Biology 2e
2nd Edition
ISBN: 9781947172517
Author: Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher: OpenStax
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Chapter 13, Problem 4RQ
X-linked recessive traits in humans (or in Drosophila) are observed.
- in more males than females
- in more females than males
- in males and females equally
- in different distributions depending on the trait
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Part 2
Spotty and Cutie have puppies and 50% of the puppies are unaffected for both traits (not blind and not BHFD). What is
Spotty's genotype?
bbDD
bbdd
BBDd
BbDd
BbDD
BBdd
Males of many diploid species (like us) have X and Y sex chromosomes. They are hemizygous for most X-
linked genes. Thus, males express most X-linked alleles, whether they are dominant or recessive in
females. In the fruit fly Drosophila, it is common to achieve the equivalent of a test cross of X-linked
genes in females by assessing the readily observed phenotypes of their male progeny. Since males do
not receive X-linked genes from their father, sires of these crosses can be normal or wild-type flies. In fly
genetics, it is conventional to name a gene after the mutant phenotype that enabled its discovery.
Your challenge is to establish gene order and map distances between three X-linked genes in Drosophila.
Each gene is represented by recessive mutant alleles that express rather distinctive phenotypes relative
to their dominant wild-type alternative alleles. Flies expressing fruitless (f) are bisexual, lush (1) have a
heightened responses to ethanol, and ken&barbie (kb) lack external…
If the frequency of the "green" form of red-green color blindness (due to an X-linked locus) is 5 percent among males, what fraction of females would be affected? Assuming H-W equilibrium what fraction of females would be heterozygous?
Chapter 13 Solutions
Biology 2e
Ch. 13 - Figure 13.3 In a test cross for two...Ch. 13 - Figure 13.4 Which of the following statements is...Ch. 13 - Figure 13.6 Which of the following statements...Ch. 13 - X-linked recessive traits in humans (or in...Ch. 13 - The first suggestion that chromosomes may...Ch. 13 - Which recombination frequency corresponds to...Ch. 13 - Which recombination frequency corresponds to...Ch. 13 - Which of the following codes describes position 12...Ch. 13 - In agriculture, polyploid crops (like coffee,...Ch. 13 - Assume a pericentric inversion occurred in one of...
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- Analysis of X-Linked Dominant and Recessive Traits A young boy is color-blind. His one brother and five sisters are not. The boy has three maternal uncles and four maternal aunts. None of his uncles children or grandchildren is color-blind. One of the maternal aunts married a color-blind man, and half of her children, both male and female, are color-blind. The other aunts married men who have normal color vision. All their daughters have normal vision, but half of their sons are color-blind. a. Which of the boys four grandparents transmitted the gene for color blindness? b. Are any of the boys aunts or uncles color-blind? c. Is either of the boys parents color-blind?arrow_forwardIf a Drosophila female that is homozygous for an X-linked recessive mutation is bred with a male that carries the corresponding wild- type allele, the offspring will show the mutant phenotype in all individuals. be uniform wild-type. show a phenotype intermediate to the parents' phenotype. show the mutant phenotype in all males and the wild-type phenotype in all females. have mutant and wild-type males and mutant and wild-type females.arrow_forwardNLFN3, a gene in the X chromosome has been linked to Autism spectrum disorder ASD. Research has shown that the mutation R451C (represented by the allele X+) is recessive and causes ASD. Ear lobes in humans are coded by a single gene which displays simple dominance. E results in free earlobes, and e corresponds to attached earlobes. What is the probability of having a female offspring with ASD symptoms and attached earlobes from X+Y Ee and X+X ee parents? 25% O 100% 0% O 75% O 12.5% O 50%arrow_forward
- Bicoid is a maternal-effect gene in the fruit fly Drosophila that controls anterior/posterior axis formation. Recessive mutations in bicoid can result in fly larvae that have no head, and thus are embryonic lethal. bcd+ is the wild type bicoid allele bcd is the recessive mutant bicoid allele A cross between two heterozygous parents (bcd+/bcd) results in all wild-type F1 offspring. 1. What are the possible genotypes and ratios of each genotype in the F1 offspring of this cross? 1. How can you explain the fact that all the F1 offspring are phenotypically wild-type, using what you know about maternal-effect genes?arrow_forwardIn Drosophila, the autosomal recessive brown eye color mutation displays interactions with the X-linked recessivevermilion mutation. Flies homozygous for brown and hemizygous or homozygous for vermilion have white eyes.Predict the F1 and F2 progeny of crossing these true-breeding parents: brown females and vermilion males.arrow_forwardThe following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyWhat information do you know based on the question and your…arrow_forward
- The following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyAnalyze data. Make a drawing. Make a calculation.arrow_forwardThe following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyWhat topic in genetics does this question address?arrow_forwardThe following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyA. Calculate the map distances separating the three genes.B. Is…arrow_forward
- In fruit flies, the following X-linked traits are found: white eyes are recessive to red eyes, ebony body is recessive to gray body, and short wings is recessive to long wings. A cross was made between wild-type males with red eyes, long wings, and gray bodies and females with white eyes, short wings, and ebony bodies. Female heterozygote resulting from this cross, which had red eyes, long wings, and gray bodies, were then crossed with males with white eyes, short wings, and ebony bodies. The F2 generation data is obtained below: 1299 white eyes, short wings, ebony bodies 1367 red eyes, long wings, gray bodies 99 white eyes, short wings, gray body 89 red eyes, long wings, ebony bodies 49 white eyes, long wings, ebony bodies 49 red eyes, short wings, gray bodies 1 red eyes, short wings, ebony bodies 1 white eyes, long wings, gray bodies A) Calculate the map distance separating the three genes B) Which gene is in the middle?arrow_forwardMiniature wings in Drosophila result from an X-linked allele (w) that is recessive to the allele for long wings (+). In a cross of a long winged male with a long winged female, the following offspring were obtained: 100 long winged males, 106 miniature winged males, and 480 long winged females. Given this result, the female must be a carrier of the miniature wing allele. True Falsearrow_forwardRed-green colorblindness is determined in humans by a single X-linked locus. Colorblind males are XbY, and males with normal vision are XBY. XB is dominant, so XBXB and XBXb females have normal vision, while XbXb females are colorblind. Typically, 8% of males are red-green colorblind. Assuming H-W equilibrium, what percentage of females is typically colorblind?arrow_forward
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