What is the function of this C code snippet for PIC18FXXX?#pragma code My_HiPrio Int3D0x0008void My_HiPrio_Int(void){_asmGOTO chk_isrendasm#pragma codeSelect one:a. All of the aboveO b. Transfer control to main programc. Assigning 08H address for high priority interruptsO d. Transfer control to the ISR (Interrupt Sub-routine)

Name: What is the function of this C code snippet for PIC18FXXX?#pragma cod
Uploaded: 2024-03-20T06:51:23.000Z
Channel: Bartleby
Description: What is the function of this C code snippet for PIC18FXXX?#pragma code My_HiPrio Int3D0x0008void My_HiPrio_Int(void){_asmGOTO chk_isrendasm#pragma codeSelect one:a. All of the aboveO b. Transfer control to main programc. Assigning 08H address for hi

In this, we can see that a function is created by name: MyHiPrio_Int and in that we have used _asm…

Engineering

Computer Science

What is the function of this C code snippet for PIC18FXXX? #pragma code My_HiPrio_Int%3D0X0008 void My_HiPrio_Int(void) { asm GOTO chk_isr _endasm } #pragma code Select one: O a. All of the above O b. Transfer control to main program c. Assigning 08H address for high priority interrupts O d. Transfer control to the ISR (Interrupt Sub-routine)

What is the function of this C code snippet for PIC18FXXX? #pragma code My_HiPrio_Int%3D0X0008 void My_HiPrio_Int(void) { asm GOTO chk_isr _endasm } #pragma code Select one: O a. All of the above O b. Transfer control to main program c. Assigning 08H address for high priority interrupts O d. Transfer control to the ISR (Interrupt Sub-routine)

Microsoft Visual C#

7th Edition

ISBN:9781337102100

Author:Joyce, Farrell.

Publisher:Joyce, Farrell.

Chapter8: Advanced Method Concepts

Section: Chapter Questions

Problem 7RQ

See similar textbooks

Similar questions

* The LOOP # will affect only CX O All CS, CX and IP Both CX and IP non of those only IPO if BX=1000, DS=0400, and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL. the physical address is 6243H O 6324H 4244H O 6234H 4234H
* The LOOP # will affect only CX O only IP All CS, CX and IP Both CX and IP non of those It can implement the complement of the interrupt flag directly True O False
MIPS Simulator QtSpim: You are to have a complete program in MIPS assembly language that behaves exactly as the included C program. This program contains four functions in addition to the main() one. Your solution must contain all five C routines as they have been coded in the example. Make sure to run the program in MIPS and show the same output on MIPS as well to make sure there are no errors. Below is the five C routines and attached is the image of what the output must print out on QtSpim. #include <stdio.h> int getMax(int arr[], int n){int mx = arr[0];for (int i = 1; i < n; i++)if (arr[i] > mx)mx = arr[i];return mx;}void countSort(int arr[], int n, int exp){int output[n];int i, count[10] = { 0 };for (i = 0; i < n; i++)count[(arr[i] / exp) % 10]++;for (i = 1; i < 10; i++)count[i] += count[i - 1];for (i = n - 1; i >= 0; i--) {output[count[(arr[i] / exp) % 10] - 1] = arr[i];count[(arr[i] / exp) % 10]--;}for (i = 0; i < n; i++)arr[i] = output[i];}void…
Write a function that snapshots the timer using extended inline assembly and returns the32-bit value as a uint32_t. The base address of the timer should be sent as the sole argumentto the function as a uint16_t pointer.
The following code should use Timer A0 to trigger an ISR every 2ms. void main(void) { WDTCTL WOTPW | WDTHOLD; TASSEL_1 + ID_3 + MC_1 + TACLR; TAOCTL //Question 2c) //Question 2d) _enable_interrupt(); while(1); #pragma vector = TIMERO_A®_VECTOR interrupt void TIMERO_AO_ISR(void) { /* content not relevant */ } Figure Q3: Timer AO example code (a) What is the frequency of the ISR execution (i.e., how often is the ISR called per second)? (b) Based on the TAOCTL register configuration in the code, explain how Timer AO is configured. (c) Using an ACLK running at 32 kHz, calculate the correct Capture/Compare value and write the instruction to load this value into the appropriate register. (d) Write the instruction to enable Capture/Compare interrupts.
switch (c) { case 1: a = 10; break; case 2: a = 20; break; case 3: a = 30; break; default: a = 0; } Translate this piece of C codes into ILOC codes. Variable c and a should be stored in the activation record. Your translated codes start at address 1000 and grow to larger addresses. The address of a variable in the activation record is r_arp[@name], where r_arp is the register storing the activation record address and @name is the macro for the offset of the variable name. You may use labels instead of address number in jump/branch instructions.
IN C Using the parallel directives in OpenMP, parallelize the following for loop:
Q1\ 1- Write a program in assembly language for the 8085 microprocessor to send 10 bytes of data located at the memory address (3000h) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. And two high pulses must be sent before each byte (start bits) and one low pulse after each byte (end bits). You can use this flowchart, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes Transmit No Set up Character Bit Counter Send Start Bit Wait Bit Time Get Character in Accumulator Output Bit Using Do Wait Bit Time Rotate Next Bit in Do Decrement Bit Counter Is It Last Bit? Yes Add Parity if Necessary • Send Two Stop Bits Return (a)
Code required in mips assembly language not a c code required Write a MIPS procedure that takes as its two parameters the starting address of a (zero-terminated) string, and a character c, and removes all instances of the character from the string. Also, write a main program to test your procedure. Your main program should input a string from the user (you can assume that the string will be at most 40 characters, not including the zero byte delimiter), and then prompt for input of a character c. If the character c that the user inputs is the newline character (ascii code 10), your program should terminate. Otherwise, your program should invoke your procedure, output the modified string, and then prompt for input of another character to be removed from the string, continuing in this manner until the input character is the newline character.
• In string operations, register -- - is used to point to the source operand and register ----- is used to point to the destination operand. The-----flag is used to tell the CPU whether to or -- - the pointer in string operation. Your answer
code required in mips programming language a .s or .asm code not a c code. Write a MIPS procedure that takes as its two parameters the starting address of a (zero-terminated) string, and a character c, and removes all instances of the character from the string. Also, write a main program to test your procedure. Your main program should input a string from the user (you can assume that the string will be at most 40 characters, not including the zero byte delimiter), and then prompt for input of a character c. If the character c that the user inputs is the newline character (ascii code 10), your program should terminate. Otherwise, your program should invoke your procedure, output the modified string, and then prompt for input of another character to be removed from the string, continuing in this manner until the input character is the newline character
Computer Science Using memory-mapped I/O and polling, write a function print_string that prints a string onthe display, without using any system call. The address of the string is passed in register $a0and the string must be null-terminated. Test this function by calling it from the main function.Make sure to activate the “Keyboard and Display MMIO Simulator”.