Sickle cell anemia causes hemoglobin, the oxygen - carrying molecule of red blood cells, to be misshapen resulting in disease. "H" is the normal hemoglobin allele and "h" is the allele for sickle - cell shaped hemoglobin. In order to get the disease, a person must have a recessive genotype (hh). Two people with normal red blood cells are carriers of the gene - they have m genotypes Hh. Questions: a. What are the possible genotypes of the eggs the woman can produce? b. What are the possible genotypes of the sperm the man can produce? c. What is the genotypic ration for the offspring? d. What is the phenotype ratio for the offspring? e. What is the couple's chance of having a child a sickle

Sickle cell anemia causes hemoglobin, the oxygen - carrying molecule of red blood cells, to be misshapen resulting in disease. "H" is the normal hemoglobin allele and "h" is the allele for sickle - cell shaped hemoglobin. In order to get the disease, a person must have a recessive genotype (hh). Two people with normal red blood cells are carriers of the gene - they have m genotypes Hh. Questions: a. What are the possible genotypes of the eggs the woman can produce? b. What are the possible genotypes of the sperm the man can produce? c. What is the genotypic ration for the offspring? d. What is the phenotype ratio for the offspring? e. What is the couple's chance of having a child a sickle

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter10: From Proteins To Phenotypes

Section10.7: Defects In Transport Proteins: Hemoglobin

Problem 2EG

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Sickle cell anemia is caused by an individual carrying two recessive copies of the hemoglobin gene (hemoglobin gene is labeled Hb, and the recessive version is Hbs). Thus, to have sickle cell anemia, a person must have the genotype HbSHbS. A person that is HbAHbA carries two copies of the normal hemoglobin gene and does not have sickle cell anemia. A person that is heterozygous (HbAHbS) produces enough normal hemoglobin to not have sickle cell anemia but is also resistant to malaria. People that are heterozygous are called “carriers” because they carry the recessive allele but do not express the recessive phenotype. a. A couple are both resistant to malaria but do not have sickle cell anemia. Draw a Punnett square to represent this cross. b. What is the probability that the couple has three children where one child does not have a recessive allele, one child is resistant to malaria and does not have sickle cell anemia, and one child has sickle cell anemia?
Sickle cell anemia is a disease that is caused by a mutation in the gene that produces hemoglobin. Hemoglobin carries oxygen in red blood cells. The HbA allele produces normal hemoglobin and the HbS allele produces hemoglobin that sticks together and causes red blood cells to sickle. Heterozygous individuals (HbAHbS) produce both normal and "sickle" hemoglobin so the HbA and HbS alleles are codominant. Heterozygotes do not develop sickle cell anemia and are described as having the sickle cell trait. Individuals that are homozygous for the sickle allele (HbSHbS) only produce "sickle" hemoglobin and develop sickle cell disease. A man with the sickle cell trait married a woman with the sickle cell trait. Determine the probability that they will have children with the sickle cell trait or sickle cell disease.Record your answer as a value between 0 and 1 rounded to two decimal places. Answer
Suppose a woman who is a carrier of sickle-cell trait (making her a heterozygote) has children with a man who is totally healthy and does not carry the gene for sickle-cell trait at all. Which one of the following is true about their potential children? (Draw a Punnett square on scratch paper if it helps you.) A) None of their children will have sickle-cell disease. B) All of their children will have sickle-cell disease. C) All of the couple's children would be heterozygous carriers like the mother.
In humans, the allele for normal blood clotting, H, is dominant to the allele for hemophilia, h. The trait is X-linked. A female hemophiliac has a child with a man who is not a hemophiliac. What is the probability that this couple's child is a hemophiliac and what is the child's gender? Your response must include a Punnett square with correct nomenclature.
Hemophilia is an X-linked disease associated with the inability to produce specific proteins in the blood-clotting pathway. Shown above is a family pedigree tree in which family members afflicted with the disease are shown with filled-in squares (male) or circles (females). A couple is trying to determine the likelihood of passing on the disease to their future children (represented by the ? symbol above) because the hemophilia runs in the woman’s family 4.Assuming that the woman in the couple is a carrier, what is the probability that the couple’s first son will have hemophilia?
Rh factor is a protein that can be found on the surface of red blood cells. If your phenotype is Rh+ you have this protein on your red blood cells. If your phenotype is Rh-, then you do not have this protein on your red blood cells. Rh factor follows simple Mendelian genetics, meaning if you are Rh positive you can have the genotype Rh+Rh+ or Rh+Rh-. If Ruby's genotype is IBiRh-Rh-, and Sam's genotype is IAIARh+Rh-, what is the probability that their baby will be type AB+?
Alpha thalassemia is a hereditary blood condition that results in varying levels of anemia. It is tied to the HB alpha 1 gene and the HB alpha 2 gene on human chromosome 16. The diagram shows the proteins for the hemoglobin genes and the pedigree shows genotypes, designated by the letter X, on the chromosomes for a family affected by the condition. Which represents the predicted level of anemia in a child born to the mother and father in the image with a mutation that results in a genotype of xxxx? Why? A - mild anemia because the loss of 4 genes would equal the loss of the 4 proteins needed for normal alpha hemoglobin B - severe anemia because the loss of 4 genes would equal the loss of the 4 proteins needed for normal alpha hemoglobin C - mild anemia because the addition of 4 genes would produce too many of the proteins needed for normal alpha hemoglobin D - severe anemia because the addition of 4 genes would produce too many of the proteins needed for normal alpha hemoglobin
A gene is composed of two alleles. An allele can be either dominant or recessive. Suppose that a husband and wife, who are both carriers of the sickle-cell anemia allele but do not have the disease, decide to have a child. Because both parents are carriers of the disease, each has one dominant normal-cell allele (S) and one recessive sickle-cell allele (s). Therefore, the genotype of each parent is Ss. Each parent contributes one allele to his or her offspring with each allele being equally likely. Complete parts a) through c) below. a) Genes are always written with the dominant gene first. Therefore, there are two instances the offspring could have genotype Ss (one if the mother contributes the dominant allele and the father contributes the non-dominant allele; and one if the father contributes the dominant allele and the mother contributes the non-dominant allele). List the other two possible genotypes of the offspring. (Use a comma to separate answers as needed.)
Sickle cell anemia is an inheritable red blood cell disorder that results in sickle-shaped red blood cells. The sickle-shaped red blood cells can stick to blood vessel walls and cause a blockage or slow the movement of blood throughout the body. Individuals who are heterozygous produce both normal and sickle-shaped red blood cells which gives them resistance to malaria but they do not develop sickle cell anemia (so heterozygotes are unaffected on the pedigree).Let HbS be the allele for sickle cell anemia and let HbA be the allele for normal red blood cells. Which of the following rows provides the correct genotypes for individuals I-2, I-4, II-1, and III-1? Select one: a. I-2 I-4 II-1 III-1 HbA_ HbAHbS HbAHbS HbA_ b. I-2 I-4 II-1 III-1 HbA_ HbAHbS HbAHbS HbAHbS c. I-2 I-4 II-1 III-1 HbAHbS HbAHbS HbAHbS HbAHbS d. I-2 I-4 II-1 III-1 HbAHbA HbAHbA HbAHbA HbAHbA
4:33 4 Alger Edit Today 4:31 PM O LIVE Which of the following statements regarding Mendel's observations and Laws are still true and part of our knowledge of genetics today? (Check all that true.) M Two alleles segregate during meiosis, ending up in different gametes. Each pea plant has 2 alleles for every gene, but only contributes one in each gamete. The recombination of alleles in a zygote is completely random. The Law of Independeht Assortment was determined by following three traits in pea plants, TMendle was able to determine his Law of Segregation by following ane trait in pea plants. Every offspring inherits only 1 allele from each parent.
In humans, hemophilia is a sex-linked trait. Females can be normal, carriers, or have the disease. Males will either have the disease or not (but they won’t ever be carriers). X H X H = female, non-hemophilic X H X h = female, carrier X h X h = female, hemophilia X H Y = male, non-hemophilic X h Y= male, hemophiliac a.) Show the cross of a man who has hemophilia with a woman who is a carrier. What is the probability that their children will have the disease? b.) A woman who is a carrier marries a non-hemophilic man. Show the cross. What is the probability that their children will have hemophilia? What sex will a child in the family with hemophilia be? c.) A woman who has hemophilia marries a non-hemophilic man. How many of their children will have hemophilia, and what is their sex?
Sickle anemia is a favorable mutation. There is only one amino acid different in sickle haemoglobin (S) as compared with normal haemogloblin (A). Persons with sickle cell trait (AS) are able to survive in malarious areas. A couple each having sickle cell trait have five children. What is the probability that they will have a child with sickle disease?