A tank has a hole in the bottom with a cross-sectional area of 0.0025 m2 and an inlet line on the side with a cross-sectional area of 0.0025 m², as shown in Figure 4. The cross-sectional area of the tank is 0.1 m2. The velocity of the liquid flowing out the bottom hole is V = /2gh, where h is the height of the water surface in the tank above the outlet. At a certain time, the surface level in the tank is 1 m and rising at the rate of 0.1 cm/s. The liquid is incompressible. Sketch the CV and find the velocity of the liquid through the inlet. (Vin = 4.47 m/s). A = 0.1 m? h = 1 m A = 0.0025 m? A = 0.0025 m² V= V2gh Figure 4
A tank has a hole in the bottom with a cross-sectional area of 0.0025 m2 and an inlet line on the side with a cross-sectional area of 0.0025 m², as shown in Figure 4. The cross-sectional area of the tank is 0.1 m2. The velocity of the liquid flowing out the bottom hole is V = /2gh, where h is the height of the water surface in the tank above the outlet. At a certain time, the surface level in the tank is 1 m and rising at the rate of 0.1 cm/s. The liquid is incompressible. Sketch the CV and find the velocity of the liquid through the inlet. (Vin = 4.47 m/s). A = 0.1 m? h = 1 m A = 0.0025 m? A = 0.0025 m² V= V2gh Figure 4
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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