Write an 8086 assembly language a program to find the number of (1) in the AX and add it to the BL and the number of () in the AX and add it to the BH ? Note: Answer in Hexadecimal .
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- From the BCD code whose block diagram is given in the figure below, you can find the 7-segment LED display (with common anode) code. Solving combinational logic circuit will be designed. This type of commercially produced decoder is integrated State the features you consider important by researching the circuits. BCD input at the output of the decoder For the 0-9 values of the information information, the following indicator figures will be seen and the values other than these it will be considered arbitrary. Since the 7-segment LED display has a common anode, Logic "0" will be applied to the burned parts. The accuracy of the logic circuit you will design Create the table and find the output expressions by shrinking the table with the Karnaugh diagram method.From the BCD code whose block diagram is given in the figure below, you can find the 7-segment LED display (with common anode) code. Solving combinational logic circuit will be designed. This type of commercially produced decoder is integrated State the features you consider important by researching the circuits. BCD input at the output of the decoder For the 0-9 values of the information information, the following indicator figures will be seen and the values other than these it will be considered arbitrary. Since the 7-segment LED display has a common anode, The logic "0" will be applied to the burned parts. Draw this circuit.ehcu.org/pluginfile 100% 10 / 11 locations, count how many times is 0 and how many times 1 is. Questions:- 1- Write a program in assembly language to perform the following logic ci BL CL DL [5100]- 2- How we can perform the NEG and NOT instructions by using different instructions. 3- Write the following program by using different instruction or instructions for each instruction on the program. MOV AL , 00 MOV BX , FFFF XOR CL , FF NEG BYTE PTR [DI] AND CX , LG
- Digital logic design Solve it with drawing and simulation lab I need them both to have the full solution. And thanks Design counter that counts from 00 to 59, using the IC 74LS90 ripple counter and use two 7 segment display to display the result count. You can also use 7447 binary to 7-segment Display Decoder.From the BCD code whose block diagram is given in the figure below, you can find the 7-segment LED display (with common anode) code. Solving combinational logic circuit will be designed. This type of commercially produced decoder is integrated State the features you consider important by researching the circuits. BCD input at the output of the decoder For the 0-9 values of the information information, the following display figures will be seen and the values other than these it will be considered arbitrary. Since the 7-segment LED display has a common anode, Logic "0" will be applied in response to the burned parts. The accuracy of the logic circuit you will design Create the table and find the output expressions by shrinking the table with the Karnaugh diagram method.6) Write an 8086 assembly language program to multiply the contents of the registers CL & BL by using repeated addition and store the result in AX. 0006
- answere fast please question from DIGITAL LOGIC DESIGN TOPIC : Designing Combinational Logic You are designing a water level circuit using 74ALS151 (8 to 1 Multiplexer IC)* When input is 0000 that means tank is empty.* When input is 1111 that means tank is full.* When input is below 5, that means water level is low.* So, make a circuit using 74ALS151 Multiplexer IC that shows a "low water" indicator light(by setting an output L to 1) when the water level drops below level 5.Q2/A) Design 8x1 multiplexer using 2x1 multiplexer? Q2 B)Simplify the Logic circuit shown below using K-map then draw the Simplified circuit? Q2/C) design logic block diagram for adding 12 to 5 using full adder showing the input for each adder?Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).