Chap 14. Interfacing to external memory 1. Interface two 16 Kbytes RAM chips (16K x 8) with the 8051. Connect the first chip starting a 4000H onwards and the second chip C000H onwards. 2. Interface 4Kbyte of ROM (2732-EPROM, 4K x8) as data memory starting at the memory location 0000H. 3. Interface 8 Kbytes of SRAM (6264) and 8 Kbytes of EEPROM (2864) with the 8051 both starting at the address 0000H.
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- If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?Q1-Design the hardware required to interface 32KB of SRAM to the demultiplexed address and data bus of the 8086 Microprocessor connected in minimum mode using 16Kx8 memory chips. Decode the memory using two method the first one is with simple NAND gate decoder the second method is Decode the memory with 3-to-8-line decoder (74138). so that it starts from physical address 00000h also for each memory chip used in your Design determines the range of physical address which can handle. 9255 hin with 9096 microprocessors to work on on YOA common bus in a computer connects 16 source registers (each register is 32 bits) and one memory unit with word size of 32 bits also. If the bus is designed using multiplexers, answer the following: • What is the minimum number of multiplexers required? What is the minimum number of select lines each multiplexer has? If the bus is designed with three-state buffers and decoders, answer the following: • What is the minimum number of three-state buffers required? • What is the minimum number of decoders required? • What is the minimum size of each decode
- A computer employs RAM chips of 512 x 4 and ROM chips of 256 x 8. The computer system needs 1KB of RAM, and 512 x 8 ROM and an interface unit with 256 registers each. A memory-mapped I/O configuration is used. The two higher -order bits of the address bus are assigned 00 for RAM, O1 for ROM, and 10 for interface. a) How many lines must be decoded for chip select? Specify the size of the decoder b) Draw a memory-address map for the system and Give the address range in hexadecimal for RAM, ROM c) Develop a chip layout for the above said specifications.Interface 4MB RAM memory with 80386SX microprocessor. Use 256Kx8 RAM ICs and 74LS138 decoder. The RAM should start at address FF900000H, Write the end of this RAM.The MSP430F20x is a microcontroller with 64 KiB of address space divided between code memory (flash), RAM memory, and input/output peripherals. It has 2,048 Bytes of RAM memory starting at the address 0x0200, and 256 Bytes of address space reserved for special purpose registers and 8-bit input/output peripherals (starting at the address 0x0000) followed by 256 Bytes reserved for 16-bit input/output peripherals. The flash memory of 16 KiB resides at the top of address space (highest addresses in the address space). C. Determine the address map by filling in the following table. Address Byte Address (hexadecimal) Sections in address space Last Flash Address Flash Memory First Flash Address Flash Memory Last RAM address RAM Memory First RAM address RAM Memory Last I/O address (16-bit per.) I/O address space First I/O address (16-bit per.) Last I/O address (8-bit per.) I/O address space First I/O address (8-bit per.) D. What is the maximum stack…
- docs.google.com/forms :D 1- I/O device informs the computer if it is ready for a transfer by using-- A- interrupt B- In and Out instructions C- wait state D- none of the above 2- A computer with memory size 128K word with 32 bits each. its instruction format has indirect bit I, REG. part to specify one of 16 registers, an opcode part OPCOD, and address part ADR. The number of bits in REG, OPCOD, and ADR respectively are: A- 4, 16, and 16 B- 4, 10, and 16 C- 4, 16, and 17 D- 4, 10, and 17 IIQuestion 4 Why must the single-cycle datapath have separate instruction and data memories? The formats of data and instructions are different in RISC-V, and hence different memories are needed. It is less expensive to have separate memories. The processor operates in one cycle and cannot use a (single-ported) memory for two different accesses within that cycle. All of the above.Reference to the following Figure (Figure 5.6 or your book), where you designed 1Mbyte memory by applied chip group enabling on 256 Kbyte. Draw a similar 2Mbyte memory. Memory address register (MAR) Al B1 ci DI Memory buffer register (MBR) 1512 1/512 Bit 1 A2 B2 All chips 512 words by 512 bits. 2-terminal cells A7 1512 B7 D7 Group Chip group enable A8 B8 C8 D8 Select 1 of 4 1512 1/512 groups E Bit 8 Figure 5.6 1-Mbyte Memory Organization ABCA 1/5 12 1/512 1/51 2||
- Course: computer architecture Design an 256Kx16 DRAM memory using 64Kx4 module. Draw the block configuration of the modules showing all required input and output signals, and size of MAR and MBR.Given the following memory chip configurations find the requested information: An EPROM chip has a capacity of 128Kbits with 8 bits of information stored at each location, what is the organization of the chip? how many address pins and data pins does the chip require? A DRAM chip has a capacity of 16Mbits and with 4 bits of information stored at each location, what is the organization of the chip? how many address pins and data pins does the chip require? For the ROM memory chip shown, find the capacity (including units): organization: is this memory volatile or non-volatile? (circle one) D7 DO A B YO A16 A17 A0 Y1 A18 Y2 b ROM G2A G2B Y3 Y4 Y5 o Y6 o Y7 o A15 A19 G1 VccVpp MEMR OE Given the ROM memory chip and decoder circuit below (the decoder used is the 74LS138) is used in a system with a 20-bit address bus, find the address range (in hex) the chip will respond to: upper CE Each Y controls one block lowerA main memory unit with a capacity of 4 megabytes is built using 1Mx 1-bit DRAM chips.Each DRAM chip has 1K rows of cells with 1K Cells in each row. The time taken for a single refresh operation is 100 nanoseconds. The time required to perform one refresh operation on all the cells in the memory unit? Earlier someone did it wrong. If you do it wrong again i will report it to Bartleby. If you dont know ,dont solve.