y²x = 1 + Cy

Q: = 1 +

A: We have to find

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Q: Find the general solution of y''=xcos(x)

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Q: indeterminate coefficient method x^2y´´+2xy´-2y=x^2      y(1)=0      y´(1)=1/2

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Q: Use variation of parameters to find the general solution of the equation  y" - 2y' + y = (e^(x))/x…

A: Use variation of parameter.

Q: y²x = 1 + Cy

A: From the given problem: y2x=1+Cy....1 Now differentiate the above equation with respect to x.…

Q: Elimination of Arbitrary Constants Solve y = C1e^4x + C2e^-5x O y" +y' + 20y =0 O y" - y' + 20y =0 O…

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A: To complete the table, y1 y2 Solutions y=-2x+1 y=-12x-2   y=-2x+1 y=12x-4   y=x-3 y=-3x+1

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Q: С. REDUCTION OF ORDER AND VARIATION OF PARAMETERS 1 1. (D² + 8D + 16)y 1-e4x

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Q: Elimination of Arbitrary Constants Full solution. x³ - 3x2y = C

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Q: is the price, sumer surplus at the equilibrium point, and (c) th 1 D(x) = -EX 4 x+ 23, S(x) = x+5…

A: In this question we will use basic of calculus. We will use the concept that at equilibrium consumer…

Q: 4. Separation of variables: Obtain the general solution. (1 – x)y' = y? a. y In[c (1 – x)] = 1 b. x…

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Q: A. Elimination of Arbitrary Constant Eliminate the arbitrary constants (1) y = (c + c2x)e* + 2x - 4

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Q: QU ESTION 1: f6) = 2x²- 4x + 2 g(x) = 4x²-6x+ 2 h(x)= 2x-2 i(x) = 2x²-3x-2 %3D Find: C) H) o h(3)

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Q: orth0gonal trajectories y^2=4x^2(1-kx)

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Q: Boundany condition ) Solve the initial value probfem : (x-1) y" +xy' +y =0; y@) =2, y'c0)= -1

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Q: y1 y2 solutions Example: y= x-3 y= -5/2 x +4 (2,-1) y= -2x+1 y= -½ x -2

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Q: 1. 2cos(x) = vV3 2. V3 csc(x) – 2 = 0 %3D Interval [0,27)→ x = Interval [0,2n)→ x = General…

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