Your ear Class Observed Class Expected R1 /Su (Purple, Smooth) 5 245 rlrl/Su (Yellow, Smooth) S x² = R1 /susu (Purple, Wrinkled) 50 72.44 82 3 a 7. Test the validity of the data using the chi-square test. The chi square is a simple mathematical calculation which can be used to determine how well the observed experimental data (your actual results) fits the theoretical prediction (the expected results). The formula for the chi-square is: 82 3 rlrl/susu (Yellow, Wrinkled). 20.5 31.72 (0₁-e₁)² (0₂-e₂)² (03-e3)² (04-e4)² e1 e3 e4 + + Total Kernels 337.5 35.78 435535 X² = the symbol for the term, chi-square o = observed count (number) (01 = the number of purple/smooth, 02 = the number of yellow/smooth, 03= the number of purple/wrinkled, 04 the number of yellow wrinkled) e = the expected number according to the predicted ratio. All en must be calculated for your sample

Your ear Class Observed Class Expected R1 /Su (Purple, Smooth) 5 245 rlrl/Su (Yellow, Smooth) S x² = R1 /susu (Purple, Wrinkled) 50 72.44 82 3 a 7. Test the validity of the data using the chi-square test. The chi square is a simple mathematical calculation which can be used to determine how well the observed experimental data (your actual results) fits the theoretical prediction (the expected results). The formula for the chi-square is: 82 3 rlrl/susu (Yellow, Wrinkled). 20.5 31.72 (0₁-e₁)² (0₂-e₂)² (03-e3)² (04-e4)² e1 e3 e4 + + Total Kernels 337.5 35.78 435535 X² = the symbol for the term, chi-square o = observed count (number) (01 = the number of purple/smooth, 02 = the number of yellow/smooth, 03= the number of purple/wrinkled, 04 the number of yellow wrinkled) e = the expected number according to the predicted ratio. All en must be calculated for your sample

Biomedical Instrumentation Systems

1st Edition

ISBN:9781133478294

Author:Chatterjee

Publisher:Chatterjee

Chapter13: Artifacts And Noise In Medical Instrumentation

Section: Chapter Questions

Problem 7P

See similar textbooks

Similar questions

1) You compare the height and weight of 5 adult women. You get the following results:height 60 67 62 70 66weight 119 143 131 155 136(a) Construct a scatter plot of height (x) vs. weight (y)(b) Calculate the following (show your work for SScp):SSx SSy SScp ̄x ̄y(c) Calculate the correlation coefficient (r)2) Use the information from problem 1. Perform a complete test of the hypothesis that the populationcorrelation coefficient (ρ) is 0. Show all steps (note - obviously this should be a one sided test! Make sure youknow why!).3) Now let's assume you wanted to predict weights from heights. In other words, now let's use the same datafrom problem (1) and do a regression instead.(a) Calculate b0 and b1.(b) Carefully draw your least square regression line on the plot you made in 1(a). (Don't just “sketch”,be a little careful).4) (a) Now do a significance test of H0: β1 = 0. Show all your calculations (including your residualcalculations). Again, note that this should be a one sided test…
Please help me with these 2 questions based on the graph below. More than one answer may be correct for each question: 1) Figure 1. Normative hair cell data for the lateral semicircular canal in humans. Linear fitted regression line is included (n = 67). The above graph shows... a) a decrease in taste buds with age in humans.b) the relationship between hair cell density and age in humans.c) the complete loss of a photoreceptor in humans 80 years old and above.d) the disappearance of hair follicles in older humans.e) a higher density in a type of mechanoreceptor in younger humans. 2) Figure 1. Normative hair cell data for the lateral semicircular canal in humans. Linear fitted regression line is included (n = 67). The data presented in this graph could help explain why... a) turning one's head quickly may result in vertigo in older humans.b) using playground swings can make you dizzy and/or nauseous as you get older.c) long bouts of laying down without moving can cause dizziness and/or…
Use MS Excel to plot and determine the terms being asked: Please insert the excel file, thank you For each V (mmol/min), determine the value of [S] (mM) if Vmax = 5 mmol/min. Show your calculations. Using MS Excel, plot [S] (mM) versus V (mmol/min). Draw a line corresponding to the given Vmax parallel the x-axis and extend your plotted line to show its approach to Vmax. Provide your final plot [S] (mM) V (mmol/min) 10 1.2 1.7 2.1 2.2 2.5 Determine the values of Km and Vmax for the decarboxylation of β-keto acid given the following data. Please show and label your plot. Show your calculations and box your final [S] in mol/l V in mM/ min 2.500 0.588 1.000 0.500 0.714 0.417 0.526 0.370 0.250 0.256
For most cases, a p value of 0.05 is used to determine whether results fit expected values. Is this a magic number, or could p values be set more stringently, say 0.01, or more lax, say 0.10? What effect would these values have on the reliability of the chi-square test?
The gels diagrammed below show the results of amplifying two VNTR loci from: 2 hairs found at a crime scene (hair 1 and hair 2), a crime victim, and possible suspects. Determine whom hair 1 could have belonged to based on the results in the gel below. If the hair could belong to more than one individual, then choose all of the possibilities. If the hair could not belong to any of these, choose "none of these". VNTR Locus 1 Hair 1 Hair 2 Victim Suspect 1 Suspect 2 Suspect 3 Suspect4 VNTR Locus 2 Hair 1 Hair 2 Suspect 1 Suspect 2 Suspect 3 Suspect 4 Victim Select one or more: O Victim O Suspect 1 O Suspect 2 O Suspect 3 O Suspect 4 O None of these
This question is based on Bovine Serum Albumin I would like help on answering letters a-c. This lab examines the relationship between the absorbance of light by a solution at 595 nm and the concentration of the Coomassie Blue dye-BSA protein complex in the solution. State whether the following descriptions of the lab experiment are valid or not, and explain why you say Yes or No: a. The experiment would be significantly more accurate if absorbance readings were recorded for a range of wavelengths, not just for 595 nm b. The experiment has limited accuracy because it does not account for the absorbance of light by the other components (components that are not the dye-protein complex, such as excess dye that is not bound to any protein) of the solution. c. The absorbance reading measures practically all the protein content in the solutions
Example 3.5.7 Fish Vertebrae Consider the distribution of vertebrae given in Table 3.5.1. In Exam- ple 3.5.5 we found that the mean of Y is µy = 21.49. The variance of Y is VAR(Y) = of = (20 – 21.49) x Pr{Y = 20} 21) %3D + (21 – 21.49)? x Pr{Y + (22 – 21.49)? x Pr{Y = 22} + (23 – 21.49) x Pr{Y = 23} = (-1.49) x 0.03 + (-.49) x 0.51 + (0.51) x 0.40 + (1.51)² × 0.06 = 2.2201 x 0.03 + .2401 x 0.51 + .2601 x 0.40 + 2.2801 x 0.06 = 0.066603 + 0.122451 + 0.10404 + 0.136806 = 0.4299. The standard deviation of Y is ay = V0.4299 - 0.6557. %3D
Use the scoring system described to calculate the alignment score for IPNI AAIG DV VAGP VKGIYA VG DV C-GK Scoring system: • Each identity results in +10 points. • Each gap has a penalty of -25 points. score = What is the percent identity (also called percent identity match)? percent identity: %
Calculate Nabil's BMI O 95/(1.70X1.70)= 32.8 O 95/(1.7 x 2)= 27.9 O 95/1.7= 55.8 O 95/ 170= 18.5
in basic spectrophotometer technique, 1. Calculate the concentration of bovine serum albumin (BSA) if 40% of a light beam is transmitted through 2 cm of the cuvette (assume the molar absorption coefficient, e is 43,824 M-1 CM-1). 2. Calculate the %T, if the concentration of BSA in a 2 cm of cuvette is 0.025 mg/mL. and compare between 1 and 2.
[S] (mM) v0 (mM/sec) 6 150 17 250 29 260 40 360 50 350 60 400 72 403 82 425 92 430 103 442 115 455 125 450 Km and Vmax obtained from the Lineweaver-Burk plot and linear regression analysis for the data in Table 2 are 16.9 mM and 503 mM respectively. Compare these values to the values obtained Vmax = 525.3 µM/sec Km = 20.70 µM . Which method, nonlinear regression or linear regression, is more tolerant to an experimental error? Note that lower substrate concentrations, which often have the greater error, have a greater effect on the slope of the line in the Lineweaver-Burk plot.
If one is testing a goodness of fit to a 9:3:3:1 ratio, how many degrees of freedom would be associated with the Chi-square analysis?