The unstretched length of spring AB is 3 m. If the block is held in the equilibrium position shown, determine the mass of the block at D.
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- The weight of the uniform bar AB is W. The stiffness of the ideal spring attached to B is k, and the spring is unstretched when =80. If W=kL, the bar has three equilibrium positions in the range 0, only one of which is stable. Determine the angle at the stable equilibrium position.Draw the FBD for the bar described in Prob. 5.1 if the bar is homogeneous of mass 50 kg. Count the unknowns.The homogeneous 240-lb bar is supported by a rough horizontal surface at A, a smooth vertical surface at B, and the cable BC. Draw the FBD of the bar and count the unknowns.
- Find the equilibrium positions of the 30-lb homogeneous bar and investigate their stability.The bar ABC is supported by three identical, ideal springs. Note that the springs are always vertical because the collars to which they are attached are free to slide on the horizontal rail. Find the angle at equilibrium if W = kL. Neglect the weight of the bar.The uniform bar AB of weight W and length L is pinned to a sliding collar at A and to the sliding rod BD at B. The spring wound around rod BD has a stiffness k and is undeformed when rod AB is in the position =0. Determine the expression for the angle (other than =90 ) at equilibrium and investigate the stability of equilibrium for this position.
- The stiffness of the ideal spring that is compressed by the slider C is k = 250 N/m. The spring is unstretched when =20. When the mass m is suspended from A, the system is in equilibrium at =60. Determine the value of m and whether the equilibrium position is stable or unstable.The cable of mass 1.8 kg/m is attached to a rigid support at A and passes over a smooth pulley at B. If the mass M = 40 kg is attached to the free end of the cable, find the two values of H for which the cable will be in equilibrium. (Note: The smaller value of H represents stable equilibrium.)The 14-kN weight is suspended from a small pulley that is free to roll on the cable. The length of the cable ABC is 20 m. Determine the horizontal force P that would hold the pulley in equilibrium in the position x=5m.
- 7] The unstretched length of spring AB is 3 m. If the block is held in the equilibrium position shown, determine the mass of the block at D. -3 m- 4 m. 3 m kAC = 20 N/m %3D kAB = 30 N/m www kAD = 40 N/m DIn figure shown, the unstretched length of spring AC is 3 m. If the block is held in the equilibrium position, determine the mass of the block at D. 3 m- 4m- KAc=20 N/m 3m KAB=40 N/m KAD=30 N/m2. Find the horizontal force P to start the motion of any part of the system of three blocks resting upon one another as shown. The weight of the blocks are W-300 KN, Ws= 100 KN and Wc =200 KN. Between A and B μ=0.30, between C and B, μ =0.20 and between C and the ground, p=0.10. 1 sni brod nog 02.0-4 B C 05.0-4 Solution: tamos quoy worla bre sosia asquar 005 300 en of jells400 N₁-300 F3 N-300- N₂=300 Assuming B and C will not move. F₁ = 300 (0.30) F₁ = 90 kN ne à bns A zelboß 1 P = 90 kN es ensla berb hebnu 02.0- y elin 05.0= q V in Celpris orllanimetsa MX 008 Assuming C will not move: al 1st F2=400 (0.20) = 80 kN OTE Bm ribirte F₂ vica Assuming the three blocks move: F3 = 0.10 (600) F3 = 60 kN P=60 KN Least force is 60 kN.