Introduction to Algorithms
3rd Edition
ISBN: 9780262033848
Author: Thomas H. Cormen, Ronald L. Rivest, Charles E. Leiserson, Clifford Stein
Publisher: MIT Press
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Chapter 15.3, Problem 2E
Program Plan Intro
To describe the memorization fails to speed up a good divide and conquer
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Solve the following recursive function for count_partitions(6 , 4). Also draw theRecursion tree.def count_partitions(n , m)if n==0return 1elif n < 0return 0return count_partitions(n-m , m) + count_partitions(n , m-1)
Given a singly linked list, print reverse of it using a recursive function
printLinkedList( node *first ) where first is the pointer pointing to the first data
node. For example, if the given linked list is 1->2->3->4, then output should be:
4 3 2 1
(note the whitespace in between each data value)
plz do not copy from chegg
Problem 1. Implement a sorted singly linked list and support the following operations:
bool SortedIsEmpty(): return true if the list is empty;
int SortedGetLength(): return the length of the list;
bool SortedFind(int k, int& x): return the value of the kth element;
int SortedSearch(int key): return the position of the element which is same as key (note: use the most efficient method);
void SortedInsert(int x): insert x to the right position in the sorted linked list;
void SortedDelete(int k, int& x, bool& success): delete the kth element.
Part (1) Implement the aboved singly linked list allowing the duplicate element.
Part (2) Implement the above singly linked list without allowing the duplicate element.
Test your program for both parts with the following operations:
Insert 5
Insert 7
Insert 9
Insert 11
Insert 5
Print out the list
Insert 7
Print out the list
Find the 3rd element
Search 7
Print out the length of the list
Delete 7
Print out the…
Chapter 15 Solutions
Introduction to Algorithms
Ch. 15.1 - Prob. 1ECh. 15.1 - Prob. 2ECh. 15.1 - Prob. 3ECh. 15.1 - Prob. 4ECh. 15.1 - Prob. 5ECh. 15.2 - Prob. 1ECh. 15.2 - Prob. 2ECh. 15.2 - Prob. 3ECh. 15.2 - Prob. 4ECh. 15.2 - Prob. 5E
Ch. 15.2 - Prob. 6ECh. 15.3 - Prob. 1ECh. 15.3 - Prob. 2ECh. 15.3 - Prob. 3ECh. 15.3 - Prob. 4ECh. 15.3 - Prob. 5ECh. 15.3 - Prob. 6ECh. 15.4 - Prob. 1ECh. 15.4 - Prob. 2ECh. 15.4 - Prob. 3ECh. 15.4 - Prob. 4ECh. 15.4 - Prob. 5ECh. 15.4 - Prob. 6ECh. 15.5 - Prob. 1ECh. 15.5 - Prob. 2ECh. 15.5 - Prob. 3ECh. 15.5 - Prob. 4ECh. 15 - Prob. 1PCh. 15 - Prob. 2PCh. 15 - Prob. 3PCh. 15 - Prob. 4PCh. 15 - Prob. 5PCh. 15 - Prob. 6PCh. 15 - Prob. 7PCh. 15 - Prob. 8PCh. 15 - Prob. 9PCh. 15 - Prob. 10PCh. 15 - Prob. 11PCh. 15 - Prob. 12P
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