Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 10, Problem 5P
(a)
To determine
To Explain: The magnitude of its
(b)
To determine
To Explain:The magnitude of its angular momentum if the radius of the circle is doubled but the speed of the particle is unchanged.
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(a) A light, rigid rod of length = 1.00 m joins two particles, with masses m, 4.00 kg and m₂ = 3.00 kg, at its ends. The
combination rotates in the xy-plane about a pivot through the center of the rod (see figure below). Determine the angular
momentum of the system about the origin when the speed of each particle is 4.20 m/s. (Enter the magnitude to at least two
decimal places in kg-m²/s.)
magnitude
direction
kg-m²/s
-Select-O
(b) What If? What would be the new angular momentum of the system (in kg- m²/s) if each of the masses were instead a solid
sphere 12.5 cm in diameter? (Round your answer to at least two decimal places.)
kg-m²/s
(a) Calculate the axial and total angular momentum of the Earth.
(b) What is the change in the angular velocity of the Earth due to the collision?
(c) What is the maximum possible change in the length of a day due to the collision?
(d) How much energy is needed to stop the Earth’s rotation about its axis after the collision?
(e) What would be the moment of inertia of the Earth if the axis of rotation is parallelly shifted so that it touches the equator?
Chapter 10 Solutions
Physics for Scientists and Engineers
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- The position vector of a particle of mass 2.00 kg as a function of time is given by r=(6.00i+5.00tj), where r is in meters and t is in seconds. Determine the angular momentum of the particle about the origin as a function of time.arrow_forwardA bird flies overhead from where you stand at an altitude of 300.0 m and at a speed horizontal to the ground of 20.0 m/s. The bird has a mass of 2.0 kg. The radius vector to the bird makes an angle with respect to the ground. The radius vector to the bird and its momentum vector lie in the xy-plane. What is the bird’s angular momentum about the point where you are standing?arrow_forwardA thin rod of length 2.65 m and mass 13.7 kg is rotated at anangular speed of 3.89 rad/s around an axis perpendicular to therod and through one of its ends. Find the magnitude of the rodsangular momentum.arrow_forward
- A uniform rod of mass 200 g and length 100 cm is free to rotate in a horizontal plane around a fixed vertical axis through its center, perpendicular to its length. Two small beads, each of mass 20 g, are mounted in grooves along the rod. Initially, the two beads are held by catches on opposite sides of the rod’s center, 10 cm from the axis of rotation. With the beads in this position, the rod is rotating with an angular velocity of 10.0 rad/s. When the catches are released, the beads slide outward along the rod. (a) What is the rod’s angular velocity when the beads reach the ends of the rod? (b) What is the rod’s angular velocity if the beads fly off the rod?arrow_forwardThe velocity of a particle of mass m = 2.00 kg is given by v= 5.10 + 2.40 m /s. What is the angular momentumof the particle around the origin when it is located atr= 8.60 3.70 m?arrow_forwardA satellite is spinning at 6.0 rev/s. The satellite consists of a main body in the shape of a sphere of radius 2.0 m and mass 10,000 kg, and two antennas projecting out from the center of mass of the main body that can be approximated with rods of length 3.0 m each and mass 10 kg. The antenna’s lie in the plane of rotation. What is the angular momentum of the satellite?arrow_forward
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