The stress-strain curve for mild steel is shown infigure given below. Choose the correct optionreferring to both figure and table.RQ.R.S.T.U.SUPoint on the graph Description of the pointP.1. Upper yield point2. Ultimate tensile strength3. Proportionality limit4. Elastic limit5. Lower yield point6. Failure

Given. Figure shown strain stress curve for mild steel.Therefore, We have to choose the correct…

The stress- curve for mild steel is shown in figure given below. Choose the correct option referring to both figure and table. R S U Point on the graph Description of the point P. 1. Upper yield point Q. 2. Ultimate tensile strength R. S. T. U. 3. Proportionality limit 4. Elastic limit 5. Lower yield point 6. Failure

The stress- curve for mild steel is shown in figure given below. Choose the correct option referring to both figure and table. R S U Point on the graph Description of the point P. 1. Upper yield point Q. 2. Ultimate tensile strength R. S. T. U. 3. Proportionality limit 4. Elastic limit 5. Lower yield point 6. Failure

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter1: Introduction

Section: Chapter Questions

Problem 1.5.6P: The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular...

See similar textbooks

Similar questions

The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
A tensile test was performed on a metal specimen having a circular cross section with a diameter of 1 2 inch. The gage length (the length over which the elongation is measured) is 2 inches. For a load 13.5 kips, the elongation was 4.6610 3 inches. If the load is assumed to be within the linear elastic rang: of the material, determine the modulus of elasticity.
A high-yield-strength alloy steel bar with a rectangular cross section that has a width of 37.5 mm, a thickness of 6.25 mm, and a gauge length of 203 mm was tested in tension to rupture, according to ASTM E-8 method. The load and deformation data were as shown in Table Using a spreadsheet program, obtain the following:a. A plot of the stress–strain relationship. Label the axes and show units.b. A plot of the linear portion of the stress–strain relationship. Determine modulus of elasticity using the best-fit approach.c. Proportional limit.d. Yield stress.e. Ultimate strength.f. If the specimen is loaded to 155 kN only and then unloaded, what is the permanent deformation?g. In designing a typical structure made of this material, would you expect the stress applied in (f) safe? Why?
Q2c) Listed in the table below is the tensile stress-strain data for different grades of steels. Utilizing the data given answer the three queries given below. Material Yield Tensile Strain at Fracture Elastic StrengthStrengthFractureStrengthModulus (MPa) (MPa) (MPa) (GPa) A 410 1440 0.63 265 410 В 200 220 0.40 105 250 C 815 950 0.25 500 610 D 800 650 0.14 720 210 E Fractures before yielding 650 550 1) Which will experience the greatest percent reduction in area? Why? 2) Which is the strongest? Why? 3) Which is the stiffest? Why?
An aluminum alloy bar with a rectangular cross section that has a width of 12.5 mm, thickness of 6.25 mm, and a gauge length of 50 mm was tested in tension to fracture according to ASTM E-8 method. The load and deformation data were as shown in Table P4.6. Using a spreadsheet program, obtain the following: a. A plot of the stress-strain relationship. Label the axes and show units. b. A plot of the linear portion of the stress-strain relationship. Determine the modulus of elasticity using the best fit approach. c. Proportional limit. d. Yield stress at an offset strain of 0.002 m/m. e. Tangent modulus at a stress of 450 MPa. f. Secant modulus at a stress of 450 MPa. TABLE P4.6 Load (kN) AL (mm) Load (kN) AL (mm) 33.5 1.486 3.3 0.025 35.3 2.189 14.0 0.115 37.8 3.390 25.0 0.220 39.8 4.829 29.0 0.406 40.8 5.961 30.6 0.705 41.6 7.386 31.7 0.981 41.2 8.047 32.7 1.245
A round aluminum alloy bar with a 0.25-in. diameter and a 1-in. gauge length was tested in tension to fracture according to ASTM E-8 method. The load and deformation data were as shown in Table P4.8.Using a spreadsheet program, obtain the following: a. A plot of the stress–strain relationship. Label the axes and show units. b. A plot of the linear portion of the stress–strain relationship. Determine modulus of elasticity using the best fit approach. c. Proportional limit. d. Yield stress at an offset strain of 0.002 in/in. e. Initial tangent modulus. f. If the specimen is loaded to 3200 lb only and then unloaded, what is the permanent change in gauge length? g. When the applied load was 1239 lb, the diameter was measured as 0.249814 in. Determine Poisson’s ratio.
A 19-mm reinforcing steel bar and a gauge length of 75 mm was subjected to ten- sion, with the results shown in Table P3.27. Using a computer spreadsheet pro- gram, plot the stress-strain relationship. From the graph, determine the Young's modulus of the steel and the deformation corresponding to a 150-kN load. TABLE P3.27 Load, kN Deformation, mm 54 0.084 163 0.168 284 0.336 330 1.428 366 3.360
3. The distribution of stress in an aluminum machine component is given (in megapascals) by Ox = y + z? Oy = x + z Oz = 3x + y Txy = 3z2 Tyz = x Txz = %3D Calculate the state of strain at a point positioned at (1,2,4). Use E=70 GPa and v = 0.3
} 8) A tensile load of 3000 N is applied to a steel bar of cross-sectional area 500 mm?. If a tensile load was applied to an aluminum bar to achieve the same lateral (transvers) strain with the former (steel bar), what would be the load? Note: Original dimensions of the two bars are the same (Est = 2.1 x 105 MPa, Eat = 0.703 × 105 MPa, vg = 0.3, vat = 0.33) E = º , v = - Saterat Eaxial Fatuminum™ 3000 N A-500 mm² A=500 mm² Fatuminum=? 3000 N Steel Aluminum
A cylindrical specimen of stainless steel having a diameter of 12.8 mm (0.505 in.) and a gauge length of 50.800 mm (2.000 in.) is pulled in tension. Use the load–elongation characteristics shown in the following table to answer the following: a. Plot the data as engineering stress versus engineering strain. b. Compute the modulus of elasticity. 66 c. Determine the yield strength at a strain offset of 0.002. d. Determine the tensile strength of this alloy. e. What is the approximate ductility, in percent elongation? f. Compute the modulus of resilience
The shown figure represents the stress-strain relations of metals A and B during tension tests until fracture.Determine the following for the two metals (show all calculations and units):a. Proportional limitb. Yield stress at an offset strain of 0.002 in./in.c. Ultimate strengthd. Modulus of resiliencee. Toughnessf. Which metal is more ductile? Why?
2. A steel bar, whose cross section is 0.55 inch by 4.05 inches, was tested in tension. An axial load of P = 30,500 lb. produced a deformation of 0.105 inch over a gauge length of 2.05 inches and a decrease of 0.0075 inch in the 0.55-inch thickness of the bar. Determine the lateral strain. * Your answer Determine the axial strain. Your answer Determine the Poisson's ratio v. * Your answer Determine the decrease in the 4.05-in. cross-sectional dimension (in inches). * Your answer