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- The allele for freckles (F) is dominant to the allele for no freckles (f). A freckled man and an unfreckled woman have two children, a boy with freckles and a girl without freckles. What are the genotypes for all four? Question 6 options: Mom: XfXf, Dad: XY, boy: ff, girl: ff Mom: ff, Dad: FF, boy: Ff, girl: ff Mom: ff, Dad: Ff, boy: Ff, girl: ff Mom: ff, Dad: FF, boy: Ff, girl: FFDonald who is heterozygous B in blood type married Wendy who is a heterozygous A in blood type. What is the percentage of having a child with blood type A? B? AB? 0? What is the genotypic and phenotypic ratio? Traits: Test Cross: Heterozygous B = Heterozygous A = 32)_ Punnett Square 36) 37). 30) 31) X Percentage of A Blood type Offspring: Percentage of B Blood type Offspring: Percentage of A Blood type Offspring: Percentage of AB Blood type Offspring: 33) 34) 38) 40) 42) 43). 44) 45) 35). 39) 41)The allele for hitchhiker’s thumb (h) is recessive to straight thumb (H). If a man and his wife are both homozygous recessive, will any of their offspring potentially have hitchhikers thumb? What is the man’s genotype and the woman’s genotype? What is the man’s phenotype and the woman’s phenotype? What genotype(s) must the offspring have in order to have the phenotypic trait of hitchhiker’s thumb? Do a cross to determine all potential hitchhiker’s thumb genotypes and phenotypes for the offspring of this man and woman. Is it possible for any offspring of the F1 generation to have hitchhiker’s thumb?
- "A couple wants to have 6 children. The mother is heterozygous for the sex-linked recessive trait for colorblindness, and the father is colorblind. What is the probability that AT LEAST three of the six children will be colorblind?"In man, there is gradation in eye color and resulting to 9 phenotypes. These are (in order of the number of additive alleles): light blue, medium blue, dark blue, gray, green, hazel, light brown, medium brown, dark brown. Mr. A (dark brown eyes) and Mrs. A’s (light blue eyes) daughter, marries a man whose genotype is the same as herself. What is the probability that they could have: Dark brown eyed child? Hazel-eyed? What eye color is most likely to occur and what is its probability?Cystic fibrosis (CF) is an autosomal recessive trait. A three-generation pedigree is shown below for a family that carries the mutant allele for cystic fibrosis. Note that carriers are not colored in to allow you to figure out their genotypes. Normal allele = F CF mutant allele = f What is the genotype of individual #8?
- A polygenic trait has three loci. How many dominant alleles will the offspring of Eduardo (AABBCC) and Katje (aaBBcc) have?Dimples (D) are a dominant trait genetic trait. Complete a Punnett Square to determine the possible phenotypes and genotypes of a cross between a man who is homozygous dominant and a heterozygous woman. Choose the percentages correctly below. Dimples: 0% 25% 50% 75% 100% No dimples: 0% 25% 50% 75% 100% DD: 0% 25% 50% 75% 100% Dd: 0% 25% 50% 75% 100% dd: 0% 25% 50% 75% 100%Which of the following probabilities is correct (according to Mendel's law of independent assortment) regarding a mating of an Ss RR individual to an individual who is Ss Rr? (A – indicates the second allele is either dominant or recessive. A) Homozygous recessive: 10% B) Heterozygous both alleles: 50% C) ss R– : 15.5% D) S– RR: 37.5%
- A couple is going to have a baby. They are concerned about sickle cell anemia, which results from having the homozygous recessive combination of the sickle cell gene ("s"), which produces abnormal hemoglobin. Having at least one normal version of the gene ("S") results in normal hemoglobin. The woman is heterozygous, and so is the man. What alleles does mom have? What alleles does dad have?Pretending that Park shin-hye is heterozygous for A blood type marries Choi Tae-joon whose blood type is O. Show the possible blood types of their future children. 1. P1: 2. Punnett Square: 3. Genotype symbols: 4. Genotype in words: 5. Genotypic ratio: 6. Genotypic %: 7. Phenotype symbols: 8. Phenotype in words: 9. Phenotypic ratio: 10. Phenotypic %:Consider an animal with genotype F/f. The possible gametes produced by this individual may be ½ F and ½ f. Choose the correct answer below. The explanation for the possible gametes produced is Mendel’s first law, of equal segregation. The explanation for the possible gametes produced is Mendel’s second law, of independent assortment. The explanation for the possible gametes produced is BOTH Mendel’s first law, of equal segregation AND Mendel’s second law, of independent assortment. The explanation for the possible gametes produced is NEITHER Mendel’s first law, of equal segregation NOR Mendel’s second law, of independent assortment.