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N # 2 1.5 1 y 0.5 ++ + 2 1.5 1 0.5 425 -0.5 -1 -1.5 -2 0.5 1 15 -2 (x, y, z) = (cos z, sin z, z), − < z < Explanation: Step 1: y = x tan(z) with: x>0, x²+ y² = 1 −√ < ± < √ Step 2: sin(z) y = x cos(2) Step 3: substitute y: x²+x2. sin². cos2 Then we get: = 2 . (cos's+sin= 2) Hence we would get: x² = cos² z Step 4: Since x0, cos z> 0 We would get: x = COS z 1 sin(z) y = cos z. == sin z cos(2) Hence the parametric form is: (x, y, z) = (cos z, sin z, z), — √ <≤ z <

N # 2 1.5 1 y 0.5 ++ + 2 1.5 1 0.5 425 -0.5 -1 -1.5 -2 0.5 1 15 -2 (x, y, z) = (cos z, sin z, z), − < z < Explanation: Step 1: y = x tan(z) with: x>0, x²+ y² = 1 −√ < ± < √ Step 2: sin(z) y = x cos(2) Step 3: substitute y: x²+x2. sin². cos2 Then we get: = 2 . (cos's+sin= 2) Hence we would get: x² = cos² z Step 4: Since x0, cos z> 0 We would get: x = COS z 1 sin(z) y = cos z. == sin z cos(2) Hence the parametric form is: (x, y, z) = (cos z, sin z, z), — √ <≤ z <

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.4: Fractional Expressions
Problem 68E
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Continuing with this problem, shown in the picture, where the parameterization for S was determined, how do i now calculate the area/surface of S. Could you help set up the integral for this equation? 

N # 2 1.5 1 y 0.5 ++ + 2 1.5 1 0.5 425 -0.5 -1 -1.5 -2 0.5 1 15 -2
Transcribed Image Text:N # 2 1.5 1 y 0.5 ++ + 2 1.5 1 0.5 425 -0.5 -1 -1.5 -2 0.5 1 15 -2
(x, y, z) = (cos z, sin z, z), − < z < Explanation: Step 1: y = x tan(z) with: x>0, x²+ y² = 1 −√ < ± < √ Step 2: sin(z) y = x cos(2) Step 3: substitute y: x²+x2. sin². cos2 Then we get: = 2 . (cos's+sin= 2) Hence we would get: x² = cos² z Step 4: Since x0, cos z> 0 We would get: x = COS z 1 sin(z) y = cos z. == sin z cos(2) Hence the parametric form is: (x, y, z) = (cos z, sin z, z), — √ <≤ z <
Transcribed Image Text:(x, y, z) = (cos z, sin z, z), − < z < Explanation: Step 1: y = x tan(z) with: x>0, x²+ y² = 1 −√ < ± < √ Step 2: sin(z) y = x cos(2) Step 3: substitute y: x²+x2. sin². cos2 Then we get: = 2 . (cos's+sin= 2) Hence we would get: x² = cos² z Step 4: Since x0, cos z> 0 We would get: x = COS z 1 sin(z) y = cos z. == sin z cos(2) Hence the parametric form is: (x, y, z) = (cos z, sin z, z), — √ <≤ z <
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