problem1. Formulate the YBus matrix for the network shown here.Line Series Reactance p.u. Shunt Admittancep.u1-21 0.20) 0.10I 0.251 0.241 0.161 0.302-331-3problem2. Modify YBus in the previous problem if the line between 1 and 2 is removed.problem3. Given the impedance diagram of a simple system as shown in the figure, draw theadmittance diagram for the system and develop the 4 x 4 bus admittance matrix YBus byinspection.j1 EZ12=j0.4= jo.81Z13= j0.2Z;3=j0.23.Z34=j0.08

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1. Formulate the YBus matrix for the network shown here. Line Series Reactance p.u. Shunt Admittance p.u 1-2 1 0.20 1 0.10 I 0.25 1 0.24 ) 0.16 1 0.30 2-3 3 1-3

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.46P

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Norton Theorem

In the current circuit law, the Norton theorem (also known as the Mayer-Norton theorem) is a simplification that can be applied to networks generated by a constant line of opposition, power sources, and current assets. In two network terminals, it can be switched on with a current supply and single resistor respectively.

Question

problem
1. Formulate the YBus matrix for the network shown here.
Line Series Reactance p.u. Shunt Admittance
p.u
1-2
1 0.20
) 0.10
I 0.25
1 0.24
1 0.16
1 0.30
2-3
3
1-3
problem
2. Modify YBus in the previous problem if the line between 1 and 2 is removed.
problem
3. Given the impedance diagram of a simple system as shown in the figure, draw the
admittance diagram for the system and develop the 4 x 4 bus admittance matrix YBus by
inspection.
j1 E
Z12=j0.4
= jo.8
1
Z13= j0.2
Z;3=j0.2
3.
Z34=j0.08

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