Please help in C++ Write a while loop that prints all powers of 2 that are less than a given number n. For example, if n is 100, print 1 2 4 8 16 32 64.loop.cpp#include 2using namespace std;3int main()5 {4cout <« "n: " « endl;int n;cin >> n;8...10while (...)1112cout << ... <":13...1415cout <« endl;1617return 0;18 }CodeCheckReset

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Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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extern "C" int f(int *,int,int); int a[2][2] = {{11,12},{21,22}}; void setup(){ Serial.begin(115200); while(!Serial); delay(500); int *arr = (int*)a; Serial.println(f(arr,2,2)); } void loop(){ } .global f f: ldr r3,[r0] // get first element mov r2,#0add r2,r3 mov r1, #3 lp: add r0,#4 // add next elementldr r3,[r0]add r2,r3sub r1,#1 bgt lp mov r0,r2 bx lr Describe what operation is being performed in this code
JAVA CODE PLEASE Functions With No Parameters and Return Values Quiz by CodeChum Admin Create a function named banner that prints “CodyChum” with a newline. In the main function, write a program that accepts an integer input which would serve as an inclusive stopping point of a loop iteration that starts at the value of 1. If the number that loops through the range is divisible by either 2 or 3, then call the banner function, otherwise just print the number. Input 1. One line containing an integer Output First line is the integer user input. Succeeding multiple lines containing an integer or “CodyChum” 10 1 CodyChum CodyChum CodyChum 5 CodyChum 7 CodyChum CodyChum CodyChum
Write a loop that finds the smallest value. Print it and the index code format: #include <iostream>using namespace std; #include <cstdlib> // required for rand() int main(){// Put Part2 code here // Declare smallestFoundSoFar// Q: what should be its initial value?int indexOfSmallest = -1;// sign that it is not initialized Part 2 code #include <iostream> using namespace std; // part 1 code#include <cstdlib> int main() { srand(17); const int ARRAYSIZE = 20; // size for the array int RandArray[ARRAYSIZE]; // array declared int i; // to iterate the loop // this loop will store thei random number in the array for (i = 0; i < ARRAYSIZE; i++) RandArray[i] = rand() % 100; // this loop will print the array for (i = 0; i < ARRAYSIZE; i++) cout <<"randArray["<< i <<"]=" << RandArray[i] << endl; int largestFoundSoFar=-1; // anything is larger than this! int indexOfLargest = -1; // sign that it is not initialized for (i = 0; i…
/* segvhunt.cFind and eliminate all code that generates Segmentation Fault*/#include <stdio.h>int main() {char **s;char foo[] = "Hello World";*s = foo;printf("s is %s\n",s);s[0] = foo;printf("s[0] is %s\n",s[0]);return(0);}
In c++ Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, th backwards End each loop with a newline. Ex If courseGrades (7, 9, 11, 10), print: 7 9 11 10 10 11 9 7 Hint Use two for loops. Second loop starts with i=NUM VALS-1. (Notes) Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades(4) See 'How to Use zyBooks Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message 32344345730rity? 2 using namespace std; 3 4 int main() { 5 6 7 8 9 10 11 12 13 14 const int NUM VALS-4; int courseGrades [NUM VALS]; int i; for (i = 0; i > courseGrades[1]; } y Your solution goes here Y
C++ A robot is initially located at position (0; 0) in a grid [?5; 5] [?5; 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move and the current position of the robot. If the robot makes a circle, which means it moves back to the original place, print "Back to the origin!" to the console and stop the program. If it reaches the boundary of the grid, print \Hit the boundary!" to the console and stop the program. A successful run of your code may look like:Down (0,-1)Down (0,-2)Up (0,-1)Left (-1,-1)Left (-2,-1)Up (-2,0)Left (-3,0)Left (-4,0)Left (-5,0)Hit the boundary! or Left (-1,0)Down (-1,-1)Right (0,-1)Up (0,0)Back to the origin! About: This program is to give you practice using the control ow, the random number generator, and output formatting. You may use <iomanip> to format your output. You may NOT use #include "stdafx.h".
#include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…
Use a for loop to modify each element of arrfile4 by 2Use a for loop to modify each element of arrfile4a by 3 write the new contents of arrfile4 to file4by2write the new contents of arrfile4a to file4aby3 CODE: import java.util.*; import java.io.*; public class Pwriter2 { public static void main(String[] args) throws IOException { PrintWriter tofile2 = new PrintWriter ("file4.txt"); PrintWriter tofile2A = new PrintWriter ("file4a.txt"); int[] arrfile4=new int [10]; int[] arrfile4a=new int [10]; int i=0; while(i<10) { arrfile4[i]=i+1 ; tofile2.println(arrfile4[i] ); arrfile4a[i]=i+11; tofile2A.println(arrfile4a[i]); i=i+1; } tofile2.close(); tofile2A.close(); } }
A/ find code optimization method to this code and then find type to this code 1- For(i=1;i
Q1 #include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…
a) FindMinIterative public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i]; } return x; } b) FindMinRecursive public int FindMin(int[] arr, int length) { if(length == 1) return arr[0]; return Math.Min(arr[length - 1], Find(arr, length - 1)); } What is the Big-O for this functions. Could you explain the recurisive more in details ?
#include <stdio.h> #include <string.h> int IsPasswordOkay(char* pass) { char Password[12]; strcpy(Password, pass); if (!strcmp(Password, "goodpass")) return(1); else return(0); } int main(int argc, char **argv) { int PwStatus; if (argc < 2) { printf("Input your password\n"); return(-1); } PwStatus = IsPasswordOkay(argv[1]); if (PwStatus == 0) { printf("Acces denied"); return(-1); } else { printf("Access granted"); return(1); } } Write a function to conduct input validation to secure the smallest buffer. You may call this function void SecurePasswordBuffer(const char *arg).

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