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- Using the data provided below and the information from the Activity 2's Experiment section, answer the following questions: Questions 7-10. Light tan represents the spots where the inoculum was plated, but showed no growth. Dark Tan represents the spots where inoculum was plated, but did show growth. Rich UMM UMM + histidine UMM + lysine UMM + tryptophanUsing the data provided below and the information from the Activity 3's Experiment section, answer the following questions: Questions 12-15. Light tan represents the spots where the inoculum was plated, but showed no growth. Dark Tan represents the spots where inoculum was plated, but did show growth. UMMYou are doing a viable cell count for a culture of E. coli you are growing in a flask. The volume of media in the flask is 1L. You took an aliquot directly from the media and diluted it using trypan blue. Here are the numbers that you get: squares counted: 4 total cells counted: 988 total viable cells counted: 960 THESE ARE THE QUESTIONS: What is your cell viability? What is the total number of viable cells in your flask? Show all work. Given: Cell Viability = Viable Cells/Total Cells Cells/mL = Total Viable Cells/Coners Counted x 10,000 x Dilution factor
- One of the early results shows that the post-centrifugation pellet of encapsulated cells also contains EA1 and/or Sap. Why is this not proof that Bacillus anthracis cells have both an S-layer and a capsule simultaneously? I need help finding the answer in the article and explain in short answer link to article: https://www.ncbi.nlm.nih.gov/pmc/articles/PMC106848/A Manton-Gaulin homogenizer is used for cell lysis. Which of the following are true? Increasing the number of passes can increase fine cell debris and make subsequent clarification more difficult. Cell growth conditions and phase of growth at which cells are processed can impact cell disruption. Decreasing temperature can increase protein release. Decreasing pressure reduces the number of passes required. Explain what is meant by the extent of cell disruption is 0.9.A phagehunter performs a full plate titer using standard techniques (100 ul of each dilution added to 250 ul of Gordonia terrae cells) of a lysate obtained from an optimum webbed plate experiment. The phagehunter counts 72 plaques on the 10-7 dilution plate. Which of the following scenarios is the best choice for the phagehunter to do next? a.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should adopt a phage from direct isolation. b.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should go back to the pick-a-plaque experiment. c.) The phagehunter has achieved a high enough titer lysate to move forward with characterization experiments. d.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should try to make more optimum webbed plates.
- Identify which antibiotic was used per set-up (see figure). Describe the result in the graphs provided to help you explain your answer. Listed below are some essential information.Antibiotic A: 0.5 kDa protein, targets peptidoglycanAntibiotic B: 20 kDa protein, targets peptidoglycanAntibiotic C: Cationic antimicrobial peptideAntibiotic D: Targets lipopolysaccharideStaphylococcus aureus: gram-positive bacteriumVibrio cholera: gram-negative bacteriumMethanosarcina: an archaean bacteriumCationic antimicrobial peptides (CAMPs): these positively charged antibiotics are attracted to the negatively charged cell wall and membrane. They are hydrophobic, and they insert into the membranes to create pores.The results of blood agar from the umbilical cord(a) and blood culture(b) both show beta haemolysis how would you present this in a results table?How does the microscopy in Figure 2 show that the capsule and an S-layer can exist in the same cell at the same time? I need help finding the answer in the article and explain in short answer link to article: https://www.ncbi.nlm.nih.gov/pmc/articles/PMC106848/
- Which of the the following results of the extracellular enzyme tests is FALSE? Question 3 options: A Liquid gelatin positive for gelatinase B Clear area around bacterial growth on a starch plate after iodine is added means amylase is present C Clear zone around bacterial growth on a milk plate means caseinase is present D Solid gelatin after is positive for gelatinase E No clear zone around bacterial growth on milk plate means absence of casienaseConfluence cells added onto 100-wells plate, 2 ml trypsin added onto cells and 6 ml media added to dilute trypsin, 1 ml was used for counting, and average number of Cells counted was 24(DF 2) find out the the number of cells/ml and total number of cells in 7 ml? How many cells you need for 100 wells, assuming Number of cells/well is 10 to the power 4 cells?Which tube will serve as the control in the “Normal Serum Bactericidins” portion of this lab activity? Tube A (Unheated normal serum) Tube B (Normal serum heated at 56 degrees C for 30 minutes) Both Tubes A( Unheated normal serum) and B (Normal serum heated 56 degrees C for 30 minutes) Tube C (Saline) There is no control in this activity.