write ARM assembly code to find an average of 16 inputs and store in an address then find minimum and maximum.
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A: the solution is an given below :
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A: GIVEN:
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A: Lets see the solution.
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A: Given The answer is given below.
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A: Mov R0,#0x20000100Msr APSR,R0LDR R0, [APSR]LDR R1,[APSR,#1] LDR R3,[APSR,#1] LDR R4,[APSR,#1] LDR…
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Q: The program then computes the sum of the three values,
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write ARM assembly code to find an average of 16 inputs and store in an address then find minimum and maximum.
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- please write the exchange instruction code. Need perfectly correct, otherwise skip.Draw the Output bus cycle of 8086 I/O interface.For each of the following sets of RISC-V assembly instructions below, identify any data hazards that occur and indicate which type (i.e., EX hazard 1a or 1b, MEM hazard 2a or 2b, or load-use hazard) of hazard has occurred. You can specify where the hazard has occurred by indicating which instruction (i.e., the first instruction, second instruction, etc.) will experience the hazard. x11, 0(x6) x12, 8(x6) add x20, x11, x12 x20, 0(x6) x13, 16(x6) add x20, x20, x13 x20, 8(x6) ld ld sd ld sd
- Write an ARM code segment that will provide the equivalent to a NAND function. Hint: there is no single NAND instruction.An ADD instruction stores a value 7308h at offset value 9F71h. if the computed address is 7CB31h, what will be the starting address? Assume real mode operation a. 72BC0 b. 72BC00 c. 82BBF d. 82BBF0An ADD instruction stores a value 7308h at offset value 9F71h. If the computed address is 7CB31h, what will be the ending address? Assume real mode operation a. 82BBFH b. 72BC0H c. 73BBFFH d. 7CB31H
- Write an ALP for 8086 to add two hex numbers augend 88 h and addend = C3 h without using ADC instruction and store the result (sum) in the memory address 300 H and result (carry) in the memory address 400 H.Q1-Design the hardware required to interface 32KB of SRAM to the demultiplexed address and data bus of the 8086 Microprocessor connected in minimum mode using 16Kx8 memory chips. Decode the memory using two method the first one is with simple NAND gate decoder the second method is Decode the memory with 3-to-8-line decoder (74138). so that it starts from physical address 00000h also for each memory chip used in your Design determines the range of physical address which can handle. 9255 hin with 9096 microprocessors to work on on YOExplain the difference between a R, I, and J instruction type in MIPS.
- Please write corresponding MIPS assembly instruction to the right of MIPS machine instruction.Need some help with this. The code is attached below 1. Translate the following C code to RISC-V assembly code, using the minimum number of instructions you can think of. The values of: w, y, i, j are in registers: x4, x5, x6, x7. Register x10 holds the base address of array A. 2. How many RISC-V instructions are needed to implement the above code? If w and y are initialized to 5 and 10, and elements of A are initially 0, what is the total number of RISC-V instructions executed to complete the loop?Develop an assembly language program for 8085 microprocessor to count continuously in hexadecimal from 00H to 0FH in a system with 1 MHz frequency continuously. Use register pair technique to set up a 750 ms delay between each count and display the count at output port address 00H.