DO R Oa blackboard.uob.edu.bhView AssessmentGiven below is the diagram of Process of chromatographic column'. Identify the unmarked component in the process.PumpSolventSampleColumn目目A Mobile phaseB) LampC) DetectorD) Stationanı nhaenO 97 minutes remainingE The due date for this submission has passed. New attempts will be marked as late.Last saved 2:51:32 PMSave and CloseSubmit LateOO O O

The unmarked component is detector. It is placed at the bottom of the column. It responds to solute…

DO R O a blackboard.uob.edu.bh View Assessment Given below is the diagram of Process of chromatographic column'. Identify the unmarked component in the process. Pump Solvent Sample Column A) Mobile phase B) Lamp C) Detector D) Stationanı nhaen O 97 minutes remaining E The due date for this submission has passed. New attempts will be marked as late. Last saved 2:51:32 PM Save and Close Submit Late OO O O

DO R O a blackboard.uob.edu.bh View Assessment Given below is the diagram of Process of chromatographic column'. Identify the unmarked component in the process. Pump Solvent Sample Column A) Mobile phase B) Lamp C) Detector D) Stationanı nhaen O 97 minutes remaining E The due date for this submission has passed. New attempts will be marked as late. Last saved 2:51:32 PM Save and Close Submit Late OO O O

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter31: Introduction To Analytical Separations

Section: Chapter Questions

Problem 31.24QAP

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Similar questions

cont irmation True or false: The purpose of the internal standard is to make quantitation of the analyte insensitive to injection errors
A new method is proposed to simultaneously detectand separatefour foodadditives by reversed-phase liquid chromatography. The data were obtained using theliquid chromatographic column with a flow rate of 0.5 mL per min and with the followingparameters: Pore size 100 A Particle Size 3.5 Internal diameter 4.6 mm Length 150 mm The food additives found in the sample resulted in the following data: ( see image for table) a.Calculate the number of plates from each peak. b.Calculate the plate height for the column. c.Retention factor for each peak.
The method of internal standard was used to analyze and measure the concentration of chemical X by GC A known mixture of compounds X and Y (internal standard) gave the following chromatographic results: Compound X Y a) 2.0 x 106 M b) 8.4 x 10-7 M c) 6.6 x 10-7 M Concentration (M) 6.3 x 10-8 2.0 x 10-7 d) 4.1 x 10-7 M e) 2.9 x 10-7 M Peak Area Then, an unknown was analyzed as follows. 3.0 mL of unknown X was treated with 0.100 mL of 1.6 x 10-5 MY and the mixture diluted to 10.0 mL final volume. Peak areas were 633 (for X) and 520 (for Y). What is the concentration of X in the unknown. (The original 3.00 sample?) 395 787
The internal standard method compensates for errors that affect both the analyte and the reference. True False
i need clear ans and solve very very fast in 20 min and thank you | DYBALA # what is the SA of a liquid sample of 103 m³ containing 10-6 Kg of ³2P? t2 = 14.3 d, (0.285 ci/m³) 32p?
4.Consider the peaks for pentafluorobenzene and benzene in the gas chromatogram shown here. The elution time for unretained solute is 1.06 min. The open tubular column is 30.0 m in length and 0.530 mm in diameter, with a layer of stationary phase 3.0 μm thick on the inner wall. a) Measruing the width, w, at the baseline on the chromatogram, find the number of plates for these two compounds b) Use your answer to (a) to find the resolution between the two peaks c) Using the number of plates N=sqrtN1*N2 with the values from (a) calcuate what the resolution should be and compare your answer with the measured resolution in b
The data in the following table were extracted from a gas chromatographic analysis of a two- component mixture. Air nonane decane Retention time (s) 5 26 32 Peak width, baseline (s) 5 4 (i) Calculate the capacity factor, k, for the two compounds. (ii) Calculate the selectivity factor, a, for the two compounds.
the efficiency of a chromatographic column improves the measure thata.increases the height of the theoretical dishesb.decreases the number of theoretical platesc.platform height is reducedd.None of the above Please explain it Provide clear handwriting and clear image
5. Using the diagram answer the questions below: Increasing time Sample applied p to top of column Column fow (a) eluent eluent eluent eluent (A) Draw a sketch of the expected chromatrogram (peaks, broadening, relative elution times, etc.) (B) Explain the term "analyte dilution" using the diagram as a reference.
A 0.0200 gram blood sample was decomposed by a microwave digestion technique followed by dilution to 100.0 mL in a volumetric flask. Aliquots of the sample solution were treated with a lead complexing reagent and water as follows: Solution 1: 10.0 ml blood sample + 20.0 mL complexing agent + 30.0 mL H20. Solution 2: 10.0 ml blood sample + 20.0 mL complexing agent + 26.0 mL H20 + 4.00 mL of 78 ppb Pb2+ standard. The resulting solutions were analyzed by UV/Vis at 375 nm. Absorbance for solution 1 = 0.155 and for solution 2 = 0.216. Calculate the concentration of lead (ppb) in the original sample.
(2) A CHEM 215 student performed 5 measurements of the wt% of SO4²- of a solid power sample. The results are 8.75%, 8.85%, 8.89%, 8.71%, 8.64%. The standard deviation is 0.10%. What is the confidence interval for this student's experiment at 95% confidence level. The t values for 95% confidence for degree of freedom from 1 to 5 are 12.71, 4.303, 3.182, 2.776, 2.571, respectively. Show your work!
2 (1) When performing chemical measurements, replicate experiments are often needed. This is to mitigate (Systematic or Random) error. (2) A CHEM 215 student performed 5 measurements of the wt% of SO4²- of a solid power sample. The results are 8.75%, 8.85%, 8.89%, 8.71%, 8.64%. The standard deviation is 0.10%. What is the confidence interval for this student's experiment at 95% confidence level. The t values for 95% confidence for degree of freedom from 1 to 5 are 12.71, 4.303, 3.182, 2.776, 2.571, respectively. Show your work!