The anode in the above cell can actually be considered a standard hydrogen electrode if concentrations were standardized. That would make the cathode an ion selective electrode. What analyte would the electrode be detecting? And what component of the cathode would you replace by the solution containing the unknown concentrations of analyte?

The anode in the above cell can actually be considered a standard hydrogen electrode if concentrations were standardized. That would make the cathode an ion selective electrode. What analyte would the electrode be detecting? And what component of the cathode would you replace by the solution containing the unknown concentrations of analyte?

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter6: Solutions And Colloids

Section: Chapter Questions

Problem 6.89P

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H2O(l) + H2O(l) (double- headed arrow) H3O+(aq) + OH-(aq) At 5.0o C, the value of Kw for the equilibrium shown above is 1.9 x 10-15 and the value of pKw is 14.73. Based on this information, which of the following is correct for pure water at this temperature. A) H3O+ = sqrt( 1.9 x 10-15 ) B) pH = -log( 1.9x 10-15) C) 14.73 =( H3O+)(OH-) D) pOH = pH + 14.73
L_{2} is considerably more soluble in CC*L_{4}(1) than it is in H_{2}*O(1) At a certain temperature, the concentration of I_{2} in its saturated aqueous solution is 1.3*10^-3* M and the equilibrium achieved when I_{2} distributes itself between H_{2}*O and CC*L{4} is 12 (aq) rightleftharpoons 1 2 (CCL 4),; K = 85.5Part A: A 12.0-mL sample of saturated I_{2}(aq) is shaken with 12.0 mL of CC*L_{4} After equilibrium is established, the two liquid layers are separated. How many milligrams of will be in the aqueous layer? I_{2}
6-10. BaCl2 H,O(s) loses water when it is heated in an oven: BaCl2 H20(s) = BaCl2(s) + H2O(g) AH° = 63.11 kJ/mol at 25°C AS° = +148 J/(K• mol) at 25°C (a) Write the equilibrium constant for this reaction. Calculate the vapor pressure of gaseous H2O (PH,0) above BaCl2 H2O at 298 K. (b) If AH° and AS° are not temperature dependent (a poor assump- tion), estimate the temperature at which PH-O above BaCl, H,0(s) will be 1 bar.
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a laccd sign in ||| trl shift ↑ tab O CHEMICAL REACTIONS Calculating molarity using solute moles caps lock 0 ILION X ALEKS A chemist prepares a solution of potassium dichromate (K₂Cr₂O₂) by measuring out 9.94 µmol of potassium dichromate into a 100. mL volumetric flask and filling the flask to the mark with water. mmol esc Calculate the concentration in mmol/L of the chemist's potassium dichromate solution. Be sure your answer has the correct number of significant digits. K Explanation fn. https://www-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-lgNslkr7j8P3jH-IvUrTNdLZh5A8CnG03PBGuXr8iC Pa7ZMmym95T1680XL... L Check Type here to search Z X Graw 2 W ilion x360 hp here and every way am P S # x10 3 McGraw-Hill E X X X * alt E $ 4 C S ○ 박 % 5 V - Shusha 16 4- G H 4+ & 7 I hp 18 IAA * 8 J McGraw- © 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Access 6:38 PM a 7/22/2022 ? 87°F N K M A) f10 ALEKS - Shush f11 f12 3/5 insert alt [ prt sc ] G Shi backspace pause ctrl
oi ms uwn aci- dissociation constant, K. K,, etc. For example, a diprotic acid HA reacts as follows: The change in concentration (y =0.000064 mol Lis negligible compared to the initial concentration (0.083 mol L), so the simplitying approximation was valid. HA(ag) + H; O() = H,O" (ag) + HA (aq) Ka H,0*HA HA] Part C HA (ag) + H2O()= H,O (aq) + A? (aq) Calculate the equilbrium concentration of HC,O, in a 0.20 mol L solution of oxalic acid. Express your answer to two significant figures and include the K HA appropriate units. > View Available Hint(s) In general, K., = [A-| for a solution of a weak diprotic acid because H,0] [HA ]. HÀ ? Value [HC,0,) Units Submit
5:23 O13%DE elearning.yu.edu.jo/m O A student was given 2 beakers labeled with numbers 1 and 2, each beaker contains a clear solution. Additionally, he was given two reagent bottles labeled with A and B. Now, he added reagent A to both beakers and he noticed the formation of a precipitate in beaker 2 but not in beaker 1. However, the addition of reagent B to both beakers resulted in the formation of a precipitate in beaker 1 but not in beaker 2. Based on the information, which of the following is correct? a. compound A is the limiting reactant in beaker 1. b. compound B is the limiting reactant in beaker 2. c. compound A is the limiting reactant in beaker 2. d. compound B will be the excess reactant in beaker 1. Question 2
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