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Question 2 Find the permeability of core sample were data obtained by using air as shown below:- Flow rate Pressure upstream side of the core 1000 cc of air at downstream in 500 sec at standard condition (baseline) 1.7 atm Pressure downstream side of core 1 atm Cross-sectional area of core 2 cm² Length of core Viscosity of air 2 cm 0.02 cp flowrate upstream P₁Q₁ P₂ = Pb QP = QPb = Q₁P1 Ра P₂ downstream PbQb

Question 2 Find the permeability of core sample were data obtained by using air as shown below:- Flow rate Pressure upstream side of the core 1000 cc of air at downstream in 500 sec at standard condition (baseline) 1.7 atm Pressure downstream side of core 1 atm Cross-sectional area of core 2 cm² Length of core Viscosity of air 2 cm 0.02 cp flowrate upstream P₁Q₁ P₂ = Pb QP = QPb = Q₁P1 Ра P₂ downstream PbQb

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question 2 Find the permeability of core sample were data obtained by using air as shown below:- Flow rate 1000 cc of air at downstream in 500 sec at standard condition (baseline) Pressure upstream side of the core 1.7 atm Pressure downstream side of core 1 atm Cross-sectional area of core 2 cm² Length of core 2 cm Viscosity of air 0.02 cp flowrate upstream P₁ Q₁ downstream Pb Qb P₂ = Pb QP=QbPb = Q₁P₁ PQ P₂
Transcribed Image Text:Question 2 Find the permeability of core sample were data obtained by using air as shown below:- Flow rate 1000 cc of air at downstream in 500 sec at standard condition (baseline) Pressure upstream side of the core 1.7 atm Pressure downstream side of core 1 atm Cross-sectional area of core 2 cm² Length of core 2 cm Viscosity of air 0.02 cp flowrate upstream P₁ Q₁ downstream Pb Qb P₂ = Pb QP=QbPb = Q₁P₁ PQ P₂
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