Universe
11th Edition
ISBN: 9781319039448
Author: Robert Geller, Roger Freedman, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 11, Problem 92Q
To determine
The change in elongation angle of Vulcan, due to the change in its orbital size by one-half. It is given that Vulcan is orbiting closer to the Sun than Mercury and its eccentricity is the same as that of Mercury.
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Scientist once hypothesized the existence of a planet called vulcan to explain Mercury's precession. Vulcan is supposed to be between mercury and the sun with a solar distance equal to 2/3;of that mercury. What would be its supposed period
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Chapter 11 Solutions
Universe
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- I. Directions: Complete the given table by finding the ratio of the planet's time of revolution to its radius. Average Radius of Orbit Times of Planet R3 T2 T?/R3 Revolution Mercury 5.7869 x 1010 7.605 x 106 Venus 1.081 x 1011 1.941 x 107 Earth 1.496 x 1011 3.156 x 107 1. What pattern do you observe in the last column of data? Which law of Kepler's does this seem to support? II. Solve the given problems. Write your solution on the space provided before each number. 1. You wish to put a 1000-kg satellite into a circular orbit 300 km above the earth's surface. Find the following: a) Speed b) Period c) Radial Acceleration Given: Unknown: Formula: Solution: Answer: Given: Unknown: Formula: Solution: Answer: Given: Unknown: Formula: Solution: Answer:arrow_forwardOn the evening of an autumnal equinox day Siddhant noticed that Mars was exactly along the north-south meridian in his sky at the exact moment when the sun was setting. In other words, the Sun and Mars subtended an angle of exactly 90° as measured from the Earth. If the orbital radius of Mars is 1.52 au, What will be the approximate rise time of the mars on the next autumnal equinox day?arrow_forwardCalculate how many seconds there are in 1.0 Mars year (678 Earth days). Report your answer in scientific notation with the correct number of significant digits.arrow_forward
- The average orbital distance of Mars is 1.52 times the average orbital distance of the Earth. Knowing that the Earth orbits the sun in approximately 365 days, use Kepler's law of harmonies to predict the time for Mars to orbit the sun.arrow_forwardComet Halley (Fig. P11.21) approaches the Sun to within 0.570 AU, and its orbital period is 75.6 yr. (AU is the symbol for astronomical unit, where 1 AU = 1.50 1011 m is the mean EarthSun distance.) How far from the Sun will Halleys comet travel before it starts its return journey?arrow_forwardYou may attempt this question 3 more times for credit. In this problem, we will directly calculate the surface gravity and your weight on another planet. In metric, your weight is measured in "Newtons", and 1 Newton = 1 kg m / s². Newton's constant G = 6.67 x 10-11 m³/(kg s²). Earth has a mass = 5.97 x 1024 kg and a radius of 6378 km. You should be able to verify that g = 9.8 m/s² on Earth using the formula for surface gravity. If your mass is 64 kg, you should also be able to verify you should weigh 626 Newtons. If you can do that you should be OK for what's next. The mass of Venus is 4.87E+24 kg, and it's radius is 6.05E+3 km. What is the surface gravity of this planet? (Watch your units!). m/s² If your mass is 64 kg, what would you weigh on Venus? Newtons. Note: Remember if your answer requires scientific notation to use the "e" notation: "1.1 x 105" is "1.1e5" to OWL.arrow_forward
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