After the extraction of benzoic acid from 0.5g impure sample, the weight of pure benzoic acid in the filter paper was 0.4g. Calculate the % impurity?
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- 4. A fat sample with combination of acids contain standard hydrochloric acid for blank and sample with 8mL and 5mL respectively. The normality of the standard hydrochloric acid is 0.93N and the weight of the sample is 3 grams. Calculate the saponification value.A K2SO4 solution is prepared by weighing out a certain amount of the pure solid reagent,dissolving it to 500.0 mL in a volumetric flask. An aliquot was taken from this solution.of 25.00 ml and diluted to 500.0 ml. An aliquot of 5.00 was taken from this new solution anddiluted to 50.00 ml. A chemical analysis of this new solution showed a 0.100%(w/v)in K+. Calculate the weight of the pure solid K2SO4 used for the preparation of the original solution.and its concentration in each volumetric flask. The answer is 2.23x10^2gTo 47.62 ml of wine were added 5 mL of concentrated KI solution and 32.11 mL of solution containing (0.7557 g KIO 3)/(100.00 mL solution). The wine+reagent mixture was acidified with 10 ml of 1 M HCI to create a known number of moles of I 2 by the reaction 10 3 + excessl + some H*-> 31 2 Some of this I 2 immediately reacted with the sulfite in the wine sample by the reaction SO 3 +12 --> products we don't care about The left over I 2 was titrated to a starch end point with 10.14 mL of 0.04521 M thiosulfate solution, by the reaction 12+ 25 20 32-> products we don't care about What is the concentration of sulfite in the wine, expressed in mM?
- A 15.00 g sample containing mixed alkali and other inert components was dissolved and diluted to 300 mL with water. A 20 ml, aliquot was titrated with 5.02 mL of 0.5352 M HCI to reach PHP endpoint. Another 20 mL aliquot was titrated to the BCG endpoint, using up 18.87 mL of titrant in the process. Identify the alkali components and their percent weight.A 5.000-g soil sample was analyzed for potassium content by extracting the potassium using 10.00 mL aqueous ammonium acetate solution. Following the extraction, the soil was filtered and rinsed. The filtrate with rinsings was diluted to exactly 50.00 mL. Then, 1.00 mL of this solution was diluted to 25.00 mL, and this dilution was tested with an instrument. The concentration in this 25.00 mL was found to be3.18 ppm. What is the concentration of the potassium in the soil in ppm?Q1: What is the density (g/ml) of a 3.6M Sulfuric acid solution that is 29% H,So, by mass (Mwt. = 98)? Q2: Fill the blanks with suitable answers 1: The is the thing being dissolved. ......... 2: The branches of quantitative analysis are and 3. The filterability of the precipitate depend on the of practices. Q3: Which one is correct? 1. Molality changes with temperatures. 2. Molality does not change with temperatures. 3. Molarity changes with temperatures. 4. Normality changes with temperatures. Q4: What weight of pyrite ore (impure FeS,) must be taken for analysis so that the BaSO, precipitate weight obtained will be equal to one-half that of the percent S in the sample? Note: Mwt. of Ba =32, Mwt. of BaSo4 =233, Mwt. of FeS, =119
- A 15.00 g sample containing mixed alkali and other inert components was dissolved and diluted to 300 mL with water. A 20 mL aliquot was titrated with 5.02 mL of 0.5352 M HCl to reach PHP endpoint. Another 20 mL aliquot was titrated to the BCG endpoint, using up 18.87 mL of titrant in the process. Note: Answer in two decimal places only. If there is no answer, type in 0.00. Use the molar masses 105.989 ?/??l ??2cO3 and 84.007 g/mol NaHCO3 indicated. The volume of titrant needed to neutralize NaOH is _________ mL.The volume of titrant needed to neutralize Na2CO3 is _____________ mL.The volume of titrant needed to neutralize NaHCO3 is _____________ mL. The mass of NaOH is ___________ g.The mass of Na2CO3 is __________ g.The mass of NaHCO3 is __________ g. The percent weight of NaOH is __________ %.The percent weight of Na2CO3 is __________ %.The percent weight of NaHCO3 is __________ %.The scatter plot below shows the density of ethylene glycol solutions vs. the mass % of those solutions. Density (g/mL) 1.04+ 1.03- 1.02- 1.01 0.99- 0.98- 8 % 10 12 14 16 18 20 Mass % Q The equation for the line of best fit shown on the scatter plot is y= 0.001683 +0.9959. Use the equation of the trendline to determine the mass percent of an ethylene glycol solution with a density of 1.015 g/mL.The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? OA. Solution A: 0.123 Solution B: 0.463 O B. Solution A: 0.463 Solution B: 0.234 O C. Solution A: 0.123 Solution B: 0.234 O D. Solution A: 0.234 Solution B: 0.463
- 25 ml of pickled brine was taken from an apple pickled with vinegar and diluted to 500 ml, 25 ml of this was taken and acidity was determined with 0.2 N (Factor: 1.05) NaOH. In the main trials, 6.3 ml - 6.5 ml - 6.9 ml, respectively, 0.1 ml base was used in the analysis without using the sample.For example, how many ppm is its acidity?The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? A. Solution A: 0.123 Solution B: 0.463 B. Solution A: 0.463 Solution B: 0.234 C. Solution A: 0.123 Solution B: 0.234 D. Solution A: 0.234 Solution B: 0.463The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with D water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. Which of the following technique can be used to determine the amount of mercury in the undiluted sample of river water? O A. IR spectroscopy O B. Cold vapor atomic absorption OC. Hydride generation atomic absorption OD. Electrothermal atomic absorption
