With n(x) = e-x²/2 an(x) = Hn (x) (2"n! 1/2)1/2 verify that x-ip √√2 x + ip √√2 = = √/ 2 (x + 2x) Vn(x) = n²/² #₁-1(x), d = √/ 2 ( x − ²)√₁(x) = (n + 1) ¹/² #n+1(x). dx an(x)= Note. The usual quantum mechanical operator approach establishes these raising and lowering properties before the form of (x) is known.
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