Write a method and test it to insert an array of elements at index in a single linked list and then display this list. The method receives this array by parameters. write. java programming
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- Write a method and test it to insert an array of elements at index in a single linked list and then display this list. The method receives this array and index by parameters. By using java languageWrite a method to insert an element at index in a Doubly Linked List data structure and test it. The method receives this list by parameters By using java languagein java language import java.util.ArrayList;import java.util.Arrays; Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical order.*…
- Write a Java class myLinkedList to simulate a singly linked list using arrays as the underlying structure. Include the following methods: 1. insert an element within the linked list.(this should also work for the front and the rear of the list) 2. Remove an element from the linked list 3. Display (print) the elements of the linked list in order. 4. A method to check if the list is "empty". Test your solution using a linked list that initially has the characters A, B, D, E, F, and G. Insert "C" between B and D. Remove element "F". [Hint: One solution (recommended) is to use 2 arrays. One for the data, and the other for the "next" pointer. Also, consider using dummy nodes for the front, and possibly the rear of the list] Extend the solution so that it simulates a doubly linked list! (hint: You will need a third array to represent the "backward" pointers)Create a DeleteDuplicatesclass which consists of a deleteDuplicates method which takes the nums list as its parameter. Implement the deleteDuplicates method: Check if the input list is null or empty, and return an empty list if so. Initialize a pointer i to keep track of the unique elements. Use a for loop to Iterate through the list using another pointer j which starts at j=1 and goes until j=nums.size(); If the current element at j is not equal to the previous element at i using !nums.get(i).equals(nums.get(j), increment i and set the current element at j to the new position at i using nums.set(i, nums.get(j)). After the for loop ends, return the sublist from the beginning to i + 1, as this will contain all unique elements. Call the deleteDuplicates method with the sample list as argument: Call the deleteDuplicates method and pass the nums list as argument Store the result in a variable result Print the result to the console. Input: [1, 1, 2, 3, 3,…Complete ArrayStack.java, an array-based implementation o the Stack.java interface. Modify only the bodies of the following methods in the ArrayStack class: push pop top isEmpty isFull Nothing else should be modified in ArrayStack. Write the class ArrayStackTest to test your implementation. Print only the names of the tests and error messages. Give the test method meaningful names (e.g., emptyStackTest). Test push, pop, top, and isEmpty immediately after the stack has been instantiated. Push an element on an empty stack. Test pop, top, and isEmpty. Instantiate a stack with initialCapacity of 1. Push two elements. Check capacity. Other tests you deem necessary.
- Computer Science create a method +addToList(o:E):void that adds the object (o) to the ArrayList referenced by the instance variable list. create a method +removeFromBackOfList():E that removes the object at the back of the ArrayList and returns it.import java.util.ArrayList;import java.util.Arrays;public class PS{/*** Write the method named mesh.** Start with two ArrayLists of String, A and B, each with* its elements in alphabetical order and without any duplicates.* Return a new list containing the first N elements from the two* lists. The result list should be in alphabetical order and without* duplicates. A and B will both have a size which is N or more.* Your solution should make a single pass over A and B, taking* advantage of the fact that they are in alphabetical order,* copying elements directly to the new list.** Remember, to see if one String is "greater than" or "less than"* another, you need to use the compareTo() method, not the < or >* operators.** Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]** @param a an ArrayList of String in alphabetical order.* @param b an…import java.util.ArrayList;import java.util.Arrays; public class PS07A{/*** Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical…
- A consecutive sequence a list of numbers that are organized in increasing order with the next eleme. one bigger than the current. Write a non-recursive method "lengthConsec", which takes an IntNode myList as the parameter and returns the length of the consecutive sequence in myList. To simplify the implementation, you can assume that there is no more than one consecutive sequence in the list. For example, in the following linked list, the consecutive sequence begins at node "5" and ends at node "7", so lengthConsec (myList) should return 3 in this case. myList 8 13 4 public class IntNode { 12 private int m_data; private IntNode m_link; Consecutive sequence 6 7 28Java language Write a method to insert an array of elements at index in a single linked list and then display this list. The method receives this array by parametersSuppose that you want an operation for the ADT list that adds an array of items to the end of the list. The header of the method could be as follows: public void addAll( T[ ] items) Write an implementation of this method for the class LinearLinkedList