Applied Fluid Mechanics (7th Edition)
7th Edition
ISBN: 9780132558921
Author: Robert L. Mott, Joseph A. Untener
Publisher: PEARSON
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Chapter 10, Problem 10.46PP
Figure 10.38 shows a test setup for determining the energy loss due to a heat exchanger. Water at
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4. A heat exchanger creates energy loss in the fluid system shown below. Water at 50°C flows vertically upward
at a constant volume flow rate of 6 x 10-3 m³/s. A mercury manometer is used to measure pressure difference
between points 1 and 2. Evaluate the total energy loss (in a unit of m) between points 1 and 2. Using the
velocity in the inlet tube, evaluate the minor loss coefficient K corresponding to the heat exchanger. The
pipe geometry and mercury manometer setup are indicated in the figure. In the figure, OD indicates the
outer diameter of pipe. The specific weights of water and mercury are water = Pwater9 = 9.81 kN/m³ and
133.7 kN/m³, respectively. Ignore the volume flow rate of water into or out of the mercury manometer, but
one cannot ignore the contribution of water to the manometer measurement.
A
Flow
1200 mm
Y
Water
100-mm OD X
3.5-mm wall
steel hydraulic tube
Heat
exchanger.
1250 mm
350 mm
Y
Mercury
-50-mm OD x
2.0-mm wall
steel hydraulic tube
A (fluid 1) at the rate of 145 Ib/min is heated 75 °F to 150 °F by another fluid (fluid 2) enters the exchanger at 215 °F and leaves at 159 °F.(Fluid 2)making one shell pass and the (fluid 1) making two tubes pass. Due to fouling the heat transfer drops by 7% and the value of fouling factor is 0.0012. Calculate the outlet temperatures, I f the Cp to
the both fluids are = 0.98 Btu/ Ib .° F, flow is counter current.
Area of the heat exchanger is 98 ft2 and the
1. Consider the following schematic of a power plant (operating in what is called a
'Rankine Cycle')
Turbine
Steam
generator
Condenser
Coling water
Economiaer
The power plant control room reports that the plant is operating continuously at the following
peak load conditions:
a. Power to pump = 300KW
b. Rate of steam flow = 25 kg/s
c. Cooling water temperature at condenser inlet = 13 C
d. Cooling water temperature at condenser outlet = 34 C
Additionally, the following measurements were made at various points in the piping connecting
the power plant components
Data Pressure Temp. Quality enthalpy Specific Velocity
(kJ/kg)
point (kPa)
volume (m/s)
(m3/kg)
(C)
(x)
1
6200
2
6100
43
5900
177
----
4.
5700
493
-----
5
5500
482
-----
6
103
0.94
183
7
96
43
-----
Chapter 10 Solutions
Applied Fluid Mechanics (7th Edition)
Ch. 10 - Determine the energy loss due to a sudden...Ch. 10 - Determine the energy loss due to a sudden...Ch. 10 - Determine the energy loss due to a sudden...Ch. 10 - Determine the pressure difference between two...Ch. 10 - Determine the pressure difference for the...Ch. 10 - Determine the energy loss due to a gradual...Ch. 10 - Determine the energy loss for the conditions in...Ch. 10 - Compute the energy loss for gradual enlargements...Ch. 10 - Plot a graph of energy loss versus cone angle for...Ch. 10 - For the data in Problem 10.8, compute the length...
Ch. 10 - Add the energy loss due to friction from Problem...Ch. 10 - Another term for an enlargement is a diffuser. A...Ch. 10 - Compute the resulting pressure after a "real"...Ch. 10 - Compute the resulting pressure after a "real"...Ch. 10 - Determine the energy loss when 0.04m3/s of water...Ch. 10 - Determine the energy loss when 1.50ft3/s of water...Ch. 10 - Determine the energy loss when oil with a specific...Ch. 10 - For the conditions in Problem 10.17, if the...Ch. 10 - True or false: For a sudden contraction with a...Ch. 10 - Determine the energy loss for a sudden contraction...Ch. 10 - Determine the energy loss for a gradual...Ch. 10 - Determine the energy lass for a sudden contraction...Ch. 10 - Determine the energy loss for a gradual...Ch. 10 - For the data in Problem 10.22, compute the energy...Ch. 10 - For each contraction described in Problems 10.22...Ch. 10 - Note in Figs. 10.10 and 10.11 that the minimum...Ch. 10 - If the contraction from a 6-in to a 3-in ductile...Ch. 10 - Compute the energy loss that would occur as 50...Ch. 10 - Determine the energy loss that will occur if water...Ch. 10 - Determine the equivalent length in meters of pipe...Ch. 10 - Repeat Problem 10.30 for a fully open gate valve.Ch. 10 - Calculate the resistance coefficient K for a...Ch. 10 - Calculate the pressure difference across a fully...Ch. 10 - Determine the pressure drop across a 90 C standard...Ch. 10 - Prob. 10.35PPCh. 10 - Repeat Problem 10.34 for a long radius elbow....Ch. 10 - A simple heat exchanger is made by installing a...Ch. 10 - A proposed alternate form for the heat exchanger...Ch. 10 - A piping system for a pump contains a tee, as...Ch. 10 - A piping system for supplying heavy fuel oil at 25...Ch. 10 - A 25 mm ODx2.0 mm wall copper tube supplies hot...Ch. 10 - Specify the radius in mm to the centerline of a 90...Ch. 10 - The inlet and the outlet shown in Fig. 10.36 are...Ch. 10 - Compare the energy losses for the two proposals...Ch. 10 - Determine the energy loss that occurs as 40 L/min...Ch. 10 - Figure 10.38 shows a test setup for determining...Ch. 10 - Compute the energy loss in a 90 bend in a steel...Ch. 10 - Compute the energy loss in a 90 bend in a steel...Ch. 10 - For the data in Problem 10.47, compute the...Ch. 10 - For the data in Problem 10.48, compute the...Ch. 10 - A tube similar to that in Problem 10.47 is being...Ch. 10 - Prob. 10.52PPCh. 10 - Prob. 10.53PPCh. 10 - Prob. 10.54PPCh. 10 - Prob. 10.55PPCh. 10 - Repeat Problem 10.55 for flow rates of 7.5 gal/min...Ch. 10 - Prob. 10.57PPCh. 10 - Prob. 10.58PPCh. 10 - Prob. 10.59PPCh. 10 - Prob. 10.60PPCh. 10 - A 34 plastic ball valve carries 15 gal/min of...Ch. 10 - A 114 plastic butterfly valve carries 60 gal/min...Ch. 10 - A 3 -in plastic butterfly valve carries 300...Ch. 10 - A 10-in plastic butterfly valve carries 5000...Ch. 10 - A 1 12 plastic diaphragm valve carries 60 gal/min...Ch. 10 - Prob. 10.66PPCh. 10 - Prob. 10.67PPCh. 10 - Prob. 10.68PPCh. 10 - Prob. 10.69PPCh. 10 - An 8 -in plastic swing check valve carries 3500...Ch. 10 - Use PIPE-FLO software to determine the pressure...Ch. 10 - Use PIPE-FLO to calculate the head loss and...
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- Hot oil is pumped through a heat exchanger (see figure below) at a flow rate of 0.5 L/s. An inlet manifold equally distributes the oil into 20 parallel, 5-mm-diameter copper tubes that are about 1 m in length. The oil cools down as it flows through the copper tubes. Oil then exits through an outlet manifold. The viscosity of the oil is 250 centipoise and its density is 950 kg/(m^3). Assuming uniform pressure in the manifolds and laminar flow through the tubes. calculate the total head loss (in meters) across those 20 copper tubes. COPPER TUBES MANIFOLDS Round your answer to 2 decimal places.arrow_forwardHot oil is pumped through a heat exchanger (see figure below) at a flow rate of 0.5 L/s. An inlet manifold equally distributes the oil into 20 parallel, 5-mm-diameter copper tubes that are about 1 m in length. The oil cools down as it flows through the copper tubes. Oil then exits through an outlet manifold. The viscosity of the oil is 250 centipoise and its density is 950 kg/(m^3). Assuming uniform pressure in the manifolds and laminar flow through the tubes, calculate the total head loss (in meters) across those 20 copper tubes.arrow_forwardDesign a simple piping system to pump water at temperature 130F from a sump below a heat exchange to the top of the cooling. The desired flow rate is 222gal/min, and the pump efficiency is 88%. Include the required power and head loss of the pump and the total head loss.arrow_forward
- Consider a pumping system used in a cooling water loop. Water is drawn from a tank, which maintains a height of 2 m of water. It then enters the pump and then passes through the process heat exchanger, where it is heated. The water is then cooled back to cooling water temperature using a chiller (another heat exchanger). Finally, water exits the chiller and is circulated back to the original tank, forming a closed loop. All equipment is at ground level. All pipe in the system is 2-inch schedule 40, commercial steel pipe.arrow_forwardExample -5.2- It is required to pump cooling water from storage pond to a condenser in a process plant situated 10 m above the level of the pond. 200 m of 74.2 mm i.d. pipe is available and the pump has the characteristics given below. The head loss in the condenser is equivalent to 16 velocity heads based on the flow in the 74.2 mm pipe. If the friction factor = 0.003, estimate the rate of flow and the power to be supplied to the pump assuming n = 0.5 Q (m³/s) 0.0028 0.0039 0.005 0.0056 0.0059 Ah (m) 23.2 21.3 18.9 15.2 11.0arrow_forwardThe Figure shown below is a parallel pipeline system with two branches used to supply lubricating water to the bearings. The main line and two branches use the same size of pipes. The pressures at section 1 and section 2 are and , respectively. The resistance coefficients for two bearings are and . The cross section areas of two branch pipes are . The energy loss caused by friction can be ignored. The energy loss caused by one bend is . (4) Calculate the energy loss for branch b_________arrow_forward
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- Find the air flow rate in the duct. Data: Air pressure: 17 psia air temperature at the inlet: 65 F air temperature at the exit: 125 F duct wall temperature 230 F duct cross section is 1.5 ft by 1 ft length of the heated segment is: 8 ftarrow_forwardFLUID MECH Support your answer with the appropriate solution and diagram. 7. Water from the reservoir is pumped over hill through a 90 cm diameter pipe, and the pressure of 200 kPa is maintained at the summit, where the pipe is 90 cm above the reservoir. The flow is 1.40 m^3/s with a head loss of 3.0 m between the reservoir and summit. If the pump is 90% efficient, what is the input power furnished to the water in KW. A. 1865 B. 1954 C. 1734 D. 1923.arrow_forwardThe Figure shown below is a parallel pipeline system with two branches used to supply lubricating water to the bearings. The main line and two branches use the same size of pipes. The pressures at section 1 and section 2 are and , respectively. The resistance coefficients for two bearings are and . The cross section areas of two branch pipes are . The energy loss caused by friction can be ignored. The energy loss caused by one bend is . (3) Calculate the energy loss for branch a_________arrow_forward
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