Q1/ Three reactors linked by pipes. As indicated, the rate of transfer of chemicals through each pipe is equal to a flow rate (Q, m³/s) multiplied by the concentration of the reactor from which the flow originates (C, mg/m³). In steady state, develop mass balance equations for the reactors, and solve the three simultaneous linear algebraic equations for their concentrations by Gauss-elimination method with partial pivoting. 400 mg/s 221%2 Q13c1 0121 e23c₂ 3 200 mg/s 233= 120 13 = 40 12 = 80 l23 = 60 21 = 20

Q1/ Three reactors linked by pipes. As indicated, the rate of transfer of chemicals through each pipe is equal to a flow rate (Q, m³/s) multiplied by the concentration of the reactor from which the flow originates (C, mg/m³). In steady state, develop mass balance equations for the reactors, and solve the three simultaneous linear algebraic equations for their concentrations by Gauss-elimination method with partial pivoting. 400 mg/s 221%2 Q13c1 0121 e23c₂ 3 200 mg/s 233= 120 13 = 40 12 = 80 l23 = 60 21 = 20

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Develop three mass balance equations for each tank in Figure 1. Solve to determine the concentrations in each tank. Use 'np.linalg.solve' to solve the system of equations you generate. Assume the tanks are at steady-state (i.e. concentration within each tank is not changing with time) and well-mixed (i.e. the concentration flowing out of the tank is equal to the concentration within the tank). Mass can be tracked by multiplying flow rate, Q (L/s) by concentration, c (mg/L) to give mg/s. Hint: for each tank the mass coming in mg/s must equal the mass going out mg/s, set this up like our two reactor example from lecture 6. Note: Volume balances must hold in addition to mass balances. In other words, the Q entering the tank must equal the Q leaving the tank. You can use this principle to find any values for Q that are missing in the figure. 500 mg/s 221c2 21291 Q13c1 2 02392 Q33c3 500 mg/s 33 = 120 13 = 40 212 = 90 23 = 60 21 = 30
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