Chapter 1.1, Problem 27WE

To determine

To Evaluate: The expression $\frac{\left(y+x\right)}{\left(y-x\right)}$ if $x=2$ , $y=3$ , and $z=4$

Answer to Problem 27WE

The value of the expression $\frac{\left(y+x\right)}{\left(y-x\right)}$ is $\frac{\left(y+x\right)}{\left(y-x\right)}=5$

Explanation of Solution

Given information:

The expression $\frac{\left(y+x\right)}{\left(y-x\right)}$ and the values $x=2$ , $y=3$ , and $z=4$

Concept Used:

The value of an expression at the given values of the unknowns is calculated by substituting the given values of the unknowns into the expression and simplifying it.

Calculation:

Given the expression $\frac{\left(y+x\right)}{\left(y-x\right)}$

Evaluating the expression $\frac{\left(y+x\right)}{\left(y-x\right)}$ at $x=2$ , $y=3$ , and $z=4$ , we have

  $\begin{array}{c}\frac{\left(y+x\right)}{\left(y-x\right)}=\frac{\left(3+2\right)}{\left(3-2\right)}\text{ Substituting }x=2,y=3\\ =\frac{5}{1}\text{ Solving numerator and denominator}\\ =5\end{array}$

Therefore, $\frac{\left(y+x\right)}{\left(y-x\right)}=5$

Conclusion:

The value of the expression $\frac{\left(y+x\right)}{\left(y-x\right)}$ is $\frac{\left(y+x\right)}{\left(y-x\right)}=5$