Concept explainers
(a)
The voltage
(a)
Answer to Problem 1E
The voltage
Explanation of Solution
Given data:
The voltage
The voltage
Calculation:
The voltage
Substitute
Conclusion:
Therefore, the voltage
(b)
The power dissipated in the junction
(b)
Answer to Problem 1E
The power dissipated in the junction
Explanation of Solution
Given data:
The current flowing into the terminal
Calculation:
The power dissipated in the junction
Substitute
Conclusion:
Therefore, the power dissipated in the junction
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Chapter 12 Solutions
Engineering Circuit Analysis
- (a) Refer to the circuit in figure 1 below: R = 5 k2 Ip Vp: = 10 V Figure 1 i. Determine and draw the load line for the circuit. ii. Calculate VD, given Ip, is 3.5mA. iii. Determine the power dissipated in the diode. (c) Let say a new AC source v is added to the circuit in Figure 1, as shown in Figure 2 below. Given vi = 0.5sinot V, determine the total voltage vz across the resistor R. | R = 5 k2 Vp: = 10 V ♡ VD Figure 2arrow_forward(2) Consider the following circuit with a source voltage Vs and resistances Rlimiting-R=1.0 km2. The diode IV characteristics have a turn-on voltage Vio=0.70 V, a breakdown voltage - Vbr=-6.0 V, and a reverse saturation current of lo= 0.10 mA. The source voltage varies between Vs Max=+25.0 V and Vs Min=-25.0 V. Calculate the resistor voltage Vo for the maximum and minimum of Vs. www Rlimiting Karrow_forwardThe diodes in the circuit depicted can be modelled as ideal diodes with an 0.7 V diode drop. The resistor values are R1 = 2.1 kO and R2 = 2.2 KQ. Vin = 120° v w = 1k rad/s Vout[max.] = Vout[min.] = R1 Ω Vout= ( What are the maximum and minimum voltage values vout takes? Also, define a and b, such that between the maximum and minimum voltages Vout= (axVin - b) V. Answer to within 1% accuracy. R2 Ω ww (₁₁ out V V Vin - ) Varrow_forward
- a. What is the effect of applying reverse voltage on a pn junction? b. What is the critical electric field and when will it happen?arrow_forwardA load is connected in the Full Bridge rectifier circuit (Four Diodes). Usedtransformer primary voltage value is 220 V (rms). The transformer winding ratio is 1:10.Using the 0.7 V model of the diode,Load Value: Student No. Last 1 digit ( will be selected as kΩ, LastThose whose number is "0" get "9")a) How many % of conduction does each diode branch stay on?b) Find the average values of the load voltage.c) Find the average values of the load current.d) Find the effective value of the load voltage.e) Find the effective value of the load current.arrow_forwardUsing the Mathematical and Graphical Method, Determine the Qpoint and terminal voltages for the given circuit below. Compare the values from the two different approaches. Determine the terminal voltages and currents and the inter-electrode voltages.arrow_forward
- (a) State one possible reason why the diodes have different knee voltage values. 2. Figure A.1 shows I-V characteristics of two diodes, namely A and B. Diode A has UTM higher dynamic resistance than diode B. 5 UTM U UTM Ip UTM TM 3 UTM UTM O UTM UTM UTM UTM & UTM 03 TM UTM 0.68 VD Figure A.1 State one possible reason why the diodes have different knee voltage values. 5 UTM & UTM M 3 UTM (b) Based on Figure A.1, identify the knee voltage of UTM (c) Draw with complete labelling an equivalent circuit that represents the circuit in UFigure A.2. Consider practical diode model. TM 5 UTM 5 UPde BE UTM & UTM & UTM 1 ΚΩ Diode B 5 UTM O UTM UTM & UTM & UTM 1.5 V 5 UTM UT 5 UTM 3 V 5 UTM O UTM Figure A.2 M G UTM 5 UTM 5 UTM & UTM 5 UTM UTMarrow_forwardIn the circuit of the following figure, the input voltage Vs is 15 volts rms with a frequency of 60 Hz, R equals 150 Ohms and C equals 100,000 Pico Farads. The diodes are Germanium (Vd = 0.2 volts) and the Zener diode is 12 volts. a) The magnitude of the ripple voltage at Cb) The Magnitude of the Peak Inverse Voltage (PIV) for D1 and D2.arrow_forwardQ2) Explain the working of zener diode on both forward and reverse bias. From the circuit in the Figure-2, Rs=1KO, Vz=7.2V and RL=3KN. If Vs = 12V. Find out the following DC parameters: a) Is = ?, Current passing through resistor Rs b) IL = ?, Current passing through resistor RL c) Iz = ?, Current passing through Zener Diode d) VL= ?, Output Voltage (Figure-2) Rs 1k Ohm Is Iz RL VL Vs UA723_ZD2 .3k Ohm 12 Varrow_forward
- A half-wave rectifier is needed to supply 15-V dc to a load that draws an average current of 250 mA. The peak-to-peak ripple is required to be 0.2 V or less. What is the minimum value allowed for the smoothing capacitance?arrow_forwardConsider the circuit shown below. The reverse saturation current is 1x10-¹6A and R₁=3kQ2. Vin 5V. D₁-D4 are the same. Vin P₁ # Ri M P₂ D3 Dy + Vout (a) What should be the current flow through the diodes? Use the full exponential model to analyze this. (b) What is Vout? Use the full exponential model to analyze this. (c) Suppose, Vin is increased by 0.1V. What will be the increase of Vout? Use the full exponential model to analyze this.arrow_forward*Use 4 decimal places. For the circuit below, determine the diode voltages VD1 and VD2, diode currents Ip1 and Ip2, and voltage across the resistor, VRLIMIT- Assume r'a (for both diodes)=200. Note D, is Germanium, D2 is Silicon, VBJAS = 22V and RLIMIT = 2 kohms. VD1 = 0 V; VD2 = 0 V; Ip1 = Blank 3 mA; Ip2 = Blank 4 mA ; VRLIMIT = Blank 5 v Use ideal model. Capture3.JPG +VD1- +VRLIMIT +Vp2- Ip2 VBIAS 두arrow_forward
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