(b) Determine the incident densities Power electric field 1 mv/m. Electric field incident E Incident Power density Pincident Wave Incident ad incident at Region O Мо n = no = √260 छ Powen = Reflection Transmitted Preflected ETransmitted where 1) 1207 Incident Power electric field = at Esuflected 7.5 2 12₂ when. the Power Density IM₂ 8₂ N than reflected Power Density Preflected= Co. Power Denaity P E transmitted Reflected & transmittied the amplitude of incident interface is addumed 1 mu/m = DA 120x ohm. 2 0.230 0.230 mu/m = 00.265x10 W/m² 0.265 Nano w/m² [Reflection Coefficient ] x Ein = 0.230m) 2 x 120 व 7.016 x10" 0-230 Transmitted Powed Density = 1207 √& = 235062 [1-1T1] Eincident x 1 m v/m (Ereflected) 240 W/m² R 2 (E transmitted) ² 21₂ [ Eincident] 24 0.77 mulm [ & traindmitted] 24, (0.77 mulm) 2 x 235.62 1 1 milm 2 -1208 √√2.56 S then, -9 1 x 10 Nano W/m w/m

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Transmission Coefficient
Power
electric field
Electric
+
(b) Determine the incident
densities
when
Wave Incident
Reflected & transmittied
the amplitude of incident
interface is
addumed
1 mu/m
Incident Power density P₁ = [ E incident]
incident
24
the
1 mu/m. UVO
ad incident
Reflection
Transmitted
n = n₂ = 120
Мо
field incident Eincident
Preflected
Etransmitted
out
where
T
I
G
I =
7/₂
2
N
Ereflected
N
مه
2
Powen = (1)
²
1204
Incident Power
than reflected Power Density
Preflected=
n₁ =
Etransmitte
Power •Density.
at Region O
0.265 Nano W/m²
electric field = [Reflection Coefficient ]x
0.230 x 1 mu/m
0.230 mu/m
2
Power Density
1- Relection Coefficient
1 + 0.230
As
1.230
(0.230m)
120x ohm.
LM₂
8₂
2 x 120 व
7.016 x10
6
2
1- TR
IR
0 230
ra
1
0.77 mulm
Transmitted Powed Density
falar bor
120Ā
√&
= 235.62 र
[1-1T1] Einsident
24.
2
(Ereflected)
240
W/m²
(Etransmitted)
21₂
0.265x₁0W/m²
2
[ Etrandmitted] ²
(0.77 mulm)
2 x 235.62
1
2
1 mulm
2
TR
2
1२०६
√2.56
then,
2
Nano W/m
Eincider
1x109 w/m.
Transcribed Image Text:Transmission Coefficient Power electric field Electric + (b) Determine the incident densities when Wave Incident Reflected & transmittied the amplitude of incident interface is addumed 1 mu/m Incident Power density P₁ = [ E incident] incident 24 the 1 mu/m. UVO ad incident Reflection Transmitted n = n₂ = 120 Мо field incident Eincident Preflected Etransmitted out where T I G I = 7/₂ 2 N Ereflected N مه 2 Powen = (1) ² 1204 Incident Power than reflected Power Density Preflected= n₁ = Etransmitte Power •Density. at Region O 0.265 Nano W/m² electric field = [Reflection Coefficient ]x 0.230 x 1 mu/m 0.230 mu/m 2 Power Density 1- Relection Coefficient 1 + 0.230 As 1.230 (0.230m) 120x ohm. LM₂ 8₂ 2 x 120 व 7.016 x10 6 2 1- TR IR 0 230 ra 1 0.77 mulm Transmitted Powed Density falar bor 120Ā √& = 235.62 र [1-1T1] Einsident 24. 2 (Ereflected) 240 W/m² (Etransmitted) 21₂ 0.265x₁0W/m² 2 [ Etrandmitted] ² (0.77 mulm) 2 x 235.62 1 2 1 mulm 2 TR 2 1२०६ √2.56 then, 2 Nano W/m Eincider 1x109 w/m.
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