A compound with the molecular formula C7H14O exhibits the following 13C NMR spectra: Broadband-decoupled 220 200 180 160 140 120 100 80 -0 DEPT-90 220 200 180 160 140 120 100 80 DEPT-135 220 200 180 160 140 120 100 9-9 60 40 40 20 909 60 40 20 80 60 40 20 Chemical Shift (ppm) Several structures are consistent with these spectra. To determine which structure is correct, a ¹H NMR spectrum was acquired which exhibits five signals. One of those signals is a singlet at 1.9 ppm with an integration of 3, and another of the signals is a doublet at 0.9 ppm with an integration of 6. Using this information, draw the correct structure of the compound. Draw Your Solution

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter13: Nuclear Magnetic Resonance Spectroscopy
Section: Chapter Questions
Problem 13.27P: The 13C-NMR spectrum of 3-methyl-2-butanol shows signals at 17.88 (CH3), 18.16 (CH3), 20.01 (CH3),...
icon
Related questions
Question
A compound with the molecular formula C7H14O exhibits the following 13C NMR spectra:
Broadband-decoupled
220
200
180
160
140
120
100
80
-0
DEPT-90
220
200
180
160
140
120
100
80
DEPT-135
220
200
180
160
140
120
100
9-9
60
40
40
20
909
60
40
20
80
60
40
20
Chemical Shift (ppm)
Several structures are consistent with these spectra. To determine which structure is correct, a ¹H NMR spectrum was acquired which
exhibits five signals. One of those signals is a singlet at 1.9 ppm with an integration of 3, and another of the signals is a doublet at 0.9
ppm with an integration of 6. Using this information, draw the correct structure of the compound.
Draw Your Solution
Transcribed Image Text:A compound with the molecular formula C7H14O exhibits the following 13C NMR spectra: Broadband-decoupled 220 200 180 160 140 120 100 80 -0 DEPT-90 220 200 180 160 140 120 100 80 DEPT-135 220 200 180 160 140 120 100 9-9 60 40 40 20 909 60 40 20 80 60 40 20 Chemical Shift (ppm) Several structures are consistent with these spectra. To determine which structure is correct, a ¹H NMR spectrum was acquired which exhibits five signals. One of those signals is a singlet at 1.9 ppm with an integration of 3, and another of the signals is a doublet at 0.9 ppm with an integration of 6. Using this information, draw the correct structure of the compound. Draw Your Solution
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9781305580350
Author:
William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:
Cengage Learning