pls answer the The mass contained in the cylinder, in kg, is: Your answer has been saved. See score details after the due date.The expression used to solve for the mean effective pressure is:мерWeV(1-2)mep (p, + P₂ + P +P₁)/4WeV(1-2)mcp=mcp =WeeV₂Calculate exergy transferYour answer has been saved. See score details after the due date.The expression used to solve for the exergy transfer accompanying the heat addition to the cycle is:Fo.23= m(ws - 12) - mTo|csin -Rin.Eg2 = (1-1) - mTa[1² - & -Ⓡ)]€)Eg23 = To--Rin()O= m (1₁-12) - MT [ 2² - 2 - Rin (m(s)- Rin() - FieYour answer has been saved. See score details after the due date.OAttempts: 1 of 1 usedThe volume of the cylinder at State 1, in L. is:Attempts: 1 of 1 usedYour answer has been saved. See score details after the due date.0.5901.3810.7246.370(Ew) cycle = W₁3 - W₁2 = Weyle−(Ew)cycle = [Was - Po(V₂ - V₁)] + [W₁2 - Po(V₂ - V.)](Ew) yle= Was Po(V₁ - V₁)None of the answers provided.The mass contained in the cylinder, in kg, is:6.85 × 10-4O 8.41 x 10-4O 1.61 × 10-37.40 x 10-3Your newer has been seved See score details after the due date.PiThe expression used to solve the orgy transfer accompanying the heat rejection from the cycle is (note that v = v.Calculate exergy transferque (teks) mit 2-4-F-1(₁-2₁)-MiTo|12-19 - Rix((7)Five (₁-21)- MiTo | (7)|Kape - m(te - ks) —mita|-|The color wood to solve the energy trwale walanging die mark of the yearwerhot hand Senre details smer the deteⒸ(F) - Was - P(V₁-₂)] [Wi-(-V)](F)Ⓒome of the camera provided.The expression used to solve the exergy transfer accompanying the work of the cycle is:Determine the cylinder volume for an air-standard Otto cycleDetermine the cylinder volume for an air-standard Otto cycleYour answer has been saved See score details after the due dateThe value of the cylinder State 1, in LiⒸ0.590Determine the cylinder mass for an air-standard Otto cycleWas-P(V-V₂)- 0724Attempt 11 sedAttempe 1 of 1 usedAttempts: 1 of 1 usedAttempts: 1 of 1 used At the beginning of the compression process of an air standard Otto cycle, p₁ = 1 bar, T₁ = 300 K. The maximum temperature inthe cycle is 2250 K and the compression ratio is 9.8. The engine has 4 cylinders and an engine displacement of V=2.6 L. Determineper cylinder:a) the volume at state 1.b) the air mass per cycle.c) the heat addition per cycle, in kJ.d) the heat rejection per cycle, in kJ.e) the network per cycle, in kJ.f) the thermal efficiency.g) the mean effective pressure, in bar.h) Develop a full exergy accounting per cycle, in kJ. Let To = 300 K, P = 1 bar.i) Devise and evaluate the exergetic efficiency for the cycle.Understand air-standard Otto cycleYour answer has been saved. See score details after the due date.Which statement is true for this air-standard Otto cycle?Heat is added to the air at constant volume.O Heat is added to the air at constant pressure.O Heat is rejected from air at constant pressure.O None of the answers provided.Understand compression ratioYour answer has been saved. See score details after the due date.Which expressions are used to solve for the volume V₁ given the information provided?OOr =r=r=T=V₂V/₂V₁and V₂ V₁ VaV₂and V₂ = V₁ + VaVand V₂ = V₁ - VaV₂₁₂and V₂ V₁ VaUnderstand isentropic compressionAttempts: 1 of 1 usedAttempts: 1 of 1 usedYour answer has been saved. See score details after the due date.Which expressions can be used to fix State 2?V₁ = rand = rV₂VrlP2= rand P2 =PrP₁PA=rV2 = rand 2 = rV₁P₁None of the answers provided.Calculate heat additionYour answer has been saved. See score details after the due date.The expression used to solve for the heat addition from 2 to 3 is:ⒸQ23 = m(4₂ - 12)ⒸQ23 = m(U₂ - 143)ⒸQ23= m(us-M₁)O None of the answers provided.Calculate net workYour answer has been saved. See score details after the due date.The expression used to solve for the network of the cycle is:Wcycle = ml(us-M₁)+(1₂-₁)]Wcycle = m[(h3 - ₂) - (₁-₁)]Wcycle = (13-U₁) + (U₂ − U₁)Ⓒ Wcycle = m[(U3 - U₁) – (U₂ - ₁)]Attempts: 1 of 1 usedAttempts: 1 of 1 usedAttempts: 1 of 1 used

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