = atof (argv[4])/100; i = atof(argv[5])/100; // TODO write your code here printf("Future Value: $%.2f\n", value) printf("Present Value: $%.2f\n", present); I have provided code to input the 5 arguments using argy and also code to print the results. Do not change this code. The first three arguments are integers, but the last 2 arguments are floating-point arguments, so that's why I use the double type and the atof function instead of atoi. Remember that the investment return and inflation rates are expressed as percentages - that's the reason for the divide by 100. You will need to write a loop that iterates over the number of years and accumulates the future value. Make sure to add the annual contribution every loop iteration. Note that it is possible to calculate the future and present value with a single equation, but for this problem, you are required to do the calculations using a loop. Do not use any functions from the built-in math library. You will need to create a function to calculate the power function so that you can get the denominator of the present value formula.