A female fruit fly that is heterozygous for the white-eye mutation has red-eyed sons and white-eyed sons in equal proportions: a. regardless of the genotype of the male. b. only when mated with a red-eyed male. c. only when mated with a white-eyed male. d. only when mated with a heterozygous male
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Question:-
A female fruit fly that is heterozygous for the white-eye mutation has red-eyed sons and white-eyed sons in equal proportions:
| a. |
regardless of the genotype of the male. |
|
| b. |
only when mated with a red-eyed male. |
|
| c. |
only when mated with a white-eyed male. |
|
| d. |
only when mated with a heterozygous male. |
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- 1.In Drosophila melanogaster body color is controlled by one gene while wing shape is controlled by a second gene. Gray body color is dominant to black body color, and normal wings are dominant to vestigial wings. Flies homozygous for gray body color and vestigial wings are crossed with flies homozygous for black body color and normal wings. A.compare the possible f2 generation genotypes and phenotypes and proportions if these two traits. B.How does your answer change if one of the original parents is homozygous for gray body color and normal wings while the other has black body color and vestigial wings?Deranged: is a phenotype in Drosophila in which the thoracic bristles are disarranged and the wings held vertically upward. Crosses between deranged females and normal males, each from pure stock cultures, result in a 1:1 ratio of normal females to deranged males among the progeny. What does this show? A. The gene for deranged is autosomal and dominant. B. The gene for deranged is autosomal and recessive. C. The gene for deranged is X-linked and dominant. D. The gene for deranged is X-linked and recessive. E. Deranged is determined by two genes interacting epistatically.In Drosophila melanogaster white (w) and miniature (m) wings are controlled by X-linked recessive genes with a recombination fruequency between them of approximately 38%. Show the sexes, phenotypes and proportions of offspring expected from the following mating:a. ++/wm female X wm maleb. +m/w+ female X w+ malec. w+/+m female X ++ maleIf we assume that white eyes and miniature wings are not x-linked but are linkedto the autosomal genes, what phenotypic frequencies would you expect from this cross: ++/wm female X ++/wm male?
- GENETICS: X LINKED GENES In fruit flies, eye color is a sex linked trait. Red is dominant to white. What are the sexes and eye colors of flies with the following genotypes: XRXr XRY XRXR X'Y What are the genotypes of these flies: white eyed, male red eyed female (heterozygous). red eyed, male white eyed, female Show the cross of a white eyed female X'X' with a red-eyed male XRY. Show a cross between a pure red eyed female and a white eyed male. What are the genotypes of the parents: & & Show the cross of a red eyed female (heterozygous) and a red eyed male. What are the genotypes of the parents? How many are: white eyed, male_ red eyed, male How many are: white eyed, male white eyed, female red eyed, male red eyed, female white eyed, female red eyed, femaleA mutation occurs in the bicoid gene in a female fly. What will result if her eggs are fertilized? 1.Her embryos will be normal if they are fertilized by a male fly that contributed a wild type allele for bicoid 2.Her embryos will be normal if the male that fertilizes her eggs also has that same bicoid mutation 3.All of her embryos will be disrupted irrespective of the genotype of the father 4.Her embryos will develop normally but the adults will be sterilePlease explain how you do this question step by step I am very confused! thank you:) You have three independent mutant alleles in the Drosophila gene no-antenna: nan1, nan2 and nan3. You determine the phenotype of Drosophila that are heterozygous for the three alleles (heterozygous for a wild-type allele and a mutant allele), and that are homozygous for the three mutant alleles. The antenna is composed of three segments that are followed at the distal end by a feathery arista (that is the antenna is composed of three segments and an arista). Allele nan1 nan2 nan3 heterozygous Wild-type No arista Wild-type homozygous No arista No antenna No antenna nan1 is a __x__ allele, nan2 is a __y__ allele, and nan3 is a __z__ allele. X Y Z A Dominant negative Null Hypomorphic B Null Dominant negative Hypomorphic C Null Hypomorphic Dominant negative D Hypomorphic Dominant negative Null E Dominant negative Hypomorphic Null Referencing the table above, select the…
- .Certain forms of human color blindness are inherited as X-linkedrecessive traits. Hemizygous males are color-blind, but heterozygous females are not. However, heterozygous females sometimeshave partial color blindness.A. Discuss why heterozygous females may have partial color blindness.B. Doctors identified an unusual case in which a heterozygousfemale was color-blind in her right eye but had normal colorvision in her left eye. Explain how this might have occurred.STUDY GUIDE Name a A HUMAN TRAITS In your textbook, read about color blindness in Section 27:2. 1. Color blindness is a trait carried on the sex chromosomes. Let C be normal color vision and c b red-green color blindness. Use the diagrams to answer the questions. a. What is the sex of each of these people? Write either male or female on the blank below each. XX XX X Xa XX C b. Which are red-green color blind? c. Which have normal color vision? X X XXXXX B ①① X X XXXXX M a XaXa Date a d. Which has normal color vision even with the gene for color blindness? 2. a. Complete the following Punnett squares. The first one has been done for you. b. Using these colors, shade the following parts of the Punnett squares. Blue-normal females Yellow-normal males Red-color blind females Green-color blind males X X XXXXX Class D CHAPTER 27 X X XXXXX a Xalo E X X X×××× X oooolgolma 8 X X XXXXX a X a Xa 15 15. Design a mating between a female with these three traits: purple (eye color), black (body color), and curved (wing shape), and a wild type male. a. What are the phenotypes of their offspring? + (wildtype) b. What are their genotypes? XW+ XW+ XW+ Y 9 Female PRC Source Design View QFy Flies to be Mated Phenotype Female: + Male: + Total Male Source Design View Results for Cross # 3 Observed Proportion 522 0.5113 499 1021 0.4887 1.0000 Female: PR, C, BL; N=1 8 Parents of Cross #3 Select to Mate Q Select to Mate Offspring of Cross #3 Male N-499 Female N 522 Select to Male 10 Total Male N=1 Phenotype Select to Mate Results for Cross #3 Observed Proportion 1021 1.0000 1021 1.0000
- Diagram the genotype of a female fly that is recessive for apterus (ap, chromosome 2), heterozygous wild-type for black (b, chromosome 2), recessive for forked (f, x-chromosome), and homozygous wild type for rosy (ry, chromosome 3). Diagram the genotype of a male fly that is heterozygous for clot (ct) eyes (an autosomal gene) and has yellow (y) body color (x-linked gene).✓ [Select] all 75% 50% 25% noneIn Drosophila, an X-linked recessive mutation, (s) causes irregular wing margins. Give the genotypes, phenotypes and phenotypic ratio of the F1 and F2 offspring in the following crosses a. scalloped female crossed with a normal male b. scalloped male crossed with a homozygous normal female. Compare these results to those that would be obtained if the scalloped gene is autosomal.