Answered: ½ O₂ + 2H+ +2 e → H₂O FAD + 2H+ + 2e →… | bartleby

Principles Of Pharmacology Med Assist

Principles Of Pharmacology Med Assist

6th Edition

ISBN:9781337512442

Author:RICE

Publisher:RICE

Chapter1: Numerals And Fractions

Section: Chapter Questions

Problem 5RP

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½ O₂ + 2H+ +2 e → H₂O
FAD + 2H+ + 2e → FADH₂
E'º = 0.816V
E'º = -0.219V
Calculate the AG" of the following reaction:
FAD + H₂O → FADH₂ + 1/2 0₂.
A. -200 kJ/mol
B. -100 kJ/mol
C.
50 kJ/mol
D.
100 kJ/mol
E. 200 kJ/mol

Which of the following statements are CORRECT?
I. Enzymes catalyses reactions by lowering the activation energy
II. Enzymes increases K'e of the chemical reaction
III. Enzymes bind the transition state more stronger than the substrate
Reversible enzyme inhibitors compete with the substrate for the same active site
IV.
A. I and II
B. II and III
C. I, II and III
D. I, III and IV
E. All of them
O

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