Simplify the following expressions to a minimum SoP. Only individual elements should be complemented. a) [(XY)' + ( X' + Y')'Z ] b) (A + (B(C' + D')')')' c) [ (P' + Q)' + (PQ'R)' + R'S]'
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![Simplify the following
expressions to a minimum SoP.
Only individual elements should
be complemented. a) [(XY)' + (
X' + Y')'Z] b) (A + (B(C' + D')')')'
c) [ (P' + Q)' + (PQ'R)' + R'S ]'
please answer in typing
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- Eliminate the exclusive-OR, and then factor to obtain a minimum product of sums: (a) D'B'+ (DCA) (b) CB+(AB) C'+A'B Simplify each of the following expressions: A'D'(B+C)+(B+C)A'D+(B+C)(B+C) (a) (b) A'B'+A'C'+B'D'+B'C+DC (c) CB+BA+B'A'Describe each of the following expressions as SOP/POS. Discuss the no. of variables and identify min term (standard product term) or max term (standard sum term) F = A BC'D + AB + B`CD + D` * SOP POS min term = A`BC`D max term %3D max term = A`BC`D Number of variables Number of variables = 4What will be the final value of DI after executing the following piece of code? Execute the instructions dependently one after another. CLD MOU CX,OFOH MOU AX,05678H MOU DI,01000H MOU ES, DI SUB DI, DI REPNZ SCASB -R AX-0000 DS-073F 073F:0100 0000 D 1000:0 F 1000:0000 92 00 14 12 54 56 44 78-AD 56 78 FO 00 00 00 00 BX-0000 CX-0000 DX-0000 SP-00FD ES-1000 SS%3073F CS=073F BP-0000 SI=0000 DI=0000 IP-0100 NU UP EI PL NZ NA PO NC ADD IBX SI1,AL DS:0000 CD TUDX.Ux..... .... Notes: 1- Use the DEBUG window to answer this question (values shown are prior to execution and in hexadecimal 2- Write down the final value of DI as four hexadecimal digits without any additional characters.
- processors Systems And Interfacing If you subtract two decimal numbers, after BCD subtraction, to correct the result we use Oa AAA Instruction Ob AAM instruction Oc DAA instruction Od. DAS instruction Next page Windows bu alacy Jait ------ hp f3 ア D f7 19 %23 & フ R T Y Y ! VACO 12 DI F 1 G Y BY N T こo つ3) For the circuit shown in the following figure, Io - I3 are inputs to the 4:1 multiplexer. R (MSB) and S are control bits. The output Y can be represented by Answer: P 13 1₂ 4:1 MUX B Io S1 So RS Y O PQ+PR+ P Q S OPQ+ PS + QRS O PQ R+PQR+ Q R S + PQRS OPQR+ PQRS + Q R S+PQ RSShow graphical convolution for the following pair of signals please answer very soon will give rating surely All questions complete Answers needed
- What will be the modified form of the following codeword is odd parity scheme is used: Codeword: 0110101please solve this accurate and exact. thank youFor a ((A+B)' + (A'B')) Boolean equation, with the input waveforms as shown in Figure 2, which output waveform is correct? INPUT A INPUT B- OUTPUT a- OUTPUT b- OUTPUT C OUTPUT d- Figure 2 Output a Output d Output b Output c
- Remember to put no space in between characters. If the final answer is a whole number, put no decimal places. If it has one decimal place, then just put one decimal place. If the final answer has two decimal places, then put two, A maxcimum of two decimal places shall be placed as final answer. Allso, do not forget your units.) Given that Ci= 2.5F, C2= 1.5F, C3= 2F, C4= 2F. Solve for the following: 02 =Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A B C D) respectively with A is the MSB, the output variables are organized as (W XY Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. W=A+BD+BC' W=A+BD+BC, W=A'+BD+BC W= BC'D'+B'D+B'CAccording to the code below, all jumps are short jumps, meaning that the labels are in the range -128 to +127. IP Code Е06C 733F JNC ERRORI E072 7139 JNO ERROR1 ............ E08C 8ED8 MOV DS, AX ..... ЕOA7 ЕВЕЗ JMP C8 E0AD F4 ERRORI: HLT The address calculation of JNC, JNO, and JMP are: а. E08C, E08C, ЕOAD O b. E06E, EO74, EOA9 с. ЕОЗF, ЕОЗF, EOAD O d. EOAD, EOAD, E08C О е. Е039, EО39, EOEЗ