D pH pH = 4.389 pH = 4.874 = pK₁ pH = 5.339 Answer Bank Using the equation to calculate the quotient [A]/[HA] at three different pH values. [A-] [HA] + log [A-] [HA] [AT] [HA] = = [A] [HA] 1 0.3273

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter21: Potentiometry
Section: Chapter Questions
Problem 21.14QAP
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pH
pH = 4.389
pH = 4.874
=
pH = 5.339
pKa
Answer Bank
Using the equation to calculate the quotient [A]/[HA] at three different pH values.
[A]
[HA]
+ log
[A-]
[HA]
[A]
[HA]
||
=
H
=
[A]
[HA]
1
0.3273
Transcribed Image Text:pH pH = 4.389 pH = 4.874 = pH = 5.339 pKa Answer Bank Using the equation to calculate the quotient [A]/[HA] at three different pH values. [A] [HA] + log [A-] [HA] [A] [HA] || = H = [A] [HA] 1 0.3273
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