Suppose a router has built up the routing table shown in the Table below. SubnetNumber 128.96.39.0 128.96.39.128 128.96.40.0 192.4.153.0 (default) SubnetMask 255.255.255.128 255.255.255.128 255.255.255.128 255.255.255.192 a) 128.96.39.130 b) 128.96.39.100 c) 128.96.39.128 d) 128.96.40.10 NextHop Interface 0 Interface 1 R2 R3 R4 The router can deliver packets directly over interfaces 0 and 1, or it can forward packets to routers R2, R3, or R4. Describe what the router does with a packet addressed to each of the following destinations:

Suppose a router has built up the routing table shown in the Table below. SubnetNumber 128.96.39.0 128.96.39.128 128.96.40.0 192.4.153.0 (default) SubnetMask 255.255.255.128 255.255.255.128 255.255.255.128 255.255.255.192 a) 128.96.39.130 b) 128.96.39.100 c) 128.96.39.128 d) 128.96.40.10 NextHop Interface 0 Interface 1 R2 R3 R4 The router can deliver packets directly over interfaces 0 and 1, or it can forward packets to routers R2, R3, or R4. Describe what the router does with a packet addressed to each of the following destinations:

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter9: Computer Networks

Section: Chapter Questions

Problem 9VE

See similar textbooks

Similar questions

c) Suppose a router has built up the routing table shown in Table below: SubnetNumber SubnetMask NextHop 255.255.254.0 Interface () 255.255.254.0 Interface 1 128.96.170.0 128.96.168.0 128.96.166,0 255.255.254.0 R2 128.96.164.0 255.255.252.0 R3 (defaule) R4 The router can deliver packets directly over interfaces 0 and 1, or it can forward packets to routers R2, R3, or R4. Assume the router does the longest prefix match. Describe what the router does with a packet addressed to each of the following destinations: i. 128.96.167.151. ii. 128.96.163.151 ii. 128.96.169.192. iv. 128.96.165.121. v. 171.1.2.3
A router receives a packet with destination address IP: 201.10.64.199 (please refer to the table attached to find the IP address) Show how it finds the network and the subnetwork address to route the packet. Assume the number of subnetwork required is four.
A router interconnects a subnet, where all the interfaces of the subnets must have the prefix 164.132.62/24. suppose that the Subnet is required to support up to 60 interfaces, provide a network address that satisfies the above.
A router with IP address 125.45.23.12 and Ethernet physical address 23:45:AB:4F:67:CD has received a packet for a host destination with IP address 125.11.78.10 and Ethernet phys-ical address AA:BB:A2:4F:67:CD. (I) Show the entries (a, b, c, d, e in Figure 1(a)) in the ARP request packet sent by therouter. Assume no subnetting. (II) The packet made in part (I) is encapsulated in a data link frame. Fill in the fields fand g in Figure 1(a). (III) Show the entries (h, i, j, k, l in Figure 1(b)) in the ARP reply packet sent in responseto part (I). (IV) The packet in part (III) is encapsulated in a data link frame. Fill in the fields m andn.
Suppose a router has built up the routing table shown in Table 3.19. The router can deliver packets directly over interfaces 0 and 1, or it can forward packets to routers R2, R3, or R4. Assume the router does the longest prefix match. Describe what the router does with a packet addressed to each of the following destinations: (a) 128.96.171.92 (b) 128.96.167.151 (c) 128.96.163.151 (d) 128.96.169.192 (e) 128.96.165.121 Table 3.19 Routing Table for Exercise 56 SubnetNumber 128.96.170.0 128.96.168.0 128.96.166.0 128.96.164.0 (default) SubnetMask 255.255.254.0 255.255.254.0 255.255.254.0 255.255.252.0 NextHop Interface 0 Interface 1 R2 R3 R4
Registration Number: 193046 Consider a network with 3 hosts and a NAT router. Suppose that the network address of the home network is 192.168.NNN/24, where NNN are the last 3 digits of your Reg#. For example, if your Reg# is BSE193046, NNN = 046 and therefore the network address wil be 192168.46/24. (If NNN>255, consider NNN=254) (a) Assign any public IP address to NAT router’s outgoing interface. (b) Assign IP addresses to all 3 hosts and local interface of the NAT router in the home network. (
1) All dynamic routing protocols make routing decisions that are decided by an a) Central processing unit (CPU) b) Router c) Algorithm d) Processor
SUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 : A 175 hosts QUESTION 2 OF 10 Answer How many hosts can there be in this address space? 144.145.110.0/23 B Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. 84 hosts
R2(config)# router ospf 20 R2(config-router) # router-id 2.2.2.2 R2(config-router) # network 192.168.10.0 0.0.0.3 area 0 R2(config-router) # network 10.2.1.0 0.0.0.255 area 0 R2(config-router) # end R1(config)# router ospf 10 R1(config-router) # router-id 1.1.1.1 R1(config-router) # network 10.1.1.0 0.0.0.255 area 1 R1(config-router) # network 10.1.2.0 0.0.0.255 area 1 R1(config-router) # network 192.168.10.0 0.0.0.3 area 1 R1(config-router) # end Refer to the exhibit. Why are routers R1 and R2 not able to establish an OSPF adjacency? 1. Open Packet tracer and replicate the topology. 2. Refer on the configuration and load them in your topology 3. Apply the correct configuration 4. Test PC with 10.1.1.10/24 should be able to ping 10.2.1.10/24 5. Record your testing and save it as MP4 format. Area 0 10.2.1.0/24 GO/0.1 192.168.10.0/30 Area 1 .2 S0/0/0 .1 R2 10.1.1.0/24 SO/0/0 R1 GO/O G0/1 .1 10.1.2.0/24
19. ARP is used for: O packet path determination O finding of a mapping IPV6 → MAC address O finding of a mapping IPV4 → MAC address O finding of a mapping IPV4 → TCP address
Design a classfull network addressing scheme that will supply the minimum number of hosts per subnet, and allow enough extra subnets and hosts for 25% growth in all areas. IP Address 172.16.0.0 FO/0 S/0/1 FO/O Sales Administrative Router A FO/1 SO/0/0 185 Hosts 30 Hosts Marketing 50 Hosts
Refer the exhibit and the required number of hosts given. Subnet the address 192.168.50.0/24 for the required number of hosts using VLSM and complete the subnet table using the following instructions: NW: 192.168.50.0/24 NET-X: 45 USABLE HOSTS NET-Z: 2 USABLE HOSTS NET-Y: 25 USABLE HOSTS ------ GO/O R2 G0/0 GO/1 GO/1 R1 PC2 PC1 Assign the first subnet to network with the highest host requirement. Assign the second subnet to the network with the second highest host requirement. Assign the third subnet to the network with the third highest host requirement. Subnet Table: Subnet No. of Subnet First Last Usable Broadcast Subnet Name Usable Address Usable Host Address Mask hosts Host Address required Address