8.) A supply of 50 kg of chicken at 6 C contained in a box is to be frozen to -18 C in a freezer (Figure). Determine the amount of heat that needs to be removed. The container box is 1.5 kg, and the specific heat of the box material is 1.4 kJ/kg • K. m=50kg h=247 kJ/kg Chicken m= 50 kg T=6°C T=-18°C freezing =-2.8°C C3=3.32 kJ/kg.K Ch=1.77 kJ/kg.K Container =1.5 kg Cbox=1.4 kJ/kg.K

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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8.) A supply of 50 kg of chicken at 6 C contained in a box is to be frozen to -18 C in a freezer
(Figure). Determine the amount of heat that needs to be removed. The container box is 1.5 kg,
and the specific heat of the box material is 1.4 kJ/kg • K.
mc=50kg
h=247 kJ/kg
Chicken
m= 50 kg
T=6°C
T=-18°C
Tfreezing=-2.8°C
Ca=3.32 kJ/kg.K
Ch=1.77 kJ/kg.K
Container=1.5 kg
Cbox=1.4 kJ/kg.K
Transcribed Image Text:8.) A supply of 50 kg of chicken at 6 C contained in a box is to be frozen to -18 C in a freezer (Figure). Determine the amount of heat that needs to be removed. The container box is 1.5 kg, and the specific heat of the box material is 1.4 kJ/kg • K. mc=50kg h=247 kJ/kg Chicken m= 50 kg T=6°C T=-18°C Tfreezing=-2.8°C Ca=3.32 kJ/kg.K Ch=1.77 kJ/kg.K Container=1.5 kg Cbox=1.4 kJ/kg.K
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