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In the window below, draw the form of the alkyne that will predominate at equlllb CH3 CH, CH, C=CH NaOCH, CH3 = ?+Conjugate acid of the base pka pK Acid Acid CH; CH3 51 H20 15.7 NH3 CH3 NH3 + 38 10.64 H2 35 H2CO3 10.33 HC=CH 25 +NH, 9.24 CH3 CH2 OH 15.9 H30+ -1.74 • Do not include counter-ions, e.g., Na, I, in your answer.

In the window below, draw the form of the alkyne that will predominate at equlllb CH3 CH, CH, C=CH NaOCH, CH3 = ?+Conjugate acid of the base pka pK Acid Acid CH; CH3 51 H20 15.7 NH3 CH3 NH3 + 38 10.64 H2 35 H2CO3 10.33 HC=CH 25 +NH, 9.24 CH3 CH2 OH 15.9 H30+ -1.74 • Do not include counter-ions, e.g., Na, I, in your answer.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In the window below, draw the form of the alkyne that will predominate at equll CH3 CH, CH, C=CH + NaOCH, CH3 ? + Conjugate acid of the base Acid pKa Acid pK CH3 CH3 51 H2O 15.7 NH3 38 CH3 NH3+ 10.64 H2 35 H2CO3 10.33 HC=CH +NH4 25 9.24 CH3 CH2 OH 15.9 H30+ -1.74 • Do not include counter-ions, e.g., Na", I, in your answer. | の
Transcribed Image Text:In the window below, draw the form of the alkyne that will predominate at equll CH3 CH, CH, C=CH + NaOCH, CH3 ? + Conjugate acid of the base Acid pKa Acid pK CH3 CH3 51 H2O 15.7 NH3 38 CH3 NH3+ 10.64 H2 35 H2CO3 10.33 HC=CH +NH4 25 9.24 CH3 CH2 OH 15.9 H30+ -1.74 • Do not include counter-ions, e.g., Na", I, in your answer. | の
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