If you were to monitor the reaction mechanism for the hydroboration by TLC (Thin Layer Chromatography), would you expect the starting material (1-octene) or the product (1-octanol) to have a lower Rf? Please explain your answer, being sure to mention important intermolecular forces. Why does the hydroboration part of the reaction have to be performed in anhydrous conditions?
If you were to monitor the reaction mechanism for the hydroboration by TLC (Thin Layer Chromatography), would you expect the starting material (1-octene) or the product (1-octanol) to have a lower Rf? Please explain your answer, being sure to mention important intermolecular forces. Why does the hydroboration part of the reaction have to be performed in anhydrous conditions?
Chapter20: Nucleophilic Substitution Reactions: Competing Nucleophiles
Section: Chapter Questions
Problem 9Q
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