a XCF) = 5 SCF - 2000 +58(f+2000 )+3 6(F-300) + S( F+30)XF) =- 2-58(F-2000) +2-5 6CF+2000) +1-56(F -3000) +Noo the sampled spectaum Expression is1•5 6(F+3000)Xs (F )= Ę Ž x(f-nfs) = Ss 2 xCfnfs)Ts n=-0n=-00- 8000 2 XCF-n8000)%3Dnニ-のI need the drawing step by stepand each information separatelyStep 3 of 5:)The spectoumX(F) is2.51.511-5FCKHZ)2-3-2- 0o to +0we cam drao spedtoum asOn putingn from2.5x8000 =20,00012000235 6 8 10 I| 13 14 16 18 21*a 49 -14 -13 - -l0-G -6-5 -3 -2 o4 KHZcut off Frequermcy is* output spectoum is20, O0012,0007FCKHZ)-3 -2Nouo eguation 5 oulput spectrum isyE) =24000Cos(an x3000t) + 49000 COs(aix2000

Answered: Image /qna-images/answer/ea51162e-baf0-461f-8115-9201cd662da0.jpg

-21 -14 14 -3 -1 -10-G -6-5 -3 -2 o 2 3 Step 3 of 5:) I need the drawing step by step and each information separately The spectoum XC F) is 2.5 12.5 1.5 FCKHZ) -2 2 - 3 we can drauo spedtoum as On puttingn from -o to +oo 2.5X8000 =20,000 12000 5 6 8 1o I| 13 14 16 18 21 FCHE tf Frequency is 4KHZ * output spectrum is 20, O00 12,000 FCKHZ) 3 3 -2 0 2 NoUO equation 5 oulput spectrum is aE) = 240ocos(an x3000t) + 49000 Cos(aTI x 2.000

-21 -14 14 -3 -1 -10-G -6-5 -3 -2 o 2 3 Step 3 of 5:) I need the drawing step by step and each information separately The spectoum XC F) is 2.5 12.5 1.5 FCKHZ) -2 2 - 3 we can drauo spedtoum as On puttingn from -o to +oo 2.5X8000 =20,000 12000 5 6 8 1o I| 13 14 16 18 21 FCHE tf Frequency is 4KHZ * output spectrum is 20, O00 12,000 FCKHZ) 3 3 -2 0 2 NoUO equation 5 oulput spectrum is aE) = 240ocos(an x3000t) + 49000 Cos(aTI x 2.000

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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