Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
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Chapter 11, Problem 11.11PFS
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To check for the given member
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In the built-up girder shown below that has an unbraced length of 25 ft. (L-25 ft) and moment gradient factor of C,-1,
determine the maximum flexural design strength.
E-29000 ksi
Fy-50 ksi
PL 25x0.6"
PL 35*0.3"
PL 25x0.6"
A W36x210 can be used for Transfer Girder ‘A’ as shown in the elevation next page.Assume the LRFD loads on the ‘Transfer Girder’ are as follows:Pu= 200 kips from the column above. Assume also that the loads from self-weight of thewu = 2.0 kip/ft (girder self weight and beams framing into this transfer girder are equivalentto a uniformly distributed load). These loads are shown in the last figure.a) Check whether the W36x210 ‘Transfer Girder’ is adequate for bending and shear.Assume the unbraced length Lb =20 ft.b) Suppose that service loads, w and P, are both 50% dead load and 50% live load. Does theW36x210 satisfy a service live load deflection limit of L/480?
a) Name one benefit of a moment frame over a braced frame and name one benefit of a braced frame over a moment frame.
b) Name and describe the two major failure modes of a beam-column member comprised of a W-section.
c) What is the major difference of a beam-column from a beam or a column?
d) Why are moment magnifications needed for beam-columns? Briefly explain each of the two.
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Structural Steel Design (6th Edition)
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- The frame shown below is subjected to uniformly distributed load of 2.6KP.. Determine the maximum moment of member BF (assume simple beam support) A E, 1.5m F 1.5m 351 C 1.5m H 3m Barrow_forward1 - Det. the force in each member of the roof truss and identify if (C) – compression or (T) – Tension. 300N 30⁰ X B 500N 30⁰ 600N X AB AC BC BD CD 30⁰ Darrow_forwardTutorial 7 Вeams 1. A simply supported beam must carry the factored ultimate loads (two 15kN point loads) shown in the figure. Do not consider the self-weight of the beam. The beam is laterally and torsional supported only at A, B, C and D. For a 203 x 133 x 25 I- section: (Grade 350 W steel) (a) Determine the class of the section. (b) Determine whether the section has sufficient flexural resistance. 15 kN 15 kN 4,0 m 2,0 m 4,0 marrow_forward
- A two-story frame, is braced in y axis (Ky-1) and is connected as moment frame for x axis as shown below. Assuming elastic behavior, and all steel has Fy-50ksi, determine following for column BF. a) Kx for column. b) The governing buckling axis. c) Failure mode in column (Inelastic or elastic global buckling). d) Design strength of the column according to LRFD method (Pn). e) If the column is adequate for the service dead load of 180K and live load of 240K. Use the kx value obtained in part a and select lightest HSS rectangular to replace W12x72. Compare the weight of selected section f) E A W18 X 35 W18 X 35 F 20' B J W12 X 50 W12 X 72 W18 X 40 W18 X 50 30' G K 30' H 20¹ 15'arrow_forwardUse proper method ASimply supported one way slab is reinforced with 0.5% tension steel and has effective depth of 130 mm for a span of 3.5. Using D. A. - Sp 16, check the slab for deflection. Use M 20, Fe 415arrow_forwardThe floor structural system shown in Fig 1 comprise W-section steel beams and girders supporting a 5-inch thick concrete slab which provides full restraint to the flanges of the beams. The density of concrete is 150 lbs./ft'. and the uniformly distributed live load L- 50 lbs/ft². L-22 B. Girder G1: - B [za] 12' GI GI 12 + [ial FIG. 1-Steel Floor Beam a) Strength - Bending and Shear -I 1) Produce a sketch of the floor plan showing the tributary load distribution areas for the beams and girders [za]arrow_forward
- Use A992 steel, select a W-shape for the upper girder that spans left to right and picks up the loading from the three floor beams. Assume the beam is simply supported. The maximum permissible live load deflection is L/360. The service dead loads consist of a 5-inch thick reinforced concrete floor slab (normal weight concrete), a partitionload of 25 psf, and 20 psf to account for suspended ceiling and mechanical equipment. Don’t forget to check with self-weight. The service live load is 100 psf. You may use AISC Table 3-2 and/or Table 3-10 to check for bending and shear. Use LRFD only. Take Cb = 1.0. Please show all work to verify that this beam is adequate for bending, shear and deflectionarrow_forwardVerify the bending resistance and global stability of the beam. Gravity load is 0.9kN/m, concentrated load 100 kN is applied in the midpoint of the span. Q235 steel is used. a. No brace in the middle of the span. Concentrated load is applied on the top flange. b. No brace in the middle of the span. Concentrated load is applied on the bottom flange. (optional) C. Braced in the middle of the span. Concentrated load is applied on the top flange. d. Same as (a), use Q345B steel. 0.9kN/m 200×12 5000 100KN 5000 I 776x8 200×12arrow_forwardProblems / Eqi FUNDAMENTAL PROBLEMS All problem solatioIS must include an FBD. FS-1. Determine the horizontal and vertical companents of reaction at the supports. Neglect the thickness of the beam. FS sup SCI tb t tb-ft 5t 511 F5-1 Determine the harizontal and irntsarrow_forward
- View Policies Current Attempt in Progress The simply supported beam consists of a W460 x 82 structural steel wide-flange shape [E-200 GPa; 1-370 x 10 mm4]. For the loading shown, determine the beam deflection vc at point C. Assume P-62 kN, w - 28 kN/m, LAB - LBC -2.9 m. LCD - 1.9 m. P W TV D C LBC Answer: VCF LAB B mm. LCDarrow_forwardThe beam is A992 steel. For the loading shown, determine the 600 lb/ft slope at A and the deflection at C. A B W14x 26 ( 9 kip -8 ftarrow_forwardQ3) A simply supported beam has been satisfactorily designed to resist flexure. At a distance d from the support face the following condition exist: V-45 KN, M-9KN.m V₁-25KN,M₁-18KN.m h=500mm, d=450mm, b=300mm, f'c-21MPa and fy=350MPa.As consists of 3 No.29 bars. A/ Check the beam for shear requirements. use: V - (0.16 [Fe + 170. Xd) b. d fe Pw M₂arrow_forward
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