Create a program that finds all the prime factorials of numbers from 2 to 1000. Note: proof that all numbers above 1 have at least one prime factor. Add these to a list and print out the list at the end.
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please code in python
Forbidden concepts: recursion, custom classes
Create a program that finds all the prime factorials of numbers from 2 to
1000. Note: proof that all numbers above 1 have at least one prime factor. Add these to a list and print out the list at the end.
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- please code in python Forbidden concepts: recursion, custom classes Create a program that finds all the prime numbers between 2 to 1000. As each is found, add it to the list, then print the list in an organized fashion.Java source code writing - a recursive algorithm. Please use non-recursive and recursive ways to determine if a string s is a palindrome, that is, it is equal to its reverse. Examples of palindromes include 'racecar' and 'gohangasalamiimalasagnahog'. Turn in your java source code file with three methods, including one main() method.Lab Goal : This lab was designed to teach you more about recursion. Lab Description : Take a string and remove all occurrences of the word chicken and count how many chickens were removed. Keep in mind that removing a chicken might show a previously hidden chicken. You may find substring and indexOf useful. achickchickenen - removing the 1st chicken would leave achicken behindachicken - removing the 2nd chicken would leave a behindSample Data : itatfunitatchickenfunchchickchickenenickenchickchickfunchickenbouncetheballchickenSample Output : 01302
- In Python: Write a recursive function named Multiply2 that multiples by 2 and prints each element in a given list. For example: mylist=[1,2,3,4] Multiply2(mylist) prints: 2 4 6 8 Note: the function takes only one parameter, which is the list on which the operation will be performed. It's ok if the list becomes empty after calling the function.Complete this code Do not use any loops or regular expressions.THIS IS THE GIVEN CODE public static boolean skipSum(List<Integer> list, int sum) { // call your recursive helper method returnskipSumHelper(list, 0, sum); }private static boolean skipSumHelper(List<Integer> list, int start, int sum) { // base case // recursive step}getSumEven Method; public static int getSumEven(int[] array) Returns the sum of even values (if any) present in the array parameter. You can assume array is not null. You may only use one auxiliary function. Your implementation must be recursive and you may not use any loop construct. Do not use ++ or -- in any recursive call argument. It may lead to an infinite recursion. For example, use index + 1, instead of index++. Parameters: array - Returns: Sum of even values
- In JavaScript use recursion to find the sum of all pages in the following: function getPageTotal(list) {// your code here// returns an integer}Example test case:Input: {"book":"A","pages":50,"next":{"book":"B","pages":25,"next": null}}Output: 75Reasoning: 50 + 25 pagesWrite a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] Hint:The trick is to remove the last element each time to make the ArrayList a little shorter. import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum =…Write a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] ================================================ import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum = findMinimum(numbers);System.out.println("Minimum: " + minimum);}public static int…
- Write a recursive function named Multiply2 that multiples by 2 and prints each element in a given list. For example: mylist=[1,2,3,4] Multiply2(mylist) prints: 2 4 6 8 Note: the function takes only one parameter, which is the list on which the operation will be performed.PYTHON: This exercise is a variation on "instrumenting" the recursive Fibonacci program to better understand its behavior. Write a supporting method that counts how many times the fib function is called to compute fib (n) where n is a user input. Hint: To solve this problem, you need an accumulator variable whose value "persists" between calls to fib. You can do this by making the count an instance variable of an object. Create a FibCounter class with the following methods: _init_(self) Creates a new FibCounter, setting its count instance variable to 0. getCount(self) Returns the value of count. fib(self, n) Recursive function to compute the nth Fibonacci number. It increments the count each time it is called. resetCount(self) Sets the count back to 0.* allSame returns true if all of the elements in list have the same value. * allSame returns false if any two elements in list have different values. * The array may be empty and it may contain duplicate values. * * Your solution should contain at most one loop. You may not use recursion. * Your solution must not call any other functions. * Here are some examples (using "==" informally): * * * * * * * * true == allSame (new double[] { }) true == allSame(new double[] {11}) true == allSame (new double[] { 11, 11, 11, 11 }) false == allSame(new double[] { 11, 11, 11, 22 }) false == allSame (new double[] { 11, 11, 22, 11 }) true == allSame (new double[] { 22, 22, 22, 22 }) * */ public static boolean allSame (double[] list) { return StdRandom.bernoulli(); //TODO: fix this