ou take a representative soil sample back to your home laboratory and determine the following data: Exchangeable cation cmolc/kg of soil Ca2+ 2.7 Mg2+ 1.0 K+ 0.1 H+ 1.0 Al3+ 2.8 Na+ 0.1 1) How many lbs of aluminum (Al3+) would there be in one acre furrow slice of this soil? Given: 1 AFS soil = 2,000,000 lbs; 1 lb. = 454 g; 1 kg = 2.2 lbs.

ou take a representative soil sample back to your home laboratory and determine the following data: Exchangeable cation cmolc/kg of soil Ca2+ 2.7 Mg2+ 1.0 K+ 0.1 H+ 1.0 Al3+ 2.8 Na+ 0.1 1) How many lbs of aluminum (Al3+) would there be in one acre furrow slice of this soil? Given: 1 AFS soil = 2,000,000 lbs; 1 lb. = 454 g; 1 kg = 2.2 lbs.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter4: Plasticity And Structure Of Soil

Section: Chapter Questions

Problem 4.6P: Refer to the soil in Problem 4.5. Using the Casagrande plasticity chart, graphically estimate the...

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Refer to the soil in Problem 4.5. Using the Casagrande plasticity chart, graphically estimate the shrinkage limit of the soil as shown in Figure 4.22. 4.5 The following data were obtained by conducting liquid limit and plastic limit tests on a soil collected from the site. Liquid limit tests: Plastic limit test: PL = 19.3% a. Draw the flow curve and determine the liquid limit. b. Using the Casagrande plasticity chart (Figure 4.21), determine the soil type.
The properties of seven different clayey soils are shown below. Investigate the relationship between the strength and plasticity characteristics by performing the following tasks: Soil Beauharnois Detroit I Horten Gosport Mexico City Shellhaven St. Thuribe Mineral % Clay fraction (<2 μm) Kaolinite Illite 79 36 40 55 90 41 36 Montmorillonite Halloysite (hydrated) Halloysite (dehydrated) Attapulgite Allophane Activity, A 0.52 0.36 0.42 0.89 4.5 1.33 0.33 Liquid limit, LL 35-100 60-120 100-900 Undisturbed shear strength (kN/m²) 50-70 40-55 150-250 200-250 18 17 41 29 46 36 38 a. Estimate the plasticity index for each soil using Skempton's definition of activity. b. Estimate the probable mineral composition of the clay soils based on plasticity index and activity using the table below. Plastic limit, PL 20-40 35-60 50-100 Sensitivity, S, 14 40-60 30-45 100-125 120-150 2.5 17 2.2 5.3 7.6 150 Activity, A 0.3-0.5 0.5-1.2 1.5-7.0 0.1-0.2 0.4-0.6 0.4-1.3 0.4-1.3 c. Sensitivity refers to the…
Q3 No. 200 sieve 100 80 - D40 - Soil A 60 Soil B Figure 5.9 gives the grain-size distribution of two soils. The liquid and plastic limits 40 of minus No. 40 sieve fraction of the soil are as follows: Dyo – Soil A Soil B 20 D10 Liquid limit Plastic limit 30 26 22 20 1.0 0.1 0.1 0.01 0.001 Particle diameter (mm) - log scale Determine the group symbols and group names according to the Unified Soil Classification System. Figure 5.9 Particle-size distribution of two soils You can use the following charts: Table 5.2 Unified Soil Classification System (Based on Material Passing 76.2-mm Sieve) Group symbol Criteria for assigning group symbols Gravels More than 50% of coarse fraction Gravels with Fines C, 2 4 and Is C, 3 PI 7 and plots on or above "A" line (Figure 5.3) GM GC More than 50% of sieve retained on No. 200 sieve Sands 50% or more of Less than 5% fines C, 2 6 and Is C,= 3° C, 3° SW SP Clean Sands coarse fraction Sands with Fines PI7 and plots on or above "A" line (Figure 5.3) SM SC…
2.67 A sample of soil was tested in the laboratory and the following grain-size analysis results were obtained: Sieve No. Sieve Opening (mm) Percent Coarser by Weight 4 10 20 40 60 100 200 Pan 4.75 2.00 0.85 0.425 0.25 0.15 0.075 37 52 64 69 71 77 90 100 LL = 60, PL = 26 Classify this soil according to the USCS, providing the group symbol for it.
U B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30 = 0.35 mm D₁0 = 70 μm L.L = 36% P.L = 31% D8 = 2 µm 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if we = 26%.
I need just the answer of (d) The following data were recorded during a shrinkage limit test on the sample from the soil: • Initial volume of soil in a saturated state = 20.6 cm3 • Final volume of soil in a dry state = 13.8 cm3 • Initial mass in a saturated state = 47.5 g • Final mass in a dry state = 34.6 g (i) Determine the shrinkage limit of the soil sample. (ii) Determine the shrinkage ratio.
PLS. ANSWER ASAP WITH COMPLETE SOLUTION4 DECIMAL PLACES A saturated sample of clay with a shrinkage limit of 22 has a natural water content of 35%.a. What would its dry volume be as a percentage of its original volume if the specific gravity of soil solids is 2.70?b. What would be the void ratio of the soil in its natural water content?c. What is the dry density of the soil sample?
% Finer • Particle size analyses were carried out on two soils-Soil A and Soil B-and the particle size distribution curves are shown in Figure 100 90 80 70 60 50 40 30 Clay 20 10 0 0.001 + Silt 0.01 Soil A Sand Soil B 0.1 1 Particle size (mm) - log scale Gravel 10 Soil A LL 26 (oven-dried; assume same for not dried) B Nonplastic 1. Which of the two soils, in your opinion, is a better material for the core of a rolled earth dam? PL 18
Sr B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30=0.35 mm D₁0 = 70 μm D8=2 μm L.L = 36% P.L = 31% 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if wc = 26%.
Cohesive soil is known as fine soil while cohesionless soil is known as course soil. Thesematerials are important to be identified for its parameters and classified accordingly ingeotechnical engineering design. Hence, explain briefly about the condition of permeabilityand porosity in both cohesive and cohesionless soils. Based on the laboratory testing on a sandy soil, the following values are obtained:Volume = 0.78 m3Moist mass = 1755 kgDry mass = 1432 kgSpecific gravity of soil solids = 2.70Determine the following parameters:i) Moisture contentii) Dry densityiii) Void ratioiv) PorosityThen, by assuming the same parameters of sandy soil, determine the value for emin and relativedensity, Dr when the soil is having 10% of fine materials and emax = 0.79.
Cohesive soil is known as fine soil while cohesionless soil is known as course soil. Thesematerials are important to be identified for its parameters and classified accordingly ingeotechnical engineering design. Hence, explain briefly about the condition of permeabilityand porosity in both cohesive and cohesionless soils. Based on the laboratory testing on a sandy soil, the following values are obtained:Volume = 0.78 m3Moist mass = 1755 kgDry mass = 1432 kgSpecific gravity of soil solids = 2.70Determine the following parameters: iv) Porosity v)Then, by assuming the same parameters of sandy soil, determine the value for emin and relativedensity, Dr when the soil is having 10% of fine materials and emax = 0.79.
If soil is dried beyond its shrinkage limit, it will show [1998] Select your answer A Large volume change B Moderate volume change Low volume change No volume change