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- /*LCA of Binary TreeSend FeedbackGiven a binary tree and data of two nodes, find 'LCA' (Lowest Common Ancestor) of the given two nodes in the binary tree.LCALCA of two nodes A and B is the lowest or deepest node which has both A and B as its descendants. Example: In this example, the green coloured node is the LCA to A and B.Alt TextNote:It is defined that each node is a descendant to itself, so, if there are two nodes X and Y and X has a direct connection from Y, then Y is the lowest common ancestor. Example:Alt TextNote: 1. If out of 2 nodes only one node is present, return that node. 2. If both are not present, return -1.Input format: The first line of input contains data of the nodes of the tree in level order form. The data of the nodes of the tree is separated by space. If any node does not have left or right child, take -1 in its place. Since -1 is used as an indication whether the left or right nodes exist, therefore, it will not be a part of the data of any node. The following…7. What will be the resulting B- Trees (2-3 trees) for the following items? a. Insert 112 47 15 86 96 b. Insert 1 59 23 27 86 c. Delete 73 62 20 73 d. Delete 31 67 31 79 95Insert elements 41, 38, 31, 12, 11, 50, 55 and 22 (one by one) into an original empty BST tree. Below are a number of statements about the resulting tree. Indicate which of these is correct: A. The sequence of the elements according to "in order" is 11, 12, 22, 31, 38, 41, 50, 55 B. The sequence of the elements according to "preorder" is 41, 38, 31, 12, 11, 22, 50, 55 C. The sequence of the elements according to "preorder" is 11, 22, 12, 31, 38, 55, 50, 41 D. The sequence of the elements according to "mail order" is 11, 22, 12, 31, 38, 55, 50, 41 Correct answer is: Only statement A is correct. Only statements A and D are correct. Only statements A and C are correct. Only statements A, B and D are correct. Only statements A, C and D are correct.
- Given the preorder and inorder traversals of a binary tree, you build that binary tree. 5. Preorder: X В G Y E Inorder: Y G В D E NPLease help. Java Yatin is playing PUBG and he has reached a place with a large staircase in front of him.And there is an enemy at each landing of the staircase.This is not the actual staircase. He is looking at the staircase from sideways.The staircase is analogous to a binary tree with each of its nodes as a landing of thestaircase and each of its edges as stairs from one landing to another.Yatin wants to kill the maximum possible number of enemies. He can kill every personhe can see from his position with his suppressed sniper gun. But he can see only thepersons at the leftmost standing at each level and cannot see the rest.Before starting shooting them, he wants to know how many persons he can kill. He isbusy keeping an eye on the enemies. So he wants you to find out the maximum numberof people he can kill from that location by providing you with the analogous a binarysearch tree.[ Note: Players do not change their position after one player has died, i.e. the leftmostnode remains…int doo(node*root){ if(root !=0 ) { if(root->left==0 && root->right=D3D0) return root->data; int L=doo(root->left); int R=doo(root->right); if(L>R) return R; else return L;} } this code used for a. find the sum of leaves items in a binary tree b. the maximum item in the leaves of a binary tree c. find the minimum item in the leaves of a binary tree O d. find the minimum item in a binary tree
- int doo(node*root){ if(root !=0 ) { if(root->left==0 && root->right==0) return root->data; return doo(root->right); } } this code used for O a. find the first right item in the binary tree if it has a right sub tree O b. find the maximum item in a binary tree if it has a right sub tree O c. find the number of right leaves in a binary tree if it has a right sub tree O d. find the maximum item in a binary search tree if it has a right sub treeWrite the following string with your information: string=”your fullName 19-arid-yourNo” //e.g. GhaziMessam19-arid-1121 //consider & use space after each word Now draw a Huffman tree and generate codes.void doo(node<int>*root){ if(root !=0) { node<int>*p=root; while(root->next!=0) root=root->next; p->data=root->data; } What is this code do? a. doesn't do anything because the root parameter is passed by value b. change the root item in the binary tree with the farthest leaf item c. set the first item in the linked list as the last item d. swap the first item with the last item in the linked list
- void F(node<int>&*root){if(root!=0){F(root->left); F(root->right); root->data=0; delete root;}root=0;} this code Select one: a. free the binary tree and returns it empty b. Set all data items in the binary tree to 0 c. remove all items in the binary tree without changing its size d. all of themvoid F(node<int>&*root){if(root!=0){F(root->left); F(root->right); root->data=0; delete root;}root=0;} this code Select one: a. all of them b. Set all data items in the binary tree to 0 c. free the binary tree and returns it empty d. remove all items in the binary tree without changing its sizeQ20. * In the following array representation of the Binary tree, the degree of node C is: Tree ABC 0 1 2 3 4 5 6 7 EF O 1 3 O None of them