Principles of Physics: A Calculus-Based Text
5th Edition
ISBN: 9781133104261
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 14, Problem 33P
(a)
To determine
The length of open pipe.
(b)
To determine
The length of closed pipe.
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The A string on a violin has a fundamental frequency of 440 Hz . The length of the vibrating portion is 28 cm , and it has a mass of 0.37 g .
Under what tension must the string be placed?Express your answer using two significant figures.
The fundamental frequency of an open organ pipe corresponds to middle C (261.6 Hz on the chromatic musical scale). The third resonance of a closed organ pipe has the same frequency. What is the length of (a) the open pipe and (b) the closed pipe?
a string mass on a violin has a fundamental frequency of 440 hz. The length of the vibrating portion is 32 cm and it has a mass of 0.35 g. Under what tension must the string be placed?
Chapter 14 Solutions
Principles of Physics: A Calculus-Based Text
Ch. 14.1 - Prob. 14.1QQCh. 14.2 - Prob. 14.2QQCh. 14.3 - When a standing wave is set up on a string fixed...Ch. 14.4 - Prob. 14.4QQCh. 14.4 - Prob. 14.5QQCh. 14.5 - You are tuning a guitar by comparing the sound of...Ch. 14 - A flute has a length of 58.0 cm. If the speed of...Ch. 14 - Prob. 2OQCh. 14 - In Figure OQ14.3, a sound wave of wavelength 0.8 m...Ch. 14 - Prob. 4OQ
Ch. 14 - Prob. 5OQCh. 14 - Prob. 6OQCh. 14 - Prob. 7OQCh. 14 - Prob. 8OQCh. 14 - Prob. 9OQCh. 14 - Prob. 10OQCh. 14 - A standing wave having three nodes is set up in a...Ch. 14 - Prob. 1CQCh. 14 - Prob. 2CQCh. 14 - Prob. 3CQCh. 14 - Prob. 4CQCh. 14 - What limits the amplitude of motion of a real...Ch. 14 - Prob. 6CQCh. 14 - Prob. 7CQCh. 14 - Prob. 8CQCh. 14 - Prob. 1PCh. 14 - Prob. 2PCh. 14 - Prob. 3PCh. 14 - Prob. 4PCh. 14 - Prob. 5PCh. 14 - Prob. 6PCh. 14 - Prob. 7PCh. 14 - Prob. 8PCh. 14 - Prob. 9PCh. 14 - Prob. 10PCh. 14 - Prob. 11PCh. 14 - Prob. 12PCh. 14 - Prob. 13PCh. 14 - Prob. 14PCh. 14 - Prob. 15PCh. 14 - Prob. 16PCh. 14 - Prob. 17PCh. 14 - Prob. 18PCh. 14 - Prob. 19PCh. 14 - Prob. 20PCh. 14 - A string with a mass m = 8.00 g and a length L =...Ch. 14 - Prob. 22PCh. 14 - Prob. 23PCh. 14 - Prob. 24PCh. 14 - Prob. 25PCh. 14 - Review. A sphere of mass M is supported by a...Ch. 14 - Prob. 27PCh. 14 - Prob. 28PCh. 14 - Prob. 29PCh. 14 - Prob. 30PCh. 14 - Prob. 31PCh. 14 - The overall length of a piccolo is 32.0 cm. The...Ch. 14 - Prob. 33PCh. 14 - Prob. 34PCh. 14 - Two adjacent natural frequencies of an organ pipe...Ch. 14 - Do not stick anything into your ear! Estimate the...Ch. 14 - Prob. 37PCh. 14 - As shown in Figure P14.37, water is pumped into a...Ch. 14 - Prob. 39PCh. 14 - Prob. 40PCh. 14 - Prob. 41PCh. 14 - Why is the following situation impossible? A...Ch. 14 - 23. An air column in a glass tube is open at one...Ch. 14 - Prob. 44PCh. 14 - Prob. 45PCh. 14 - Prob. 46PCh. 14 - Prob. 47PCh. 14 - Prob. 48PCh. 14 - Some studies suggest that the upper frequency...Ch. 14 - Prob. 50PCh. 14 - An earthquake can produce a seiche in a lake in...Ch. 14 - Prob. 52PCh. 14 - Prob. 53PCh. 14 - Prob. 54PCh. 14 - Prob. 55PCh. 14 - A nylon string has mass 5.50 g and length L = 86.0...Ch. 14 - Prob. 57PCh. 14 - Prob. 58PCh. 14 - Prob. 59PCh. 14 - Review. For the arrangement shown in Figure...Ch. 14 - Prob. 61PCh. 14 - Prob. 62PCh. 14 - Prob. 63PCh. 14 - Prob. 64PCh. 14 - Prob. 65PCh. 14 - Prob. 66PCh. 14 - Prob. 67PCh. 14 - Review. Consider the apparatus shown in Figure...Ch. 14 - Prob. 69P
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- A guitar player tunes the fundamental frequency of a guitar string to 450 Hz. (a) What will be the fundamental frequency if she then increases the tension in the string by 29%? (b) What will it be if, instead, she decreases the length along which the string oscillates by sliding her finger from the tuning key one-third of the way down the string toward the bridge at the lower end? (a) Number i 80 (b) Number i 77 Units Units Hz Hzarrow_forwardAn organ pipe is open at both ends. It is producing sound at its n = 3 harmonic, the frequency of which is 164 Hz. Take the speed of sound to be 345 m/s. What is the length of the pipe?arrow_forwardThe D-string on a properly tuned guitar produces a tone with a fundamental frequency of 146.8Hz. The length of the oscillating portion of a D-string on a certain guitar is 0.616m. This same length of string is weighed and found have a mass of 1.72×10−3kg. Part (a) At what tension, in newtons, is the D-string properly tuned? Part (b) What is the wavelength, in meters, of the standing wave in the D-string when it is oscillating at its third harmonic, which is also called its second overtone? Part (c) Determine the frequency, in hertz, of the third harmonic of the tone produced by the properly tuned D-string. Part (d) The guitarist shortens the oscillating length of the properly tuned D-string by 0.138m by pressing on the string with a finger. What is the new fundamental frequency, in hertz, of the shortened string?arrow_forward
- A guitar player tunes the fundamental frequency of a guitar string to 440 Hz. (a) What will be the fundamental frequency if she then increases the tension in the string by 16%? (b) What will it be if, instead, she decreases the length along which the string oscillates by sliding her finger from the tuning key one-third of the way down the string toward the bridge at the lower end? (a) Number i (b) Number i Units Unitsarrow_forwardDavie flexed his lowest bass guitar with strings of length 1.00m between fixed points. One string, with linear mass density 60.0 g/m, is tuned to a 25.0Hz fundamental frequency. Calculate the tension of the string. Choices: 105 N 150 N 1.50 N 510 Narrow_forwardIn pipe A, the ratio of a particular harmonic frequency to the next lower harmonic frequency is 1.2. In pipe B, the ratio of a particular harmonic frequency to the next lower harmonic frequency is 1.4. How many open ends are in (a) pipe A and (b) pipe B?arrow_forward
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- The A string on a violin has a fundamental frequency of 430Hz. The length of the vibrating portion of the string is 35cm and has a mass of 0.35 g. Under what tension must the string be placed to obtain the desired frequency?arrow_forwardAn aluminum rod, 1.00 m long, is held lightly in the middle. One end is struck head-on with a rubber mallet so that a longitudinal pulse—a sound wave—travels down the rod. The fundamental frequency of the longitudinal vibration is 1.10 kHz. Calculate the speed of sound in aluminum from the information given in the problem.arrow_forwardA violin string of length L=31.8 cm and linear mass density u=0.64gm/is tuned to play an A4 note at 440.0 Hz. This means that the string is in its mode of oscillation fundamental, that is, it will be on that note without placing any fingers on it. From this information, D. When playing the violin, different notes can be produced depending on the position of the fingers of one hand on the string. The usual technique presses the string hard against the fretboard, reducing the length of the string that can vibrate. If we consider this string initially tuned for an A4, and a finger is placed a third of the way down from the headstock: What would be the new fundamental frequency, that is, the frequency of the new note that is being produced assuming it has the same tension as in part A? ii. i. What would be the new frequency of the note, if instead of using the technique described above for violin playing, the technique called artificial harmonic is used, where the string is only partially…arrow_forward
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