For numbers 34-50. Given the following pedigree, answer the following questions.1st generation would be the grandparents, 2" generation would be the children of the grandparentsand the 3" generation would be the children of the 2"generation.Trait that would be track is autosomal dominant and recessive.Cleft chin (CC or Ce) = DominantNo cleft chin (ce) = RecessiveII1034-37. What is the expected Genotype of the grandfather?A. CCВ. СеС. сеD. Either A or B38-41. What is the expected genotype of number 4 given the following genes in the 1st generationA. CCВ. СеC. Either A or BD. Neither A nor 842-45. Who are the persons failed to inherit cleft chin from the grand mother?A. Number 5, 1, 8,9 and 7B. Number 2, 9, 7, 10 and 3C. Number 2, 5, 7, and 9D. Number 1, 3 and 10E. Nurmber 2 and 547-50. If number 10 married a person without a cleft chin and all the off-springs have cleft chin, what isthe genotype of number 10?A CВ. СсС. ссD. Either A nor B

Name: For numbers 34-50. Given the following pedigree, answer the following
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Description: For numbers 34-50. Given the following pedigree, answer the following questions.1st generation would be the grandparents, 2" generation would be the children of the grandparentsand the 3" generation would be the children of the 2"generation.Trait th

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For numbers 34-50. Given the following pedigree, answer the following questions. 1st generation would be the grandparents, 2" generation would be the children of the grandparents and the 3" generation would be the children of the 2"generation. Trait that would be track is autosomal dominant and recessive. Cleft chin (CC or Ce) = Dominant No cleft chin (ce) = Recessive II 10 34-37. What is the expected Genotype of the grandfather? А. СС В. Се C. cc D. Either A or B 38-41. What is the expected genotype of number 4 given the following genes in the 1st generation A. CC В. Се C Either A or 8 D. Neither A nor 8 42-45. Who are the persons failed to inherit cleft chin from the grand mother? A. Number 5, 1, 8,9 and 7 B. Number 2, 9, 7, 10 and 3 C. Number 2, 5, 7, and 9 D. Number 1, 3 and 10 E. Number 2 and 5 47-50. If number 10 married a person without a cleft chin and all the off-springs have cleft chin, what is the genotype of number 10? A C В. Сс С. сс D. Either A nor B

For numbers 34-50. Given the following pedigree, answer the following questions. 1st generation would be the grandparents, 2" generation would be the children of the grandparents and the 3" generation would be the children of the 2"generation. Trait that would be track is autosomal dominant and recessive. Cleft chin (CC or Ce) = Dominant No cleft chin (ce) = Recessive II 10 34-37. What is the expected Genotype of the grandfather? А. СС В. Се C. cc D. Either A or B 38-41. What is the expected genotype of number 4 given the following genes in the 1st generation A. CC В. Се C Either A or 8 D. Neither A nor 8 42-45. Who are the persons failed to inherit cleft chin from the grand mother? A. Number 5, 1, 8,9 and 7 B. Number 2, 9, 7, 10 and 3 C. Number 2, 5, 7, and 9 D. Number 1, 3 and 10 E. Number 2 and 5 47-50. If number 10 married a person without a cleft chin and all the off-springs have cleft chin, what is the genotype of number 10? A C В. Сс С. сс D. Either A nor B

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter12: Genes And Cancer

Section: Chapter Questions

Problem 2CS: Mike was referred for genetic counseling because he was concerned about his extensive family history...

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A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?
A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?
Mike was referred for genetic counseling because he was concerned about his extensive family history of colon cancer. That family history was highly suggestive of hereditary nonpolyposis colon cancer (HNPCC). This predisposition is inherited as an autosomal dominant trait, and those who carry the mutant allele have a 75% chance of developing colon cancer by age 65. Mike was counseled about the inheritance of this condition, the associated cancers, and the possibility of genetic testing (on an affected family member). Mikes aunt elected to be tested for one of the genes that may be altered in this condition and discovered that she did have an altered MSH2 gene. Other family members are in the process of being tested for this mutation. Once a family member is tested for the mutant allele, is it hard for other family members to remain unaware of their own fate, even if they did not want this information? How could family dynamics help or hurt this situation?
Mike was referred for genetic counseling because he was concerned about his extensive family history of colon cancer. That family history was highly suggestive of hereditary nonpolyposis colon cancer (HNPCC). This predisposition is inherited as an autosomal dominant trait, and those who carry the mutant allele have a 75% chance of developing colon cancer by age 65. Mike was counseled about the inheritance of this condition, the associated cancers, and the possibility of genetic testing (on an affected family member). Mikes aunt elected to be tested for one of the genes that may be altered in this condition and discovered that she did have an altered MSH2 gene. Other family members are in the process of being tested for this mutation. Is colon cancer treatable? What are the common treatments, and how effective are they?
Mike was referred for genetic counseling because he was concerned about his extensive family history of colon cancer. That family history was highly suggestive of hereditary nonpolyposis colon cancer (HNPCC). This predisposition is inherited as an autosomal dominant trait, and those who carry the mutant allele have a 75% chance of developing colon cancer by age 65. Mike was counseled about the inheritance of this condition, the associated cancers, and the possibility of genetic testing (on an affected family member). Mikes aunt elected to be tested for one of the genes that may be altered in this condition and discovered that she did have an altered MSH2 gene. Other family members are in the process of being tested for this mutation. Seventy-five percent of people who carry the mutant allele will get colon cancer by age 65. This is an example of incomplete penetrance. What could cause this?
For numbers 34-50. Given the following pedigree, answer the following questions. 1st generation would be the grandparents, 2" generation would be the children of the grandparents and the 3" generation would be the children of the 2" generation. Trait that would be track is autosomal dominant and recessive. Cleft chin (CC or Ce) = Dominant No cleft chin (cc) = Recessive II II 10 42-45. Who are the persons failed to inherit cleft chin from the grand mother? A. Number 5, 1, 8,9 and 7 B. Number 2, 9, 7, 10 and 3 C. Number 2, 5, 7, and 9 D. Number 1, 3 and 10 E. Number 2 and 5
zto.mheducation.com/ext/map/index.html?_con%=con&external_browser=0&launchUrl=https%253A%252F%252Flms.mheducation.com%252Fmghmiddleware? er 10 Assignment Saved Classify the following conditions based on whether they are describing autosomal dominance, autosomal recessive, or both. Autosomal Dominant Affected children can have unaffected pped parents Book Print Heterozygotes are affected erences Autosomal Recessive Heterozygotes have a normal phenotype Both males and females are affected with equal frequency Both Affected children have at least one affected parent 080 acer -> %24 % 2. 6.
2/7 - <. Hair texture is an incompletely dominant trait in humans. The three phenotypes are curly, wavy and straight. Straight only occurs when both parents have straight hair. Curly hair also tends to follow this pattern. Only two wavy haired parents produce all three phenotypes. Please explain this observation using punnett squares. Curly x Curly straight x straight Wavy x wavy
Directions: Use the following information to answer the questions below: all are sex-linked recessive disorders. H= normal blood clotting C=Normal Vision h-hemophilia muscular dystrophy M= Normal c= colorblind 1. Write the genotypes for the following individuals: a. female with no family history of hemophilia b. male with hemophilia c. male with muscular dystrophy d. male with normal color vision e. normal color vision female with colorblind father f. male with normal blood clotting g. colorblind male m= 2. Cross a female who is a carrier of the gene for hemophilia with a man who has normal blood clotting. Tell the expected phenotypic ratio of the offspring. 3. Cross a female with normal color vision, but whose father was colorblind, with a man who has colorblindness. Tell the expected phenotypic ratio of the offspring. 4. Cross a woman who does not suffer from muscular dystrophy and has no family history of muscular dystrophy with a man who has the disorder. Tell the expected…
SUBJECT: GENETICS Topic: Probability 1. Consider albinism a trait to occur in a human family. If two parents areheterozygous for such trait, the probability of having a normally pigmented child is 3//4 and having an albino child is ¼. What is the probability that 2 will be normal and 1 will be albino?
I. ACTIVITIES AND EXERCISES-Let's Try Thesef () Solve for the following completely by following the step by step process in solving for Punnett Squares. Place your answers on the corresponding blanks. White skin tone is incompletely dominant with Dark Skin tone. A heterozygous skin tone allele will form Tan colored skin. What is/are the possible phenotype/s of the children from a white skin toned man and a tan skin toned woman? Traits: White Phenotype/s: Dark => Tan == Test Cross: Punnett Square 14) 2) 3) 8) 9) 5) 10) 12) 7) 11) Teacher: 13)