375*K4 mm k = 50*K2 N/m 50*K4 mm B www A 50* K4mm 100* K4 mm 3- A 2*K2 kg wheel has a radius of gyration about its center of gravity, of m. The wheel is released from the rest position. It then rolls K3 without slipping and rotates 90 degrees clockwise. The spring has a stiffness of 50*K2 N/m, and its natural length is 125*K4 mm. a- Compute the moment of inertia of the wheel with respect to its center of gravity. b- Compute the initial potential energy of the system (before rolling) c- Compute the final potential energy of the system (after rotating 90 degrees)
375*K4 mm k = 50*K2 N/m 50*K4 mm B www A 50* K4mm 100* K4 mm 3- A 2*K2 kg wheel has a radius of gyration about its center of gravity, of m. The wheel is released from the rest position. It then rolls K3 without slipping and rotates 90 degrees clockwise. The spring has a stiffness of 50*K2 N/m, and its natural length is 125*K4 mm. a- Compute the moment of inertia of the wheel with respect to its center of gravity. b- Compute the initial potential energy of the system (before rolling) c- Compute the final potential energy of the system (after rotating 90 degrees)
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.11P: Solve Prob. 7.10 assuming that the pick-up truck has front-wheel drive.
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K1=4 K2=10 K3=7 K4=4
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